/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Researchers measured the percent... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Researchers measured the percentage of body fat and the preferred amount of salt (percentage weight/volume) for several children. Here are data for seven children:16 ln SALT \begin{tabular}{|l|l|l|l|l|l|l|l|l|l|l|} \hline Preferred amount of satt \(x\) & \(0.2\) & \(0.3\) & \(0.4\) & \(0.5\) & \(0.6\) & \(0.8\) & \(1.1\) \\ \hline Percentage of body fat \(y\) & 20 & 30 & 22 & 30 & 39 & 23 & 30 & \\ \hline \end{tabular} Using your calculator or software, what is the equation of the least-squares regression line for predicting percentage of body fat based on the preferred amount of salt? a. \(\hat{y}=24.2+6.0 x\) b. \(\hat{y}=0.15+0.01 x\) c. \(\hat{y}=6.0+24.2 x\)

Short Answer

Expert verified
Option a: \(\hat{y}=24.2+6.0x\) is the correct equation.

Step by step solution

01

Calculate Means

First, calculate the mean of the preferred amount of salt (\(x\)) and the percentage of body fat (\(y\)). The mean of \(x\) is \( \frac{0.2+0.3+0.4+0.5+0.6+0.8+1.1}{7} \) and for \(y\) is \( \frac{20+30+22+30+39+23+30}{7} \).
02

Compute the Slope (b)

Use the formula for the slope \(b\) of the least-squares line: \(b = \frac{\sum (x_i - \bar{x})(y_i - \bar{y})}{\sum (x_i - \bar{x})^2}\), where \(x_i\) and \(y_i\) are individual data points.
03

Compute the Y-intercept (a)

Use the formula for the y-intercept \(a\): \(a = \bar{y} - b\bar{x}\), where \(\bar{x}\) and \(\bar{y}\) are the means calculated in Step 1.
04

Formulate the Regression Equation

Combine the slope \(b\) and y-intercept \(a\) to formulate the regression equation \(\hat{y} = a + bx\).
05

Match to Given Options

Compare the computed regression equation with the provided options a, b, and c, to identify the correct equation based on calculations.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Regression Line Equation
In many statistical analyses, especially those involving data with two variables, understanding the relationship between variables can be crucial. A Regression Line Equation is a mathematical tool used to express this relationship. It aims to depict the trend within the data, providing a way to predict future or unseen values. This is particularly useful in studying how one variable affects another.

In the context of the presented exercise, the regression line is used to predict the percentage of body fat based on the preferred amount of salt. In general, the equation of a regression line is written as:
  • \[\hat{y} = a + bx\]
- where \(\hat{y}\) represents the predicted value of the dependent variable (here, body fat percentage).- \(b\) is the slope of the line, indicating how much \(y\) changes for every unit change in \(x\).- \(a\) is the y-intercept, which is the value of \(\hat{y}\) when \(x\) is zero.

This equation is derived from the data through statistical computation. It's designed to minimize the sum of the squares of the vertical distances of the points from the line, meaning it's a "best fit" line for the data provided.
Body Fat Percentage
Body fat percentage is a measurement of the fat relative to the body mass. It plays a critical role in health and fitness assessments. Analyzing body fat percentage data involves understanding how it can be influenced by various factors, such as diet, age, or physical activity.

In this exercise, researchers have sought to understand if there is a correlation between the amount of salt preferred by children and their body fat percentage. This kind of analysis can contribute to nutrition science and help guide dietary recommendations. The key goal is to see if increasing salt intake is associated with higher, lower, or unchanged body fat percentages among children.

By studying regression analysis, researchers can determine if there is any statistically significant relationship that holds true across the sampled children, aiding in deeper insights into child nutrition and health outcomes.
Data Analysis
Data Analysis is a foundational process in which raw data is transformed into valuable insights or conclusions. It encompasses various techniques that allow researchers to describe, visualize, and interpret data efficiently.

The exercise involves steps like:
  • Calculating means, which provide a central value for data sets.
  • Determining the regression line that helps to predict outcomes based on input data.
These steps entail understanding the spread and characteristics of data points such as the preferred amount of salt and corresponding body fat percentages.

In analyzing this data, researchers can identify trends and test hypotheses. For instance, checking whether children with higher salt preference tend to have a specific pattern in body fat percentage helps understand broader health trends.

Effective data analysis depends on careful and accurate calculations, often facilitated by statistical software, ensuring that results are reliable and interpretable.
Statistical Computation
The exercise makes use of Statistical Computation, which refers to the use of algorithms and mathematical calculations to solve statistical problems. Through these computations, patterns and relationships in data can be identified.

For a least-squares regression line, this involves:
  • Calculating the slope \(b\) using the formula:
    \[b = \frac{\sum (x_i - \bar{x})(y_i - \bar{y})}{\sum (x_i - \bar{x})^2}\]
    where \(x_i\) and \(y_i\) are individual data points, and \(\bar{x}\) and \(\bar{y}\) are their respective means.
  • Determining the y-intercept \(a\) using:
    \[a = \bar{y} - b\bar{x}\]
These calculations require precision as even minor errors can skew final results.

Once the computations are completed accurately, the regression equation formed helps to analyze how well the data can predict outcomes. Statistical computation provides the framework to transform raw data into meaningful answers in research questions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Regression to the Mean. We expect that students who do well on the midterm exam in a course will usually also do well on the final exam. Gary Smith of Pomona College looked at the exam scores of all 346 students who took his statistics class over a 10-year period. 27 The least-squares line for predicting final exam score from midterm-exam score was \(\hat{y}=46.6+0.41 x\). (Both exams have a 100 -point scale.) Octavio scores 10 points above the class mean on the midterm. How many points above the class mean do you predict that he will score on the final? (Hint: Use the fact that the least-squares line passes through the point \(x, y\) and the fact that Octavio's midterm score is \(x+10\).) This is another example of regression to the mean: st udents who do well on the midterm will, in general, do less well, but still above average, on the final.

Workers' Incomes. Here is another example of the group effect cautioned about in the previous exercise. Explain how, as a nation's population grows older, median income can go down for workers in each age group yet still go up for all workers.

What's the Line? An online article suggested that for each additional person who took up regular running for exercise, the number of cigarettes smoked daily would decrease by \(0.178 . \underline{2}\) If we assume that 48 million cigarettes would be smoked per day if nobody ran, what is the equation of the regression line for predicting number of cigarettes smoked per day from the number of people who regularly run for exercise?

Learning Online. Many colleges offer online versions of courses that are also taught in the classroom. It often happens that the students who enroll in the online version do better than the classroom st udents on the course exams. This does not show that online instruction is more effective than classroom teaching because the people who sign up for online courses are often quite different from the classroom students. Suggest some differences between online and classroom students that might explain why online students do better.

The Price of Diamond Rings. Online advertisements contained pictures of diamond rings and listed their prices, diamond weights (in carats), and gold purity. Based on data for only the 18-carat gold ladies' rings in the advertisements, the least-squares regression line for predicting price (in dollars) from the weight of the diamond (in carats) is \(\frac{18}{18}\) $$ \text { price }=-6047.75+11975.14 \text { carats } $$ a. What does the slope of this line say about the relationship between price and number of carats? b. What is the predicted price when number of carats \(=0\) ? How would you interpret this price?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.