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The distribution of hours of sleep per week night, among college students, is found to be Normally distributed, with a mean of \(6.5\) hours and a standard deviation of 1 hour. What range contains the middle \(95 \%\) of hours slept per week night by college students? (a) \(5.5\) and \(7.5\) hours per week night (b) \(4.5\) and \(7.5\) hours per week night (c) \(4.5\) and \(8.5\) hours per week night

Short Answer

Expert verified
Option (c) \(4.5\) and \(8.5\) hours contains the middle 95%.

Step by step solution

01

Understand the Normal Distribution

The problem states that the hours of sleep per week night are normally distributed with a mean (\(\mu\)) of 6.5 hours and a standard deviation (\(\sigma\)) of 1 hour. The task involves finding the range that contains the middle 95% of this distribution.
02

Use the Empirical Rule

The empirical rule for normally distributed data tells us that approximately 95% of the data falls within two standard deviations from the mean. Specifically, this range is \(\mu \pm 2\sigma\).
03

Calculate Two Standard Deviations from the Mean

Given \(\mu = 6.5\) and \(\sigma = 1\), calculate the range: \(6.5 - 2(1)\) and \(6.5 + 2(1)\). This simplifies to 4.5 and 8.5 hours, respectively.
04

Verify the Range

The calculated range from Step 3 is 4.5 to 8.5 hours. Check the multiple-choice options to see which one contains this range. Option (c) is \(4.5\) and \(8.5\) hours per week night, which matches.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean and Standard Deviation
In statistics, the mean is often referred to as the average. It represents the central point or typical value of a set of data. In the context of normal distribution, it is the point around which the data is symmetrically distributed. For this exercise, the mean (\(\mu\)) is \(6.5\) hours.
To understand the data's variability, we use standard deviation. Standard deviation measures how spread out the numbers in a data set are from the mean. A smaller standard deviation indicates that the data points tend to be closer to the mean, while a larger one signifies a more spread-out distribution. Here, the standard deviation (\(\sigma\)) is \(1\) hour.
These two metrics, the mean, and standard deviation, fully describe a normally distributed curve. They help us understand not only the center of the data but also its spread, which is crucial for statistical analysis.
Empirical Rule
The Empirical Rule is a handy shortcut for understanding the spread of data in a normal distribution. It is sometimes known as the 68-95-99.7 rule, providing a simple way to know where most of your data points lie.
This rule states:
  • 68% of data falls within one standard deviation (\(\mu \pm 1\sigma\)) of the mean.
  • 95% of data falls within two standard deviations (\(\mu \pm 2\sigma\)) of the mean.
  • 99.7% of data falls within three standard deviations (\(\mu \pm 3\sigma\)) of the mean.
In the given problem, we are interested in the range that contains 95% of hours slept. Using the Empirical Rule, we quickly calculate that 95% of the data is within two standard deviations from the mean (\(6.5 \pm 2 \times 1\)), resulting in a range of \(4.5\) to \(8.5\) hours. This helps make quick, informed decisions without complex calculations.
Statistical Problem Solving
Solving statistical problems often involves a structured approach that helps break down complex questions into manageable steps. In the context of the exercise, it's about leveraging known statistical principles to find solutions.
First, understand the distribution. Recognize that the problem describes a normal distribution; this knowledge tells you that mean and standard deviation are key.
Then, apply relevant rules. The Empirical Rule was crucial in our problem because it provided a direct method to identify the range incorporating 95% of the data.
Finally, verify and interpret the results. Once you calculate the range, check against given options to confirm the correct answer. This validation ensures that you've correctly applied statistical concepts to arrive at the right solution.
  • Identify the distribution type.
  • Use appropriate statistical rules.
  • Calculate solutions and verify them.
A follow-through on these steps helps in solving many statistical problems with confidence.

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Most popular questions from this chapter

A surprising calculation. Changing the mean and standard deviation of a Normal distribution by a moderate amount can greatly change the percent of observations in the tails. Suppose a college is looking for applicants with SAT math scores 750 and above. (a) In 2015, the scores of men on the math SAT followed the \(N(527,124)\) distribution. What percent of men scored 750 or better? (b) Women's SAT math scores that year had the \(N(496,115)\) distribution. What percent of women scored 750 or better? You see that the percent of men above 750 is more than two and a half times the percent of women with such high scores. (On the other hand, women score higher than men on the new SAT writing test, though by a smaller amount.)

What's your percentile? Reports on a student's test score such as the SAT or a child's height or weight usually give the percentile as well as the actual value of the variable. The percentile is just the cumulative proportion stated as a percent: the percent of all values of the variable that were lower than this one. The upper arm lengths of females in the United States are approximately Normal with mean \(35.8 \mathrm{~cm}\) and standard deviation \(2.1 \mathrm{~cm}\), and those for males are approximately Normal with mean \(39.1 \mathrm{~cm}\) and standard deviation \(2.3 \mathrm{~cm}\). (a) Cecile, a 73-year-old female in the United States, has an upper arm length of \(33.9 \mathrm{~cm}\). What is her percentile? (b) Measure your upper arm length to the nearest tenth of a centimeter, referring to Exercise \(3.5\) (page 84 ) for the measurement instructions. What is your arm length in centimeters? What is your percentile?

To completely specify the shape of a Normal distribution, you must give (a) the mean and the standard deviation. (b) the five-number summary. (c) the median and the quartiles.

The Medical College Admissions Test. Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). \({ }^{8}\) A new version of the exam was introduced in spring 2015 and is intended to shift the focus from what applicants know to how well they can use what they know. One result of the change is that the scale on which the exam is graded has been modified, with the total score of the four sections on the test ranging from 472 to 528 . In spring 2015 , the mean score was \(500.0\) with a standard deviation of \(10.6\). (a) What proportion of students taking the MCAT had a score over 510 ? (b) What proportion had scores between 505 and 515 ?

The scores of adults on an IQ test are approximately Normal with mean 100 and standard deviation 15. Alysha scores 135 on such a test. She scores higher than what percent of all adults? (a) About \(5 \%\) (b) About \(95 \%\) (c) About \(99 \%\)

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