/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 The inside diameter of automobil... [FREE SOLUTION] | 91Ó°ÊÓ

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The inside diameter of automobile engine piston rings is important to the proper functioning of the engine. The manufacturer checks the control of the piston ring forging process by measuring a sample of five consecutive items during each hour's production. The target diameter for a ring is \(\mu=74.000 \mathrm{~mm}\). The process has been operating in control, with the center close to the target and \(\sigma=0.015 \mathrm{~mm}\). a. What center line and control limits should be drawn on the \(s\) chart? On the \(x\) chart? b. A different manufacturer creates the pistons in which the rings will be fitted. This manufacturer has a target value of \(73.945 \mathrm{~mm}\) for the piston diameter. The manufacturer checks control of the piston diameter four times each hour. Recently, the process has been running high with \(\mu=74.000 \mathrm{~mm}\) and \(\sigma=0.005 \mathrm{~mm}\). Do you see any issues that might arise for the manufacturer of the engine when the two parts from the different manufacturers are assembled?

Short Answer

Expert verified
Currently, the parts might not fit well due to the same mean size, risking tight assembly issues.

Step by step solution

01

Determine Control Limits for the s Chart

The control limits for an \(s\) chart (which monitors variability) are given by:\[ UCL_s = B_4 \times \bar{s}, \quad LCL_s = B_3 \times \bar{s} \] with the center line:\[ CL_s = \bar{s}\] Given the small sample, the factors \(B_3\) and \(B_4\) depend on the sample size (5). For a sample size of 5, we typically have \(B_3 = 0 (no LCL)\) and \(B_4 = 2.114\). With a process variability of \(\sigma=0.015\), the standard deviation of such samples "s" is often assumed to be \(\sigma = \bar{s}\). The centerline \(CL_s = 0.015\) is assumed.Thus, the control limits are:\( UCL_s = 2.114 \times 0.015 = 0.03171\). Since the \(LCL_s\) is typically zero, we have:\[ CL_s = 0.015\] \[ UCL_s = 0.03171, \quad LCL_s = 0\]
02

Calculate Control Limits for the x-bar Chart

For an \(x\)-bar chart (which monitors the mean), we use:\[ UCL_{\bar{x}} = \mu + A_2 \times \bar{s}, \quad LCL_{\bar{x}} = \mu - A_2 \times \bar{s} \] with the center line:\[ CL_{\bar{x}} = \mu\]The chart factor \(A_2\) for a sample size of 5 is 0.577. Therefore:\[ UCL_{\bar{x}} = 74.000 + 0.577 \times 0.015 = 74.008655\] \[ LCL_{\bar{x}} = 74.000 - 0.577 \times 0.015 = 73.991345\] Thus:\[ CL_{\bar{x}} = 74.000\] \[ UCL_{\bar{x}} = 74.008655, \quad LCL_{\bar{x}} = 73.991345\]
03

Analyze Compatibility of Parts from Different Manufacturers

The second manufacturer's process, which produces pistons, has a target of \(73.945\ \mathrm{mm}\), but it is running closer to \(74.000\ \mathrm{mm}\) due to a high shift, with a standard deviation of \(0.005\ \mathrm{mm}\). Pistons produced with a mean of \(74.000\ \mathrm{mm}\) fit tightly on average with the rings also averaging \(74.000\ \mathrm{mm}\), risking a lack of clearance needed for fitting. Ideally, pistons should be slightly smaller than the rings to ensure easy assembly. This mismatch could lead to issues such as increased friction or damage when assembling.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Process Control
Statistical Process Control (SPC) is a method used to monitor and control a process. Its aim is to ensure that the process operates at its fullest potential. By using statistical tools, SPC helps detect variations in production processes which could lead to defects. This method is commonly used in manufacturing industries to maintain high quality products.

The core idea behind SPC is to use data-driven approaches to keep a process under control. It involves the use of control charts and the regular collection of data to verify that the process stays within predetermined limits. This approach reduces variability and increases product uniformity, which is beneficial in maintaining customer satisfaction.
Control Limits
Control Limits play a crucial role in quality control charts. They serve as the benchmark for identifying whether a process is in control or out of control. Specifically, control limits are horizontal lines drawn on a control chart, often set at 3 standard deviations away from the mean. They are used to determine the acceptable range of process variability.

There are two types of control limits in a typical control chart:
  • Upper Control Limit (UCL): This is the highest value limit for the process. If the process metric goes above this line, it's a signal that something unusual might be happening and requires investigation.
  • Lower Control Limit (LCL): This is the lowest value limit for the process. If the process metric goes below this line, similar actions need to be taken.
The center line represents the average of the process and serves as a project baseline. Identifying whether a process metric exceeds these limits helps in addressing potential problems before they affect product quality.
Process Variability
Process Variability refers to the natural or inherent changes that occur in any production process. It can arise from several factors including equipment wear and tear, environmental changes, or even human error. Understanding and controlling variability is crucial because too much variation can lead to inconsistent products, which customers may view negatively.

Controlling variability involves measuring and monitoring variations within the process using control charts. These help in identifying trends or shifts that could indicate a process going out of control. Consistent monitoring leads to more stable and efficient production lines as any deviations can be addressed timely, maintaining product quality.
Assembly Compatibility
Assembly Compatibility is a key consideration in manufacturing, especially when parts are produced by different manufacturers. It refers to the ability of different components to fit together as intended. Incorrect fits can lead to malfunctions, increased wear, or even damage.

In the given case, we examine how piston rings and pistons manufactured by different companies might cause issues due to size discrepancies. With the piston ring at a target of 74.000 mm and the piston being produced closer to 74.000 mm instead of its intended 73.945 mm, there may be too tight a fit. This mismatch requires close examination and possibly process adjustment to prevent increased friction or assembly difficulties. Ensuring that parts are compatible is critical in maintaining function and avoiding costly rework or product failures.

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Most popular questions from this chapter

If the mesh tension of individual monit ors follows a Normal distribution, we can describe capability by giving the percentage of monitors that meet specifications. The old specifications for mesh tension are 100 to \(400 \mathrm{mV}\). The new specifications are 150 to \(350 \mathrm{mV}\). Because the process is in control, we can estimate that tension has mean \(275 \mathrm{mV}\) and standard deviation \(38.4 \mathrm{mV}\). a. What percentage of monitors meet the old specifications? b. What percentage meet the new specifications?

What type of control chart or charts would you use as part of efforts to improve each of the following performance measures in a college admissions office? Explain your choices. a. Time to acknowledge receipt of an application b. Percentage of admission offers accepted c. Student participation in a healthy meal plan

A large chain of coffee shops records a number of performance measures. Among them is the time required to complete an order for a cappuccino, measured from the time the order is placed. Suggest some plausible examples of each of the following. a. Reasons for common cause variation in response time b. s-type special causes c. \(x\)-type special causes

Is each of the following examples of a special cause most likely to result first in (i) a sudden change in level on the \(s\) or \(R\) chart, (ii) a sudden change in level on the \(x\) chart, or (iii) a gradual drift up or down on the \(x\) chart? In each case, briefly explain your reasoning. a. An airline pilots' union puts pressure on management during labor negotiations by asking its members to "work to rule" in doing the detailed checks required before a plane can leave the gate. b. Measurements of part dimensions that were formerly made by hand are now made by a very accurate laser system. (The process producing the parts does not change; measurement methods can also affect control charts.) c. Inadequate air conditioning on a hot day allows the temperature to rise during the afternoon in an office that prepares a company's invoices.

The computer makers who buy monitors require that the monitor manufacturer practice statistical process control and submit control charts for verification. This allows the computer makers to eliminate inspection of monitors as they arrive, which is a considerable cost saving. Explain carefully why incoming inspection can safely be eliminated.

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