Chapter 3: Problem 29
Standard Normal drill. (a) Find the number \(z\) such that the proportion of observations that are less than \(z\) in a standard Normal distribution is \(0.2\). (b) Find the number \(z\) such that \(40 \%\) of all observations from a standard Normal distribution are greater than z.
Short Answer
Expert verified
(a) \(-0.84\), (b) \(0.25\)
Step by step solution
01
Identify the Value for Part (a)
We are asked to find the z-value such that 20% of the observations are less than this value. In a standard normal distribution, this means we need to find the z-score that corresponds to a cumulative probability of 0.2.
02
Determine the z-score for 0.2
Using a standard normal distribution table or a calculator, we look for the z-score where the cumulative probability is closest to 0.2. This corresponds to a z-score of approximately \(-0.84\).
03
Interpret Part (b)
For part (b), we need the z-value where 40% of the observations are greater than this value. This means we are looking for the z-score that leaves 60% of the observations below it (since 100% - 40% = 60%).
04
Find the z-score for 0.6
Referring to the standard normal distribution table or a calculator, we find the z-score that corresponds to a cumulative probability of 0.6. This is approximately \(0.25\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Z-Score
The z-score plays an integral role in statistics, particularly when dealing with standard normal distribution. It essentially measures how many standard deviations an element is from the mean. In a standard normal distribution, the mean is 0 and the standard deviation is 1.
- A z-score of 0 indicates that the data point's score is identical to the mean score.
- A positive z-score indicates a value above the mean, while a negative one indicates a value below the mean.
Exploring Cumulative Probability
Cumulative probability refers to the probability that a random variable will be less than or equal to a certain value. In the context of the standard normal distribution, it helps to determine how much of the distribution lies to the left of a particular z-score.
- Cumulative probabilities are expressed in decimal form, representing a percentage of the total distribution.
- For instance, if a z-score has a cumulative probability of 0.2, it means that 20% of the data lies below that z-score.
- Similarly, if a z-score has a cumulative probability of 0.6, 60% of the data lies below this value, leaving 40% above it.
Approaching Statistics Problem-Solving
Statistics problem-solving often involves a methodical approach to interpret and analyze data. Tasks like identifying z-scores, as shown in the original exercise, require understanding both the theoretical and practical application of statistical concepts. Here's a suggested approach:
- Identify the Problem: Clearly determine what is being asked—in this case, the z-score corresponding to a given cumulative probability.
- Gather Information: Use the standard normal distribution table or a calculator to find the necessary z-scores.
- Interpret Results: Translate the numerical findings into meaningful insights regarding your dataset.
Using the Normal Distribution Table
A normal distribution table, often referred to as the z-table, is an essential tool in statistics. It helps find the probability that a standard normal random variable is less than or equal to a given z-score. Understanding how to read it can greatly enhance your ability to solve problems involving standard normal distribution.
- The z-table provides cumulative probabilities for z-scores, typically covering only half from 0 to positive infinity because of the symmetry of the normal distribution.
- To find a z-score for a particular cumulative probability, locate the probability in the table. Then, follow the corresponding row and column, which gives you the z-score.
- The use of a normal distribution table is prevalent in statistics due to its ability to provide quick and accurate results for probabilities related to the normal distribution.