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91Ó°ÊÓ

The examinations in a large multisection statistics class are scaled after grading so that the mean score is 75 . The professor thinks that students in the 8:00 A.M. class have trouble paying attention because they are sleepy and suspects that these students have a lower mean score than the class as a whole. The students in the 8:00 A.M. class this semester can be considered a sample from the population of all students in the course, so the professor compares their mean score with 75 . State the hypotheses \(H_{0}\) and \(H_{a}\).

Short Answer

Expert verified
\(H_0: \mu = 75\), \(H_a: \mu < 75\).

Step by step solution

01

Define the Null Hypothesis

The null hypothesis (denoted as \(H_0\)) is a statement of no effect or no difference. In this question, the professor suspects that students in the 8:00 A.M. class score lower than the average class score. Therefore, the null hypothesis would state that the mean score of the 8:00 A.M. class is equal to the mean score of the entire class. Formally, this is expressed as \(H_0: \mu = 75\), where \(\mu\) represents the mean score of the 8:00 A.M. class.
02

Define the Alternative Hypothesis

The alternative hypothesis (denoted as \(H_a\)) is what you believe to be true if the null hypothesis is rejected. The professor believes that students in the 8:00 A.M. class score lower than average due to being sleepy. Therefore, the alternative hypothesis would state that the mean score of the 8:00 A.M. class is less than the mean score of the entire class. Formally, this is expressed as \(H_a: \mu < 75\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In hypothesis testing, the null hypothesis (denoted as \(H_0\)) serves as a default statement that suggests no change or effect is present. When it comes to statistics, this hypothesis proposes that any kind of observed difference or effect in the data is purely due to random chance, and not because of a specific cause.
For the case involving the 8:00 A.M. class in a statistics course, the null hypothesis claims that there is no difference between the mean scores of students attending this early class and the established mean score of the whole class. This is formalized by stating \( H_0: \mu = 75 \). Here, \( \mu \) represents the mean of the 8:00 A.M. class.
By testing this hypothesis, it is usually understood that until there is sufficient statistical evidence gathered, the null hypothesis remains valid. The purpose is to either provide strong evidence against this hypothesis (leading to its rejection), or to find insufficient evidence, allowing it to stand.
Alternative Hypothesis
The alternative hypothesis (symbolized as \(H_a\) or \(H_1\)) comes into play when there is a belief that something beyond chance is affecting results. In other words, it's what you might believe to be true if your null hypothesis turns out to be unlikely, according to your data.
In the example of the 8:00 A.M. statistics class, the professor suspects that students score less well in the morning due to sleepiness. Consequently, the alternative hypothesis is that the mean score for the early class is actually lower than the others. This can be expressed as \(H_a: \mu < 75\), indicating the belief that \(\mu\), or average score of the 8:00 A.M. class, is less than the total class mean of 75.
  • It represents a significant shift away from the null hypothesis.
  • It usually indicates the existence of an affect, difference, or relationship.
  • While the null assumes the status quo, the alternative suggests something new at play.

The goal of hypothesis testing is to see if the data supports this alternative proposition. If so, the null hypothesis can be rejected in favor of the alternative.
Mean Score Comparison
At its core, hypothesis testing often revolves around comparing means. It's a straightforward yet powerful way to understand whether there's a meaningful difference between groups. In this context, we are comparing the mean score of the entire class against the mean score of one particular 8:00 A.M. cohort.
The established class mean score is 75. The question we aim to answer is whether the students' mean score from the earlier class is significantly different from 75. In statistics, circumstances like these often employ a mean score comparison method.
  • First, you calculate the mean of the 8:00 A.M. class.
  • Next, you compare it against the known class mean of 75.
  • The statistical analysis determines if any observed difference is significant or likely due to random chance.

A considerable difference, along with a sufficiently large sample size, might indicate that students indeed find it challenging to focus in the early hours, which adversely affects their scores. Through this comparison, educators can identify differentiating factors in student performance.

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