/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 Unusual Dice. Nonstandard dice c... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Unusual Dice. Nonstandard dice can produce interesting distributions of outcomes. You have two balanced, six-sided dice. One is a standard die, with faces having \(1,2,3,4,5\), and 6 spots. The other die has three faces with 0 spots and three faces with 6 spots. Find the probability distribution for the total number of spots \(Y\) on the up-faces when you roll these two dice. Hint: Start with a picture like Figure \(12.2\) (page 276 ) for the possible up-faces. Label the three 0 faces on the second die \(0 \mathrm{a}, 0 \mathrm{~b}, 0 \mathrm{c}\) in your picture and similarly distinguish the three 6 faces.)

Short Answer

Expert verified
The probability distribution is calculated for sums ranging from 1 to 12, based on 36 possible outcome combinations.

Step by step solution

01

Define Possible Outcomes for Each Die

The first die is a standard six-sided die with outcomes \(1, 2, 3, 4, 5,\) and \(6\). The second die has three faces with 0 and three faces with 6; let's label these faces as \(0_a, 0_b, 0_c, 6_a, 6_b,\) and \(6_c\).
02

Identify the Total Outcomes

Since each die is independent, the total number of outcomes when rolling both dice is the product of their individual outcomes. The standard die has 6 outcomes, and the nonstandard die also has 6 outcomes, resulting in \(6 \times 6 = 36\) total outcomes.
03

Calculate Possible Sums

For each roll combination, calculate the sum \(Y\) (total number of spots). If the standard die shows \(x\) and the nonstandard die shows \(y\), then the sum \(Y = x + y\).
04

Generate the Distribution Table

List all possible sums of \(Y\): \(1+0, 1+6, 2+0, 2+6, \ldots, 6+6\). For each sum, count how many outcomes result in that sum. This will help in determining the probability distribution.
05

Calculate Probabilities for Each Sum

Calculate the number of favorable outcomes for each sum \(Y\) and divide by the total number of outcomes (36). Example: for \(Y=1\), only the combination (1,0) leads to this, thus the probability is \(\frac{1}{36}\). Continue for sums varying from \(1\) to \(12\).
06

Finalize the Probability Distribution

The probability distribution for \(Y\) is a table which lists each sum and its corresponding probability. Complete this for all sums from \(1\) to \(12\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nonstandard Dice
When it comes to dice, most people think of the usual six-sided die displaying numbers from 1 to 6. But in probability exercises like the one we're exploring, a concept called 'Nonstandard Dice' comes into play. Imagine two dice: one is standard with faces numbered 1 through 6, and the other is nonstandard with three faces showing 0 and three faces showing 6.
This unusual setup creates unique combinations that might not be immediately obvious. The nonstandard die doesn't change the number of possible outcomes, since it still has six sides, but it introduces elements that differ greatly from what's expected. Understanding these differences is key to solving probability distribution problems involving such dice.
Probability Calculation
Calculating probabilities with nonstandard dice follows the same basic principles as with standard dice. First, consider the number of outcomes. Each die operates independently, which means to find the total outcomes, multiply the number of outcomes on each die together.
  • The standard die has 6 possible outcomes.
  • The nonstandard die also has 6 possible outcomes (0 three times and 6 three times).
  • Total outcomes are therefore 6 multiplied by 6, equaling 36.
In probability, we look at favorable outcomes over total possible outcomes. When rolling these nonstandard dice, you'll calculate how likely it is to achieve certain sums by dividing the number of ways to get that sum by 36, the total number of outcomes.
Sum of Rolls
When you roll two dice together, you often want to know the sum of the numbers on the top faces. With a standard die, the minimum sum is 2 (if both dice show 1), and the maximum is 12 (if both dice show 6). Our nonstandard die presents different possibilities.
  • The lowest sum, which occurs when the standard die shows 1 and the nonstandard die shows 0, is 1.
  • The highest sum happens when the standard die shows 6 and the nonstandard die shows 6, giving a sum of 12.
To find all possible sums, combine each face of the first die with each face of the nonstandard die. This covers every scenario from 1 to 12, showing you the unique character of probability distributions created by pairing standard and nonstandard dice.
Outcome Combinations
Outcome combinations are central to understanding probability distribution. Given that each die roll is independent, pairing outcomes from a standard die with outcomes from a nonstandard die creates a grid of possible sums.
  • To illustrate, if you roll a 1 on the standard die and a 0 on the nonstandard die, the sum is 1.
  • When you roll a 1 on the standard die and a 6 on the nonstandard die, the sum is 7.
Continue matching each number from the standard die with each number from the nonstandard to check off every combination. For each sum (like 7 from both "1 & 6" and "6 & 1"), count all relevant combinations. This step allows you to construct a complete probability distribution table, essential for visualizing and calculating the probability of each possible sum in the scenario. This awareness of each potential outcome combination is crucial when dealing with nonstandard probability problems.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Door Prize. A party host gives a door prize to one guest chosen at random. There are 48 men and 42 women at the party. What is the probability that the prize goes to a woman? Explain how you arrived at your answer.

Foreign-language Study. Choose a student in a U.S. public high school at random and ask if he or she is studying a language other than English. Here is the distribution of results: \begin{tabular}{|l|c|c|c|c|c|} \hline Language & Sparish & French & German & All athers & None \\ \hline Probability & \(0.30\) & \(0.08\) & \(0.02\) & \(0.03\) & \(0.57\) \\ \hline \end{tabular} a. Explain why this is a legitimate probability model. b. What is the probability that a randomly chosen student is studying a language other than English? c. What is the probability that a randomly chosen student is studying French, German, or Spanish?

Who Gets Interviewed? Abby, Deborah, Mei-Ling, Sam, and Roberto are students in a small seminar course. Their professor decides to choose two of them to interview about the course. To avoid unfairness, the choice will be made by drawing two names from a hat. (This is an SRS of size 2.) a. Write down all possible choices of two of the five names. This is the sample space. b. The random drawing makes all choices equally likely. What is the probability of each choice? c. What is the probability that Mei-Ling is chosen? d. Abby, Deborah, and Mei-Ling liked the course. Sam and Roberto did not like the course. What is the probability that both people selected liked the course?

Choose a common fruit fly Drosophila melanogaster at random. Call the length of the thorax (where the wings and legs attach) \(Y\). The random variable \(Y\) has the Normal distribution with mean \(\mu=0.800\) millimeter \((\mathrm{mm})\) and standard deviation \(\sigma=0.078 \mathrm{~mm}\). The probability \(P(Y>1)\) that the fly you choose has a thorax more than \(1 \mathrm{~mm}\) long is about a. \(0.995 .\) b. \(0.5\). c. \(0.005\).

Loaded Dice. There are many ways to produce crooked dice. To load a die so that 6 comes up too often and 1 (which is opposite 6) comes up too seldom, add a bit of lead to the filling of the spot on the 1 face. If a die is loaded so that 6 comes up with probability \(0.2\) and the probabilities of the \(2,3,4\), and 5 faces are not affected, what is the assignment of probabilities to the six faces?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.