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Grading managers. In Exercise 3.44, we saw that Ford Motor Company once graded its managers in such a way that the top \(10 \%\) received an A grade, the bottom \(10 \%\) a C, and the middle \(80 \%\) a B. Let's suppose that performance scores follow a Normal distribution. How many standard deviations above and below the mean do the \(\mathrm{A} / \mathrm{B}\) and \(\mathrm{B} / \mathrm{C}\) cutoffs lie? (Use the standard Normal distribution to answer this question.)

Short Answer

Expert verified
The A/B cutoff is at +1.28 SDs and the B/C cutoff is at -1.28 SDs from the mean.

Step by step solution

01

Understanding the Normal Distribution

Since performance scores are Normally distributed, we can use the standard Normal distribution to determine how many standard deviations specific cutoffs in the distribution are from the mean.
02

Identifying Percentiles for Cutoffs

An A grade corresponds to the top 10% of the distribution, and a C grade corresponds to the bottom 10%. This means the A/B cutoff is at the 90th percentile and the B/C cutoff is at the 10th percentile.
03

Using the Z-Score Table for the 90th Percentile

To find the Z-score for the 90th percentile, we consult a standard Normal distribution table or calculator. A Z-score of approximately 1.28 corresponds to the 90th percentile, indicating the A/B cutoff.
04

Using the Z-Score Table for the 10th Percentile

The 10th percentile corresponds to a Z-score of approximately -1.28. This indicates the B/C cutoff as it falls below the mean.
05

Conclusion: Interpretation of Cutoffs

The A/B cutoff lies 1.28 standard deviations above the mean, while the B/C cutoff lies 1.28 standard deviations below the mean.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Z-score
The Z-score is a staple concept in the Normal distribution, serving as a helpful tool that standardizes scores, making them easier to interpret. A Z-score indicates how many standard deviations an element is from the mean.
For instance, a Z-score of 0 suggests that the score is exactly at the mean. Meanwhile, a positive Z-score means that the score is above the mean, and a negative Z-score indicates it's below the mean.
In the context of our exercise, finding the right Z-scores helps us determine where the cutoffs for grades A and C lie. Specifically, the exercise shows that for the top 10% of managers (those receiving an A), their performance corresponds to a Z-score of around 1.28. This number indicates that their scores lie 1.28 standard deviations above the average performance, pointing towards excellent performance.
Conversely, a Z-score of -1.28 matches the bottom 10% (those receiving a C), illustrating that their performance is 1.28 standard deviations below the mean, suggesting room for improvement. Understanding the role of the Z-score allows us to accurately figure out the distribution of scores and determine notable cutoffs.
The Role of Percentiles
Percentiles are another important aspect when dealing with Normal distributions. They help categorize data into portions, providing insights into how a data point compares to the rest of the population.
When understanding percentiles, it's crucial to recognize that they reflect the percentage of scores falling below a certain value. For instance, being in the 90th percentile means that 90% of the data falls below that value. In our exercise, this translates to the A-grade cutoff as it encapsulates the top 10% of performers.
Similarly, the 10th percentile indicates that only 10% of data scores lower; hence, it denotes the cutoff for the C grade. This percentile-based thinking spreads scores across a scale, allowing for the identification of outliers and helping us set logical, meaningful boundaries in grading, without getting lost in the distribution of raw scores. Understanding percentiles as a concept assists in pinpointing exact cutoffs in any data set.
Grasping Standard Deviation
Standard deviation is a key measure in statistics that quantifies the amount of variation or dispersion in a set of data. It gives insight into how spread out the data points are relative to the mean.
When scores are close to the average, the standard deviation is smaller, indicating low variability. Conversely, larger standard deviation values demonstrate higher variability with data spread over a wide range. In our exercise, the standard deviation is vital for assessing the spread of performance scores across managers.
By knowing how many standard deviations above or below the mean the grades sit, we can make informed decisions about which scores fall into particular categories, such as A, B, or C. Therefore, the standard deviation helps us determine the score’s standing relative to the entire distribution, consequently recognizing areas of performance excellence or areas needing improvement. Understanding standard deviation not only interprets data spread but also aids in making educated decisions based on that spread.

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Most popular questions from this chapter

Use the Normal Table. Use Table A to find the proportion of observations from a standard Normal distribution that satisfies each of the following statements. In each case, sketch a standard Normal curve and shade the area under the curve that is the answer to the question. (a) \(z<-0.42\) (b) \(z>-1.58\) (c) \(z<2.12\) (d) \(-0.42

To completely specify the shape of a Normal distribution, you must give (a) the mean and the standard deviation. (b) the five-number summary. (c) the median and the quartiles.

Normal is only approximate: ACT scores. Composite scores on the ACT test for the 2015 high school graduating class had mean \(21.0\) and standard deviation 5.5. In all, 1,924,436 students in this class took the test. Of these, 205,584 had scores higher than 28 , and another 60,551 had scores exactly 28 . ACT scores are always whole numbers. The exactly Normal \(N(21.0,5.5)\) distribution can include any value, not just whole numbers. What is more, there is no area exactly above 28 under the smooth Normal curve. So ACT scores can be only approximately Normal. To illustrate this fact, find (a) the percent of 2015 ACT scores greater than 28 using the actual counts reported. (b) the percent of \(2015 \mathrm{ACT}\) scores greater than or equal to 28 , using the actual counts reported. (c) the percent of observations that are greater than 28 using the \(N(21.0,5.5)\) distribution. (The percent greater than or equal to 28 is the same, because there is no area exactly over 28.)

The distribution of hours of sleep per week night, among college students, is found to be Normally distributed, with a mean of \(6.5\) hours and a standard deviation of 1 hour. What range contains the middle \(95 \%\) of hours slept per week night by college students? (a) \(5.5\) and \(7.5\) hours per week night (b) \(4.5\) and \(7.5\) hours per week night (c) \(4.5\) and \(8.5\) hours per week night

Grading managers. Some companies "grade on a bell curve" to compare the performance of their managers and professional workers. This forces the use of some low performance ratings so that not all workers are listed as "above average." Ford Motor Company's "performance management process" for this year assigned \(10 \%\) A grades, \(80 \%\) B grades, and \(10 \% \mathrm{C}\) grades to the company's managers. Suppose Ford's performance scores really are Normally distributed. This year, managers with scores less than 25 received \(\mathrm{C}\) grades and those with scores above 475 received A grades. What are the mean and standard deviation of the scores?

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