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91Ó°ÊÓ

Of people who died in the United States in recent years, \(78 \%\) were non- Hispanic White, \(12 \%\) were non-Hispanic Black, \(7 \%\) were Hispanic, and \(3 \%\) were Asian. (This ignores a small number of deaths among other races.) Diabetes caused \(2.5 \%\) of deaths among non-Hispanic Whites, 4.4\% among non- Hispanic Blacks, 4.7\% among Hispanics, and 4.2\% among Asians. The probability that a randomly chosen death is a non-Hispanic White person and died of diabetes is about a. \(0.81 .\) b. \(0.025\). c. \(0.020\).

Short Answer

Expert verified
The probability is c. 0.020.

Step by step solution

01

Understanding the Problem

We need to find the probability that a randomly chosen death was a non-Hispanic White person who died of diabetes.
02

Identify Components of Probability

The probability that a death was among non-Hispanic Whites is given by \(0.78\). The probability that a death among non-Hispanic Whites was due to diabetes is given as \(0.025\).
03

Calculate the Joint Probability

To find the probability that a death was a non-Hispanic White and died of diabetes, we multiply the probability of being a non-Hispanic White \(0.78\) by the probability of dying from diabetes within this group \(0.025\): \[ P(\text{Non-Hispanic White and Diabetes}) = 0.78 \times 0.025 \] This equals \(0.0195\).
04

Select the Closest Option

Based on our calculation of \(0.0195\), the closest choice that matches this probability is option c, \(0.020\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
In the realm of probability, understanding the concept of conditional probability is crucial. It helps us determine the likelihood of an event occurring given that another event has already occurred.
For example, in the exercise, the probability of a death being due to diabetes is influenced by the demographic group in question. It's not just the overall probability of diabetes as a cause of death, but rather the probability within specific racial or ethnic groups.
Mathematically, conditional probability is calculated by: \[ P(A|B) = \frac{P(A \cap B)}{P(B)} \] where \( P(A|B) \) is the probability of event A occurring given that B is true. In simpler terms, it defines how one event affects the probability of another.
The exercise showcases this concept by providing different probabilities of diabetes-related deaths across demographics, highlighting how probabilities change when conditioned on race.
Probability Calculations
Probability calculations involve various techniques and formulas to find the likelihood of events. In the given exercise, we come across an important calculation involving something known as 'joint probability'.
Joint probability is the probability of two events happening together. To compute it, you multiply the probability of one event by the conditional probability of the second event occurring given that the first event has happened.
Here, the probability is computed for a randomly selected individual being both a non-Hispanic White and dying of diabetes. The formula used is: \[ P(\text{Non-Hispanic White and Diabetes}) = P(\text{Non-Hispanic White}) \times P(\text{Diabetes within Non-Hispanic Whites}) \] Thus, \[ 0.78 \times 0.025 = 0.0195 \] This calculation helps us understand how different factors are multiplied to find the joint probability, allowing us to understand the likelihood of interconnected events happening simultaneously.
Demographics in Statistics
Demographics play a key role in statistics, especially when conducting probability analyses involving population characteristics. They are crucial for understanding how a particular segment of the population behaves or is affected by certain factors.
In the exercise, we see demographics being used to analyze death causes based on racial and ethnic lines. Understanding demographics allows for targeted public health interventions and policy decisions.
Some key points about demographics in statistics include:
  • Provide valuable insights into population segments.
  • Help in identifying trends and disparities.
  • Facilitate targeted research and responses to address population-specific issues.

This segment of probability exercises shows the importance of considering demographic data when assessing probabilities and trends, thus ensuring that results are not only accurate but relevant to all segments of society.

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Most popular questions from this chapter

Older College Students. Government data show that \(4 \%\) of adults are full- time college students and that \(37 \%\) of adults are aged 55 or older. Nonetheless, we can't conclude that because \((0.04)(0.37)=0.015\), about \(1.5 \%\) of adults are college students 55 or older. Why not?

The Probability of a Flush. A poker player holds a flush when all five cards in the hand belong to the same suit (clubs, diamonds, hearts, or spades). We will find the probability of a flush when five cards are drawn in succession from the top of the deck. Remember that a deck contains 52 cards, 13 of each suit, and that when the deck is well shuffled, each card drawn is equally likely to be any of those that remain in the deck. a. Concentrate on spades. What is the probability that the first card drawn is a spade? What is the conditional probability that the second card drawn is a spade, given that the first is a spade? (Hint: How many cards remain? How many of these are spades?) b. Continue to count the remaining cards to find the conditional probabilities of a spade for the third, the fourth, and the fifth card drawn, given in each case that all previous cards are spades. c. The probability of drawing five spades in succession from the top of the deck is the product of the five probabilities you have found. Why? What is this probability? d. The probability of drawing five hearts or five diamonds or five clubs is the same as the probability of drawing five spades. What is the probability that the five cards drawn all belong to the same suit?

Common Names. The U.S. Census Bureau says that the 10 most common names in the United States are (in order) Smith, Johnson, Williams, Brown, Jones, Miller, Davis, Garcia, Rodriguez, and Wilson. These names account for \(9.6 \%\) of all U.S. residents. Out of curiosity, you look at the authors of the textbooks for your current courses. There are 9 authors in all. Would you be surprised if none of the names of these authors were among the 10 most common? (Assume that authors' names are independent and follow the same probability distribution as the names of all residents.)

Peanut Allergies A mong Children. About \(2 \%\) of children in the United States are allergic to peanuts. \(\underline{23}\) Choose three children at random and let the random variable \(X\) be the number in this sample who are allergic to peanuts. The possible values \(X\) can take are \(0,1,2\), and 3. Make a three-stage tree diagram of the outcomes (allergic or not allergic) for the three individuals and use it to find the probability distribution of \(X\).

YouTube Channels. During the first week in 2019, the Pew Research Center tracked the types of English language YouTube videos posted. Let \(A\) be the event that the video posted involved games of some sort, including sports. Let \(B\) be the event that the video posted involved hobbies and skills, including sports. Pew Research Center finds that \(P(A)=0.30\), \(P(B)=0.13\), and \(P(A\) or \(B)=0.34 .^{2}\) a. Make a Venn diagram similar to Eigure 13,4 showing the events \(\\{A\) and \(B\\},\\{A\) and not \(B\\},\\{B\) and \(\operatorname{not} A\\}\), and neither \(A\) nor \(B\\}\). b. Describe each of these events in words. c. Find the probabilities of all four events and add the probabilities to your Venn diagram. The four probabilities you have found should add to 1 .

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