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91Ó°ÊÓ

Suppose that scores on the mathematics part of the National Assessment of Educational Progress (NAEP) test for eighthgrade students follow a Normal distribution with standard deviation \(\sigma=110\). You want to estimate the mean score within \(\pm 10\) with \(90 \%\) confidence. How large an SRS of scores must you choose?

Short Answer

Expert verified
You need a sample size of 328.

Step by step solution

01

Identify the Given Values

We know that the standard deviation, \( \sigma \), is 110. The margin of error we want, \( E \), is 10, and the confidence level is 90%.
02

Determine the Z-score for 90% Confidence

For a 90% confidence interval, the critical z-value that corresponds to the middle 90% of the standard normal distribution is approximately 1.645.
03

Use the Margin of Error Formula

The formula to find the necessary sample size \( n \) is \[ n = \left( \frac{z \times \sigma}{E} \right)^2 \]. Substituting the known values, we have \( n = \left( \frac{1.645 \times 110}{10} \right)^2 \).
04

Calculate the Sample Size

First calculate the numerator: 1.645 times 110 equals 180.95. Divide by the margin of error, which is 10, to get 18.095. Finally, square this number to find the sample size, \( n \approx (18.095)^2 = 327.42 \).
05

Round Up to The Nearest Whole Number

Since the sample size must be a whole number, and to ensure the desired precision, round 327.42 up to 328. This is the correct sample size.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
A confidence interval is a range that estimates where the true population parameter lies, based on sample data. It gives you a way to gauge how accurate your sample statistic is in approximating the true population. Imagine it as a "safety net" around your sample mean. A 90% confidence interval means that if you took 100 different samples and computed a confidence interval for each, approximately 90 out of those would contain the true population mean.

Key aspects include:
  • Point estimate: This is typically the sample mean, representing the center of your interval.
  • Margin of error: It reflects the range of values above and below the point estimate, within which the true value lies.
  • Confidence level: This percentage shows how often the true parameter, like a population mean, lies within the interval in repeated sampling.
To understand it better, think of confidence intervals as predicting a weather forecast; while you might not know the exact temperature, you can be confident about a range where it might fall.
Sample Size Calculation
Sample size calculation is crucial for accurate data analysis. It determines how many observations or data points you need to collect to achieve a particular level of accuracy in your estimations. In this exercise, we calculate the minimum number of test scores needed to estimate the average score with a particular margin of error and confidence level.

Why is it important?
  • Ensures reliability: Larger samples typically provide more reliable estimates of population parameters.
  • Balances accuracy against resources: Bigger samples give more precision, but also require more time and resources to gather and analyze.
The formula for sample size is \[ n = \left( \frac{z \times \sigma}{E} \right)^2 \]where:
  • \( z \) is the z-score corresponding to your confidence level (1.645 for 90% confidence).
  • \( \sigma \) is the standard deviation of the population (110 in the given example).
  • \( E \) is the margin of error (10 for this exercise).
By solving this equation with the given values, you find that a sample size of 328 is required to maintain a good balance between confidence and precision.
Normal Distribution
A normal distribution, also known as a bell curve, is a probability distribution that is symmetric about the mean. It is characterized by its mean and standard deviation, which define the shape and spread of the curve. The properties of a normal distribution make it a fundamental concept in statistics for various applications.

Some features are:
  • Mean, median, and mode of a normal distribution are all equal.
  • The curve is perfectly symmetrical about the mean.
  • 68% of the data falls within one standard deviation of the mean, 95% within two, and 99.7% within three (empirical rule).
In the exercise, the NAEP test scores are assumed to follow this distribution, which allows for easier calculations related to confidence intervals and sample sizes using standard formulas. Utilizing the properties of a normal distribution simplifies the calculations of the data's behavior and expectations, especially when estimating population parameters from a sample.
Margin of Error
The margin of error indicates the range within which you expect the population parameter to lie. It represents the maximum amount by which the sample estimate might differ from the true population value.

Understanding the margin of error includes knowing:
  • The higher the confidence level, the larger the margin of error will generally be, since you want to be more certain.
  • Reducing the margin of error requires an increase in sample size.
  • The desired margin of error helps determine the sample size needed for a study.
In this exercise, you wish to estimate the mean test score within 10 points. This margin directly influences the sample size calculation, as a smaller margin usually demands a larger sample. Remember, the margin of error defines the buffer zone around your sample mean, indicating where the true mean likely falls. This concept ensures you can make statistically sound predictions based on your data.

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Most popular questions from this chapter

A medical experiment compared zinc supplements with a placebo for reducing the duration of colds. Let \(\mu\) denote the mean decrease, in days, in the duration of a cold. A decrease to \(\mu=1\) is a practically important decrease. The significance level of a test of \(H_{0}: \mu=0\) versus \(H_{a}: \mu>0\) is defined as (a) the probability that the test rejects \(H_{0}\) when \(\mu=0\) is true. (b) the probability that the test rejects \(H_{0}\) when \(\mu=1\) is true. (c) the probability that the test fails to reject \(H_{0}\) when \(\mu=1\) is true.

Valium is a common antidepressant and sedative. A study investigated how valium works by comparing its effect on sleep in seven genetically modified mice and eight normal control mice. There was no significant difference between the two groups. The authors say that this lack of significance "is related to the large inter-individual variability that is also reflected in the low power \((20 \%)\) of the test." 12 (a) Explain exactly what power \(20 \%\) against a specific alternative means. (b) Explain in simple language why tests having low power often fail to give evidence against a null hypothesis even when the null hypothesis is really false. (c) What fact about this experiment most likely explains the low power?

How much education children get is strongly associated with the wealth and social status of their parents. In social science jargon, this is socioeconomic status, or SES. But the SES of parents has little influence on whether children who have graduated from college go on to yet more education. One study looked at whether college graduates took the graduate admissions tests for business, law, and other graduate programs. The effects of the parents' SES on taking the LSAT test for law school were "both statistically insignificant and small." (a) What does "statistically insignificant" mean? (b) Why is it important that the effects were small in size as well as insignificant?

Example \(16.1\) (page 377) assumed that the body mass index (BMI) of all American young women follows a Normal distribution with standard deviation \(\sigma=7.5\). How large a sample would be needed to estimate the mean BMI \(\mu\) in this population to within \(\pm 1\) with \(95 \%\) confidence?

The Trial Urban District Assessment (TUDA) measures educational progress within participating large urban districts. TUDA gives a reading test scored from 0 to 500 . A score of 210 is a "basic" reading level for fourth-graders. 6 Suppose scores on the TUDA reading test for fourth-graders in your district follow a Normal distribution with standard deviation \(\sigma=40\). In 2013, the mean score for fourth-graders in your district was 220 . You plan to give the reading test to a random sample of 25 fourth-graders in your district this year to test whether the mean score \(\mu\) for all fourth-graders in your district is still above the basic level. You will therefore test $$ \begin{aligned} &H_{0}: \mu=210 \\ &H_{a}: \mu>210 \end{aligned} $$ If the true mean score is again 220 , on average, students are performing above the basic level. You learn that the power of your test at the \(5 \%\) significance level against the alternative \(\mu=220\) is \(0.346\). (a) Explain in simple language what "power \(=0.346\) " means. (b) Explain why the test you plan will not adequately protect you against deciding that average reading scores in your district are not above basic level.

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