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In the National AIDS Behavioral Surveys sample of 2673 adult heterosexuals, \(0.2 \%\) (that's \(0.002\) as a decimal fraction) had both received a blood transfusion and had a sexual partner from a group at high risk of AIDS. Explain why we can't use the large-sample confidence interval to estimate the proportion \(p\) in the population who share these two risk factors.

Short Answer

Expert verified
The sample size condition \(np \approx 5.346\) barely meets the criteria for normality, but \(p = 0.002\) is too small for a reliable normal approximation.

Step by step solution

01

Understand Large-Sample Confidence Interval

The large-sample confidence interval for a proportion is generally used when the sample size is large enough so that the sampling distribution of the sample proportion is approximately normal. A rule of thumb is that both \(np\) and \(n(1-p)\) should be at least 5, where \(n\) is the sample size and \(p\) is the sample proportion.
02

Calculate the Necessary Conditions

For this exercise, we find both \(np\) and \(n(1-p)\). The sample size \(n = 2673\), and the proportion \(p = 0.002\). Calculate \(np = 2673 \times 0.002 = 5.346\). Then calculate \(n(1-p) = 2673 \times 0.998 = 2667.654\).
03

Analyze the Conditions

Check if both \(np\) and \(n(1-p)\) fulfill the rule of at least 5. While \(np = 5.346\) is slightly above 5, it is barely so. Although the conditions are met in a strict sense, the very small proportion value (0.002) makes the approximation to a normal distribution questionable, as the situation involves a very low event rate.
04

Conclusion

Given that \(p\) is very small (0.002), even though \(np\) meets the minimum requirement, the reliability of the normal approximation can be poor for such rare events. Therefore, the large-sample confidence interval may not accurately estimate the population proportion \(p\) due to these limitations. A different statistical approach would be more appropriate in this case.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Size
The term 'sample size' refers to the number of observations or participants included in a study. In the context of estimating a population proportion, having a sufficient sample size is crucial because it determines how well the sample proportion estimates the true population parameter. A larger sample size generally offers more reliable estimates because it reduces the margin of error. For example, in surveys or polls, the results are more trustworthy if they are based on a larger group because they more accurately represent the entire population. But, it's not just about having a big sample; it's also about whether it meets the necessary conditions for statistical techniques, like confidence intervals, to be applicable. For instance, in the given problem, the sample size is 2673. Even though this seems large, it's important to check if criteria like the product of sample size and proportion meet thresholds for approximating a normal distribution. This links directly to the conditions for using the large-sample confidence interval.
Normal Distribution
The normal distribution, often called the bell curve due to its shape, is a fundamental concept in statistics. It describes how the values of a variable are distributed. Most values cluster around a central region, with values tapering off as they move away from the center.In statistics, many methods rely on the assumption that the underlying data follow a normal distribution. This assumption simplifes the analysis, making it easier to apply various techniques, like confidence intervals.However, this distribution is applicable only under certain assumptions. For example, with proportions, both the number of successes, \(np\), and failures, \(n(1-p)\), should be sufficiently large for the sample proportion to approximate a normal distribution. In our problem, even though these values (5.346 and 2667.654) technically meet the requirement, the distribution is skewed due to the small proportion, illustrating that meeting conditions does not always guarantee a reliable outcome.
Population Proportion
A population proportion (denoted as \(p\)) is the fraction of individuals in a population having a particular characteristic. For example, if you're looking at the proportion of people with a certain medical condition, \(p\) represents this percentage within the whole population.Estimating population proportion accurately is essential, and it involves taking a sample and calculating the sample proportion to infer about the population proportion. However, challenges arise when the proportion is extremely small, as in this scenario, where \(p = 0.002\).Such small values can make statistical techniques like the large-sample confidence interval less reliable because these methods assume the sample mean of the proportion follows a normal distribution. When \(p\) is tiny, this assumption weakens, potentially leading to inaccurate estimates.
Rare Events
Rare events refer to occurrences that happen infrequently within a given context or population. In statistics, estimating the probability or proportion of such rare events can be tricky, as traditional methods may not perform well. In our problem, the proportion of adults with both risk factors for AIDS is only 0.2%, qualifying as a rare event. While the large-sample confidence interval might work for more common outcomes, it becomes less reliable with rare events, because the assumptions of normality don't hold as well in these situations. To address rare events, alternative statistical methods, like exact tests or adjusted confidence intervals, might be necessary. This ensures more accurate estimation and better decision-making based on the data. Understanding these subtleties helps us avoid the pitfalls of using inappropriate statistical methods.

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Most popular questions from this chapter

Explain whether we can use the \(z\) test for a proportion in these situations. (a) You toss a coin 10 times in order to test the hypothesis \(H_{0}: p=0.5\) that the coin is balanced. (b) A local candidate contacts an SRS of 900 of the registered voters in his district to see if there is evidence that more than half support the bill he is sponsoring. (c) A college president says, " \(99 \%\) of the alumni support my firing of Coach Boggs." You contact an SRS of 200 of the college's 15,000 living alumni to test the hypothesis \(H_{0}: p=0.99\).

\(\hat{p}\). Greenville County, South Carolina, has 461,299 adult residents, of which 59,969 are 65 years or older. A survey wants to contact \(n=689\) residents. \({ }^{5}\) (a) Find \(p\), the proportion of Greenville county adult residents who are 65 years or older. (b) If repeated simple random samples of 689 residents are taken, what would be the range of the sample proportion of adults over 65 in the sample according to the 95 part of the 68-95-99.7 rule? (c) The actual survey contacted 689 adults using random digit dialing of residential numbers using a database of exchanges, with no cell phone numbers contacted. The 689 respondents represent a response rate of approximately \(30 \%\). In the sample obtained, 253 of the 689 adults contacted were over 65 . Do you have any concerns treating this as a simple random sample from the population of adult residents of Greenville County? Explain briefly.

Based on the sample, the large-sample \(90 \%\) confidence interval for the proportion of all American adults who actively try to avoid drinking regular soda or pop is (a) \(0.611 \pm 0.020\). (b) \(0.611 \pm 0.025\). (c) \(0.611 \pm 0.031\).

U.S. National Parks that contain designated wilderness areas are required by law to develop and maintain a wilderness stewardship plan. The Olympic National Park, containing some of the most biologically diverse wilderness in the United States, had a survey conducted in 2012 to collect information relevant to the development of such a plan. National Park Service staff visited 30 wilderness trailheads in moderate- to high-use areas over a 60-day period and asked visitors as they completed their hike to complete a questionnaire. The 1019 completed questionnaires, giving a response rate of \(50.4 \%\), provided each subject's opinions on the use and management of wilderness. In particular, there were 694 day users and 325 overnight users in the sample. \({ }^{25}\) (a) Why do you think the National Park staff only visited trailheads in moderate- to high-use areas to obtain the sample? (b) Assuming the 1019 subjects represent a random sample of users of the wilderness areas in the Olympic National Park, give a \(90 \%\) confidence interval for the proportion of day users. (c) The response rate was \(49 \%\) for day users and \(52 \%\) for overnight users. Does this lessen any concerns you might have regarding the effect of nonresponse on the interval you obtained in part (b)? Explain briefly. (d) (d) Do you think it would be better to refer to the interval in part (b) as a confidence interval for the proportion of day users or the proportion of day users on the most popular trails in the park? Explain briefly.

Sample surveys usually contact large samples, so we can use the large-sample confidence interval if the sample design is close to an SRS. Scientific studies often use smaller samples that require the plus four method. For example, Familial Adenomatous Polyposis (FAP) is a rare inherited disease characterized by the development of an extreme number of polyps early in life and colon cancer in virtually \(100 \%\) of patients before the age of 40 . A group of 14 people suffering from FAP being treated at the Cleveland Clinic drank black raspberry powder in a slurry of water every day for nine months. The numbers of polyps were reduced in 11 out of 14 of these patients. \({ }^{18}\) (a) Why can't we use the large-sample confidence interval for the proportion \(p\) of patients suffering from FAP that will have the number of polyps reduced after nine months of treatment? (b) The plus four method adds four observations-two successes and two failures. What are the sample size and the number of successes after you do this? What is the plus four estimate \(\mathrm{p}^{-\bar{p}}\) of \(p\) ? (c) Give the plus four \(90 \%\) confidence interval for the proportion of patients suffering from FAP who will have the number of polyps reduced after nine months of treatment.

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