/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 The scores of adults on an IQ te... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The scores of adults on an IQ test are approximately Normal with mean 100 and standard deviation 15. Alysha scores 135 on such a test. Her z-score is about (a) \(1.33\). (b) \(2.33\) (c) 6.33.

Short Answer

Expert verified
Option (b) \(2.33) is correct; Alysha's Z-score is approximately 2.33.

Step by step solution

01

Understand the Z-score Formula

The Z-score is a way to measure how many standard deviations an element is from the mean. The formula for calculating the Z-score is: \[ Z = \frac{X - \mu}{\sigma} \] where \(X\) is the value in question, \(\mu\) is the mean of the distribution, and \(\sigma\) is the standard deviation.
02

Identify the Given Values

From the problem, we know that the mean (\(\mu\)) is 100, the standard deviation (\(\sigma\)) is 15, and Alysha's score (\(X\)) is 135.
03

Substitute the Values Into the Formula

Using the Z-score formula, substitute \(X = 135\), \(\mu = 100\), and \(\sigma = 15\):\[ Z = \frac{135 - 100}{15} \]
04

Calculate the Difference

First, calculate the difference between Alysha's score and the mean:\[ 135 - 100 = 35 \]
05

Divide by the Standard Deviation

Now, divide the difference by the standard deviation:\[ Z = \frac{35}{15} \] \[ Z \approx 2.33 \]
06

Determine the Correct Answer

Comparing the calculated Z-score with the options provided, we see that Alysha's Z-score is approximately 2.33.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
A normal distribution is a bell-shaped curve depicting the distribution of data points where most values cluster around a central mean. This shape is symmetric, meaning it looks the same on either side of the center.
In simple terms, it helps us understand how data is spread out. Many natural phenomena, like heights, test scores, and even IQ scores, follow a normal distribution.
  • For a perfectly normal distribution, the mean, median, and mode are all equal.
  • The shape is completely defined by its mean and standard deviation.
  • Most data points lie within one standard deviation of the mean.
Understanding normal distribution is crucial because it forms the basis for many statistical analyses and hypothesis testing. It allows us to determine how likely an event is, by looking at the area under the curve corresponding to that event's range of values.
Mean and Standard Deviation
The mean is what most people commonly think of as the average. It’s calculated by adding up all the numbers in a dataset and dividing by the number of entries. The mean provides a central value making it easier to compare different datasets.
In our example, the mean of IQ scores is given as 100.
The standard deviation, on the other hand, tells you how much the data values deviate from the mean. It’s a measure of the "spread" or "dispersion" of a set of values. A small standard deviation means that most numbers are close to the mean. A larger standard deviation indicates a wider range of values.
  • Standard deviation is denoted by the symbol \(\sigma\).
  • In a normal distribution, approximately 68% of data values fall within one standard deviation of the mean.
  • For our exercise, the standard deviation is 15, indicating how spread out the IQ scores are around the mean of 100.
Understanding both concepts helps in interpreting how individual data points relate to the data set as a whole, using the Z-score calculations as seen in the exercise.
Standard Deviation Calculation
To understand the concept of standard deviation calculation, think of it as a multi-step process designed to quantify the amount of variation in a dataset.
Calculating standard deviation involves these steps:
  • Calculate the mean of the dataset.
  • Subtract the mean from each data point to find the deviation of each point.
  • Square each deviation to eliminate negative values.
  • Find the mean of these squared deviations, which is known as the variance.
  • Take the square root of the variance to find the standard deviation.
For the IQ scores in our example:
  • The dataset's mean is 100, and the standard deviation is 15. This value is pre-calculated and given to you, simplifying the process.
  • If you had a set of IQ scores, you would follow these steps to calculate the standard deviation to understand how spread out the scores are.
Mastering this concept allows students to better comprehend variability within datasets and interpret scores, much like deducing Alysha's IQ from the exercise.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Monsoon Rains. The summer monsoon rains bring \(80 \%\) of India's rainfall and are essential for the country's agriculture. Records going back more than a century show that the amount of monsoon rainfall varies from year to year according to a distribution that is approximately Normal with mean 852 millimeters \((\mathrm{mm})\) and standard deviation \(82 \mathrm{~mm}^{3}\) Use the \(68-95-99.7\) rule to answer the following questions. (a) Between what values do the monsoon rains fall in the middle \(95 \%\) of all years? (b) How small are the monsoon rains in the driest \(2.5 \%\) of all years?

Fruit flies. The common fruit fly Drosophila melanogaster is the most studied organism in genetic research because it is small, is easy to grow, and reproduces rapidly. The length of the thorax (where the wings and legs attach) in a population of male fruit flies is approximately Normal with mean \(0.800\) millimeter (mm) and standard deviation \(0.078 \mathrm{~mm}\). (a) What proportion of flies have thorax length less than \(0.7 \mathrm{~mm}\) ? (b) What proportion have thorax length greater than \(1.0 \mathrm{~mm}\) ? (c) What proportion have thorax length between \(0.7 \mathrm{~mm}\) and \(1.0 \mathrm{~mm}\) ?

Standard Normal drill. (a) Find the number \(z\) such that the proportion of observations that are less than \(z\) in a standard Normal distribution is \(0.2\). (b) Find the number \(z\) such that \(40 \%\) of all observations from a standard Normal distribution are greater than z.

A surprising calculation. Changing the mean and standard deviation of a Normal distribution by a moderate amount can greatly change the percent of observations in the tails. Suppose a college is looking for applicants with SAT math scores 750 and above. (a) In 2015, the scores of men on the math SAT followed the \(N(527,124)\) distribution. What percent of men scored 750 or better? (b) Women's SAT math scores that year had the \(N(496,115)\) distribution. What percent of women scored 750 or better? You see that the percent of men above 750 is more than two and a half times the percent of women with such high scores. (On the other hand, women score higher than men on the new SAT writing test, though by a smaller amount.)

Perfect SAT scores. It is possible to score higher than 1600 on the combined mathematics and reading portions of the SAT, but scores 1600 and above are reported as 1600 . The distribution of SAT scores (combining mathematics and reading) in 2014 was close to Normal with mean 1010 and standard deviation 218. What proportion of SAT scores for these two parts were reported as 1600 ? (That is, what proportion of SAT scores were actually higher than 1600?)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.