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Here are the probabilities that a randomly selected high school student used these different tobacco products:- \(-\) $$ \begin{array}{lll} P(A)=0.08 & P(B)=0.21 & P(C)=0.19 \\ P(A \text { and } B)=0.06 & P(A \text { and } C)=0.03 & P(B \text { and } C)=0.06 \\ P(A \text { and } B \text { and } C)=0.02 & & \end{array} $$ Make a Venn diagram of the events A, B, and C. As in Eigure I3.4 (page 297), mark the probabilities of every intersection involving these events. Use this diagram for Excercises 13.4.5 through 13.4Z Do You Use Tobacco Products? What is the probability that a randomly selected high school st udent did not use any tobacco product?

Short Answer

Expert verified
Probability of no tobacco use is 0.73.

Step by step solution

01

Identify Given Probabilities

We are given the probabilities of three events and their combinations:\[ P(A) = 0.08, \ P(B) = 0.21, \ P(C) = 0.19 \]\[ P(A \cap B) = 0.06, \ P(A \cap C) = 0.03, \ P(B \cap C) = 0.06 \]\[ P(A \cap B \cap C) = 0.02 \]These correspond to the use of different tobacco products by high school students.
02

Determine Individual and Combined Probabilities for Venn Diagram

To create a Venn diagram, calculate the probabilities specific to the areas:- Exclusive use of A (only A): \( P(A) - P(A \cap B) - P(A \cap C) + P(A \cap B \cap C) = 0.02 \)- Exclusive use of B (only B): \( P(B) - P(A \cap B) - P(B \cap C) + P(A \cap B \cap C) = 0.11 \)- Exclusive use of C (only C): \( P(C) - P(A \cap C) - P(B \cap C) + P(A \cap B \cap C) = 0.08 \)- Overlap of A and B, not C: \( P(A \cap B) - P(A \cap B \cap C) = 0.04 \)- Overlap of A and C, not B: \( P(A \cap C) - P(A \cap B \cap C) = 0.01 \)- Overlap of B and C, not A: \( P(B \cap C) - P(A \cap B \cap C) = 0.04 \)- Overlap of A, B, and C: \( P(A \cap B \cap C) = 0.02 \)
03

Calculate Probability of No Tobacco Use

To find the probability that a student did not use any tobacco product, calculate:\[ P( ext{No Tobacco Use}) = 1 - (P(A) + P(B) + P(C) - P(A \cap B) - P(A \cap C) - P(B \cap C) + P(A \cap B \cap C)) \]The union of all events is calculated as:\( P(A) + P(B) + P(C) \)Returns a sum larger than total probability due to overlaps, so subtract overlaps:\( P(A \cap B) + P(A \cap C) + P(B \cap C) \)Finally, add back the triple intersection:\( + P(A \cap B \cap C) \)\[ = 1 - 0.27 \]This results in a probability of no use being \( 0.73 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Probability is a measure of how likely it is for a certain event to happen. In the context of the given exercise, we look at different probabilities related to the use of tobacco products by high school students. Each tobacco product use can be seen as an event, and we assign a probability to each event based on observed or expected usage rates.
The probability of a single event, like a student using tobacco product A, is denoted as \( P(A) \). When dealing with probabilities, values always range between 0 and 1, where 0 indicates impossibility and 1 signifies certainty. For example, if \( P(A) = 0.08 \), it means there is an 8% likelihood a student picked at random uses product A.
Calculating probabilities requires careful consideration of overlapping events, especially when events intersect, which is common when working with Venn diagrams and set theory.
Set Theory
Set theory is the study of collections of objects, which in our case are events. We use set theory concepts to organize and calculate probabilities involving multiple events. Venn diagrams visually represent these sets, making it easier to see how they overlap or relate. In the exercise, the sets are events A, B, and C, corresponding to different tobacco products.
The Venn diagram allows us to visualize these probabilities, showcasing areas of exclusive use, mutual overlap, and the intersections of all three events. By identifying areas such as \( A \cap B \cap C \), we understand what specific portion of students uses all three product types together.
Using these visual tools and set theory language, we systematically break down complex probabilistic situations, helping to clarify how individual and combined probabilities interact.
Intersection
The concept of intersection refers to the probability that two or more events occur at the same time. In set theory, the intersection of two sets \( A \) and \( B \) is denoted as \( A \cap B \). It represents the overlap where both events happen simultaneously. For example, \( P(A \cap B) \) is the probability of a student using both tobacco products A and B.
To find the probability of intersections, we have to consider the given data about the probabilities of various combinations of events. When calculating intersections of three sets as in \( A \cap B \cap C \), it denotes the event that all three occur together. In the exercise, \( P(A \cap B \cap C) = 0.02 \), meaning there's a 2% chance a student uses all three tobacco products.
Understanding intersections helps in determining shared probabilities among events, which is crucial for both calculating exclusive probabilities and understanding union probabilities within the Venn diagram.
Complementary Events
Complementary events encompass all possible outcomes of an event set, ensuring the collective probability equals 1. The complement of an event is all outcomes not part of that event, often aiding in finding the probability of an event not happening.
In the exercise, calculating the probability of no tobacco use involves finding the complement of the union of events A, B, and C. By using the formula \( P( ext{No Tobacco Use}) = 1 - P(A ext{ or } B ext{ or } C) \), we effectively identify the likelihood that a student does not use any tobacco products. This yields \( P( ext{No Tobacco Use}) = 0.73 \).
Complementary events provide a method to tackle complex probability scenarios by focusing on what does not happen, simplifying calculations through subtraction from the total certainty of 1.

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Most popular questions from this chapter

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