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Sketch the standard Normal curve for the \(z\) test statistic and mark off areas under the curve to show why a value of \(z\) that is statistically significant at the \(1 \%\) level in a one-sided test is always statistically significant at the \(5 \%\) level. If \(z\) is statistically significant at the \(5 \%\) level, what can you say about its significance at the \(1 \%\) level?

Short Answer

Expert verified
A z-score significant at 1% is always significant at 5%, but not necessarily vice versa.

Step by step solution

01

Understanding the Significance Levels

In hypothesis testing, the significance level (\(\alpha\)) determines the threshold for rejecting the null hypothesis. A 5% level (\(\alpha = 0.05\)) implies that 5% of the area under the normal distribution lies in the tails, while a 1% level (\(\alpha = 0.01\)) implicates a smaller area, making it harder to reject the null hypothesis.
02

Standard Normal Curve and Z-Score

The standard normal distribution is a normal distribution with a mean of 0 and a standard deviation of 1. In this context, the \(z\)-score represents the number of standard deviations away from the mean. For a one-sided test at the 5% significance level, critical values mark the boundaries for statistically significant results.
03

Marking the 5% Level

For a one-sided test, under a standard normal curve, 5% of the area is in the tail of the curve. Find the critical \(z\)-value at the 5% level, which is approximately 1.645 for a one-sided hypothesis test. Shade the area beyond this critical \(z\)-value to illustrate statistical significance.
04

Marking the 1% Level

Repeat the process for a 1% level. The critical \(z\)-value for this one-sided test is approximately 2.33. Shade the area beyond this \(z\)-value under the curve. Notice that this shaded area is smaller compared to the 5% level, indicating a stricter criterion for significance.
05

Comparing 1% and 5% Levels

The area for the 1% significance level is always smaller than the area for the 5% significance level. Therefore, any \(z\)-score that falls in the 1% significance area also falls in the 5% significance area. This confirms that a \(z\) statistically significant at 1% is also significant at 5%.
06

Evaluating Significance at Different Levels

If a \(z\)-score is significant at the 5% level, it cannot be automatically considered significant at the 1% level because the 1% area is more stringent. To determine if it is significant at 1%, the \(z\)-score must exceed the critical value for the 1% level, i.e., approximately 2.33 for a one-sided test.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
The concept of normal distribution plays a fundamental role in statistics and is characterized by a symmetric, bell-shaped curve. In the context of hypothesis testing, this distribution is usually standardized to have a mean of 0 and a standard deviation of 1, forming the standard normal distribution. This standardized form helps us easily compare and interpret different test scores, notably through the calculation of a z-score.
This special type of normal distribution is crucial when performing tests like the one-sided test, as it allows scientists and statisticians to determine where a particular data point lies relative to the mean.
  • Mean of the distribution is 0
  • Standard deviation is 1
  • The total area under the curve equals 1
Understanding this distribution is essential since it provides the groundwork for calculating probabilities and standard deviations. With the standard normal curve, one can quickly visualize the impact of different z-scores and significance levels.
Z-Score
The z-score is a statistical measure that describes a value's relationship to the mean of a group of values. It is expressed in terms of standard deviations from the mean. For instance, a z-score of 1.645 on a standard normal distribution implies that the data point is 1.645 standard deviations above the mean.
Calculating the z-score involves subtracting the mean from the data point in question and then dividing the result by the standard deviation. \[ z = \frac{(X - \mu)}{\sigma} \]where \(X\) is the value, \(\mu\) is the mean, and \(\sigma\) is the standard deviation.
  • Negative z-scores indicate values below the mean
  • Positive z-scores indicate values above the mean
The purpose of using z-scores, especially in hypothesis testing, is to provide a precise measure of how unlikely a given data point is when compared to a normal distribution. This aids in assessing the statistical significance of observed effects.
Significance Level
The significance level, often denoted by \(\alpha\), represents the probability of rejecting the null hypothesis when it is actually true. It sets the threshold against which the z-score is compared in hypothesis testing. A common significance level used is 5% (\(\alpha = 0.05\)), although more stringent levels like 1% (\(\alpha = 0.01\)) are also used when greater certainty is required.

The choice of significance level affects the critical z-value, which in turn defines the boundary of the rejection region under the normal distribution curve:
  • At 5% significance level, the critical z-value for a one-sided test is approximately 1.645
  • At 1% significance level, the critical z-value is around 2.33
Lowering the significance level means requiring more evidence before rejecting the null hypothesis, making it less likely to make a Type 1 error—incorrectly rejecting a true null hypothesis.
One-Sided Test
A one-sided test, also known as a one-tailed test, is used when the research hypothesis predicts the direction of an effect or relationship. This test allows you to determine whether a particular sample is greater than or less than a known value or another sample.

In statistical analysis, a one-sided test focuses only on one end of the distribution. For example, if you hypothesize that a new drug increases recovery speed, you would use a one-sided test to see if the recovery time is significantly shorter than the time with the old drug.
  • Tests directional hypotheses
  • Only one tail of the distribution is examined
The one-sided test provides more power to detect an effect in one specified direction, making it a valuable tool when directionality is a critical feature of the research hypothesis. This approach, however, requires strong justification for ignoring potential effects in the opposite direction.

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Most popular questions from this chapter

Athletes performing in bright sunlight often smear black eye grease under their eyes to reduce glare. Does eye grease work? In one study, 16 student subjects took a test of sensitivity to contrast after three hours facing into bright sun, both with and without eye grease. This is a matched pairs design. If eye grease is effective, subjects will be more sensitive to contrast when they use eye grease. Here are the differences in sensitivity, with eye grease minus without eye grease: We want to know whether eye grease increases sensitivity on the average. (a) What are the null and alternative hypotheses? Say in words what mean \(\mu\) your hypotheses concern. (b) Suppose that the subjects are an SRS of all young people with normal vision, that contrast differences follow a Normal distribution in this population, and that the standard deviation of differences is \(\sigma=0.22\). Carry out a test of significance.

A test of \(H_{0}: \mu=0\) against \(H_{a}: \mu>0\) has test statistic \(z=1.65\). Is this test statistically significant at the \(5 \%\) level \((\alpha=0.05)\) ? Is it statistically significant at the \(1 \%\) level \((\alpha=0.01)\) ?

The examinations in a large multisection statistics class are scaled after grading so that the mean score is 75 . The professor thinks that students in the 8:00 A.M. class have trouble paying attention because they are sleepy and suspects that these students have a lower mean score than the class as a whole. The students in the 8:00 A.M. class this semester can be considered a sample from the population of all students in the course, so the professor compares their mean score with 75 . State the hypotheses \(H_{0}\) and \(H_{a}\).

Research suggests that pressure to perform well can reduce performance on exams. Are there effective strategies to deal with pressure? In an experiment, researchers had students take a test on mathematical skills. The same students were asked to take a second test on the same skills, but now each student was paired with a partner and only if both improved their scores would they receive a monetary reward for participating in the experiment. They were also told that their performance would be videotaped and watched by teachers and students. To help them cope with the pressure, 10 minutes before the second exam they were asked to write as candidly as possible about their thoughts and feelings regarding the exam. "Students who expressed their thoughts before the high-pressure test showed a statistically significant \(5 \%\) math accuracy improvement from the pretest to posttest" \((P<0.03)\). \(^{9} \mathrm{~A}\) colleague who knows no statistics says that an increase of \(5 \%\) isn't a lotmaybe it's just an accident due to natural variation among the students. Explain in simple language how " \(P<0.03\) " answers this objection.

The Graduate Management Admission Test (GMAT) is taken by individuals interested in pursuing graduate management education. GMAT scores are used as part of the admissions process for more than 6100 graduate management programs worldwide. The mean score for all test-takers is 550 with a standard deviation of \(120 .^{1}\) A researcher in the Philippines is concerned about the performance of undergraduates in the Philippines on the GMAT. She believes that the mean scores for this year's college seniors in the Philippines who are interested in pursuing graduate management education will be less than 550 . She has a random sample of 250 college seniors in the Philippines interested in pursuing graduate management education take the GMAT. Suppose we know that GMAT scores are Normally distributed with standard deviation \(\sigma=120\). (a) We seek evidence against the claim that \(\mu=550\). What is the sampling distribution of the mean score \(\mathrm{x}^{-} \bar{x}\) of a sample of 250 students if the claim is true? Draw the density curve of this distribution. (Sketch a Normal curve, then mark on the axis the values of the mean and 1,2 , and 3 standard deviations of the sampling distribution on either side of the mean.) (b) Suppose that the sample data give \(\mathrm{x}^{-} \bar{x}=542\). Mark this point on the axis of your sketch. (c) Suppose that the sample data give \(\mathrm{x}^{-} \bar{x}=532\). Mark this point on your sketch. Using your sketch, explain in simple language why one result is good evidence that the mean score of all college seniors in the Philippines interested in pursuing graduate management education who plan to take the GMAT is less than 550 and why the other outcome is not.

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