/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 The 2013-2014 roster of the Seat... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The 2013-2014 roster of the Seattle Seahawks, winners of the 2014 NFL Super Bowl, included 10 defensive linemen and nine offensive linemen. The weights in pounds of the 10 defensive linemen were \(\begin{array}{llllllllll}311 & 254 & 297 & 260 & 323 & 242 & 300 & 252 & 303 & 274\end{array}\) The mean of these data is (a) \(281.60\). (b) \(282.50\). (c) \(285.50\).

Short Answer

Expert verified
The mean of the weights is 281.60, so the correct option is (a).

Step by step solution

01

Write Down the Weights

The weights of the 10 defensive linemen are given as: 311, 254, 297, 260, 323, 242, 300, 252, 303, and 274. We need to find the mean of these numbers.
02

Sum the Weights

Add up all the weights of the defensive linemen. This means calculating 311 + 254 + 297 + 260 + 323 + 242 + 300 + 252 + 303 + 274.
03

Perform the Addition

By performing the addition, we get: \[311 + 254 + 297 + 260 + 323 + 242 + 300 + 252 + 303 + 274 = 2816\]
04

Count the Number of Linemen

There are 10 defensive linemen whose weights have been summed.
05

Compute the Mean

The mean weight is the sum of the weights divided by the number of linemen. \[\text{Mean} = \frac{2816}{10} = 281.6\]
06

Choose the Correct Option

The mean calculated is 281.6, which matches option (a) which is 281.60.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Data Analysis
Data analysis is a fundamental process that involves inspecting, cleansing, transforming, and modeling data to discover useful information and support decision-making. For this exercise, analyzing the weights of the Seattle Seahawks' defensive linemen means methodically working through the given data. The first step in any analysis is to clearly understand what the data represents and how you can use it.

Here, the dataset consists of a series of weights measured in pounds. The goal is to calculate the mean weight, a basic statistic that gives us the central tendency of the weight distribution for these athletes. This analysis provides insights into the size and mass of the players, which can be crucial for understanding team dynamics and player characteristics.
  • Data is the list of weights of 10 defensive linemen.
  • Understand the distribution of these weights can reflect player size and performance.
  • Summing up the data correctly is essential before any further calculations.
Using data analysis to compute statistics like the mean helps in drawing solid conclusions about the overall weight trend of the group's weights.
Descriptive Statistics
Descriptive statistics provides simple summaries about the sample and the measures. In this case, we aim to summarize the dataset which consists of the weights of defensive linemen from the Seattle Seahawks. Such statistics give a clear picture of data's central tendency, variability, and shape.

The mean, calculated in the exercise, is a measure of central tendency, which tells us the average weight of the linemen. Calculating this involves a series of straightforward computational steps which help distill a vast amount of data into a comprehensible form.
  • The mean shows the average weight – an important statistic for understanding the dataset's central tendency.
  • Descriptive statistics ease the comprehension of complex data by summarizing quantitative details.
  • Compute sum of the dataset and divide by number of variables to obtain the mean.
By using these statistics, we make the data more readable and useful for real-world applications such as comparing athletes in a sports analysis context.
Step-by-Step Solution
The step-by-step methodical approach to solving problems ensures clarity and accuracy. Let's walk through the process of calculating the mean of the weights using a simple step-by-step solution shown in the exercise.

  • **Write Down the Data:** Begin by documenting the weights of all linemen: 311, 254, 297, 260, 323, 242, 300, 252, 303, and 274.
  • **Sum the Weights:** Add all these weight values: \[311 + 254 + 297 + 260 + 323 + 242 + 300 + 252 + 303 + 274 = 2816.\]
  • **Count Entries:** Count the number of weights you are working with, which is 10 in total.
  • **Calculate the Mean:** For mean calculation, divide the total sum by the number of entries: \[\text{Mean} = \frac{2816}{10} = 281.6.\]
  • **Verify the Solution:** Match the mean with the options provided to ensure accuracy. Option (a) corresponds correctly in this case.
This structured approach in the exercise helps ensure that each part of the solution process contributes to the final objective clearly and effectively.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Carbon Dioxide Emissions. Burning fuels in power plants and motor vehicles emits carbon dioxide \(\left(\mathrm{CO}_{2}\right)\), which contributes to global warming. The \(\mathrm{CO}_{2}\) emissions (metric tons per capita) for countries varies from \(0.02\) in Burundi to \(44.02\) in Qatar. Although the data set includes 214 countries, the \(\mathrm{CO}_{2}\) emissions of 15 countries are not available on the World Bank database. The data set is too large to print here, but here are the data for the first five countries: \({ }^{6}\) $$ \begin{array}{lc} \hline \text { Country } & \mathbf{C O}_{2} \text { Emissions (Metric Tons per Capita) } \\ \hline \text { Aruba } & 23.92 \\ \hline \text { Andorra } & 5.97 \\ \hline \text { Afghanistan } & 0.43 \\ \hline \text { Angola } & 1.35 \\ \hline \text { Albania } & 1.61 \\ \hline \end{array} $$

What percent of the observations in a distribution are greater than the first quartile? (a) \(25 \%\) (b) \(50 \%\) (c) \(75 \%\)

What are all the values that a standard deviation s can possibly take? (a) \(0 \leq s\) (b) \(0 \leq s \leq 1\) (c) \(-1 \leq s \leq 1\)

You create the data. Give an example of a small set of data for which the mean is greater than the third quartile.

E. Coli in Swimming Areas. To investigate water quality, the Columbus Dispatch took water specimens at 16 Ohio State Park swimming areas in central Ohio. Those specimens were taken to laboratories and tested for E. coli, which are bacteria that can cause serious gastrointestinal problems. For reference, if a 100milliliter specimen (about \(3.3\) ounces) of water contains more than \(130 \mathrm{E}\). coli bacteria, it is considered unsafe. Here are the \(E\). coli levels per 100 milliliters found by the laboratories: \({ }^{2}=\mathrm{Aln}\) ECOLI $$ \begin{array}{rrrrrrrr} 291.0 & 10.9 & 47.0 & 86.0 & 44.0 & 18.9 & 1.0 & 50.0 \\ 190.4 & 45.7 & 28.5 & 18.9 & 16.0 & 34.0 & 8.6 & 9.6 \end{array} $$ Find the mean \(E\). coli level. How many of the lakes have \(E\). coli levels greater than the mean? What feature of the data explains the fact that the mean is greater than most of the observations?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.