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Peanut allergies among children. About \(2 \%\) of children in the United States are allergic to peanuts. \({ }^{21}\) Choose three children at random, and let the random variable \(X\) be the number in this sample who are allergic to peanuts. The possible values \(X\) can take are \(0,1,2\), and 3 . Make a three- stage tree diagram of the outcomes (allergic or not allergic) for the three individuals, and use it to find the probability distribution of \(X\).

Short Answer

Expert verified
P(X=0)=0.941192, P(X=1)=0.057624, P(X=2)=0.001176, P(X=3)=0.000008.

Step by step solution

01

Understand the Scenario

We are given a situation where we have 3 children picked at random, and we know the probability of any one child being allergic to peanuts is 0.02. We are to find how many out of these 3 children might have a peanut allergy.
02

Set Up Initial Probabilities for One Child

The probability of a child being allergic is 0.02. Therefore, the probability of a child not being allergic is 1 - 0.02 = 0.98.
03

Draw a Tree for Three Children

We draw a tree, starting with the first child, then branching for the second and third child. Each branch gives the probability of being allergic (A) or not allergic (N).
04

Calculate Probabilities for Each Path

Calculate the probability for each path in the tree. For example, the path 'A, A, A' (all three are allergic) has a probability of \(0.02 \times 0.02 \times 0.02 = 0.000008\). Similarly, calculate the probabilities for all other paths like 'A, A, N', 'A, N, A', etc.
05

Determine the Values of X and Their Probabilities

Consider the number of allergic children (X): X=0 means no child is allergic, X=1 means exactly one child is allergic, X=2 means exactly two are allergic, and X=3 means all three are allergic. Sum the probabilities from the tree diagram that correspond to each value of X.
06

Calculate Probability Distribution for X=0

Only the path 'N, N, N' corresponds to X=0. The probability for this path is \(0.98 \times 0.98 \times 0.98 = 0.941192\).
07

Calculate Probability Distribution for X=1

Add probabilities for paths where exactly one child is allergic (e.g., 'A, N, N', 'N, A, N', 'N, N, A'). Each path has probability \(0.02 \times 0.98 \times 0.98 = 0.019208\). There are 3 such paths, so sum their probabilities: \(3 \times 0.019208 = 0.057624\).
08

Calculate Probability Distribution for X=2

Add probabilities for paths where exactly two children are allergic (e.g., 'A, A, N', 'A, N, A', 'N, A, A'). Each path has probability \(0.02 \times 0.02 \times 0.98 = 0.000392\). There are 3 such paths, so sum their probabilities: \(3 \times 0.000392 = 0.001176\).
09

Calculate Probability Distribution for X=3

Only the path 'A, A, A' corresponds to X=3. The probability for this path is \(0.02 \times 0.02 \times 0.02 = 0.000008\).
10

Compile the Probability Distribution

The probability distribution of X is: X=0: 0.941192, X=1: 0.057624, X=2: 0.001176, X=3: 0.000008.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tree Diagram
When tackling probability problems, a tree diagram can be a lifesaver. It visually breaks down complex scenarios into manageable pieces, making calculations easier. Imagine a tree diagram as a map. It starts with a trunk and branches out with each decision or outcome.
For our problem, we begin with the first child. They can either be allergic to peanuts, with a probability of 0.02, or not allergic, with a probability of 0.98. Two branches emerge from this point. The process continues similarly for the second and third child.
  • Each branching represents the probabilities for "Allergic (A)" and "Not Allergic (N)".
  • The paths like 'A, A, N' or 'N, A, N' represent different possible outcomes.
Tree diagrams help to compartmentalize each event, guiding your calculations for each potential outcome. This diagram unfolds possibilities and shows you the necessary steps to arrive at a solution.
Random Variable
In this problem, we use a concept called a "random variable." A random variable assigns a value to possible outcomes of an experiment. Here, it tracks how many of the chosen three children have peanut allergies.
We denote this random variable as X. The possible values X can take are 0, 1, 2, and 3.
  • X=0: No child is allergic.
  • X=1: One child is allergic.
  • X=2: Two children are allergic.
  • X=3: All three children are allergic.
Random variables help translate real-world events into mathematical descriptions, making it simpler to perform probability calculations.
Binomial Probability
Binomial probability is handy when you're dealing with experiments that have two outcomes, like a success or failure. Here, the outcomes are either a child having an allergy (success) or not (failure).
Our situation involves three independent trials, each with the same probability of success.
  • The probability of a child being allergic is 0.02 (success).
  • The probability of a child not being allergic is 0.98 (failure).
The formula for determining the probability of X successes (allergic children) across n trials is:\[P(X=k) = \binom{n}{k} p^k (1-p)^{n-k}\]For each scenario, such as X=1 or X=2, binomial probability helps calculate how likely that is, by considering all possible paths from the tree diagram that yield that number of successes.
Allergies in Children
Peanut allergies can be a significant concern, especially among children. Studies show about 2% of children in the U.S. suffer from this allergy. Although it seems like a small percentage, it represents millions of children affected.
When modeling probability distributions in such cases, understanding the base rate (2% here) is crucial. This gives you the probabilities for individual cases, which are fundamental components in broader calculations.
  • Knowing the probability helps healthcare professionals prepare and manage risks effectively.
  • It also guides researchers in understanding shifts in allergy trends over time.
Understanding allergies through a probabilistic lens allows stakeholders to anticipate and address public health concerns more efficiently.

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Most popular questions from this chapter

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