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Gambling A city ballot includes a local initiative that would legalize gambling. The issue is hotly contested, and two groups decide to conduct polls to predict the outcome. The local newspaper finds that \(53 \%\) of 1200 randomly selected voters plan to vote "yes," while a college Statistics class finds \(54 \%\) of 450 randomly selected voters in support. Both groups will create \(95 \%\) confidence intervals. a) Without finding the confidence intervals, explain which one will have the larger margin of error. b) Find both confidence intervals. c) Which group concludes that the outcome is too close to call? Why?

Short Answer

Expert verified
The college class's poll has a larger margin of error and concludes the outcome is too close to call due to its confidence interval including 0.5.

Step by step solution

01

Compare Margin of Error (Conceptual)

The margin of error in a confidence interval is influenced by the sample size; smaller samples generally lead to larger margins of error. Here, the newspaper polled 1200 voters, while the college class polled 450 voters. The college class's smaller sample size suggests that their poll will likely have a larger margin of error than the newspaper's.
02

Calculate the Newspaper's Confidence Interval

To calculate the confidence interval, we use the formula for the margin of error, which is \[ ME = Z \times \sqrt{\frac{p(1-p)}{n}} \]where \( Z \) is the Z-score for a 95% confidence interval (approximately 1.96), \( p \) is the sample proportion, and \( n \) is the sample size. For the newspaper, \( p = 0.53 \) and \( n = 1200 \):\[ ME = 1.96 \times \sqrt{\frac{0.53 \times 0.47}{1200}} \approx 0.028 \].Thus, the confidence interval is \[ 0.53 \pm 0.028 \ = (0.502, 0.558) \].
03

Calculate the College Class's Confidence Interval

Using the same formula for margin of error, with the college class's data \( p = 0.54 \) and \( n = 450 \):\[ ME = 1.96 \times \sqrt{\frac{0.54 \times 0.46}{450}} \approx 0.046 \].Therefore, the confidence interval is\[ 0.54 \pm 0.046 \ = (0.494, 0.586) \].
04

Conclusion on Closeness of Call

The newspaper's confidence interval is (0.502, 0.558), which does not include 0.5, suggesting a clear preference. The college class's confidence interval is (0.494, 0.586), which includes 0.5, indicating the outcome could go either way. Therefore, the college class concludes that the outcome is too close to call.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Margin of Error
When analyzing confidence intervals, the margin of error plays a crucial role as it determines the range within which the true population parameter lies. The margin of error is calculated based on the standard deviation of the sample proportion and the sample size. The formula generally used is \[ ME = Z \times \sqrt{\frac{p(1-p)}{n}} \], where:
  • \( ME \) represents the margin of error.
  • \( Z \) is the Z-score corresponding to the confidence level (e.g., 1.96 for a 95% confidence level).
  • \( p \) is the sample proportion of the population in favor of the outcome.
  • \( n \) is the sample size.
A larger margin of error indicates less certainty about the poll results, whereas a smaller margin of error provides more confidence that the sample statistic is close to the true population parameter. Understanding these elements helps in assessing the reliability of survey results.
Sample Size Effect
Sample size significantly impacts the margin of error and subsequently the confidence interval. The general rule is: **Larger sample sizes tend to produce smaller margins of error**, making the results more reliable. This is because larger samples provide a closer approximation to the entire population. In the original exercise, the newspaper's poll, with its larger sample of 1200 voters, resulted in a smaller margin of error than the college class's poll of 450 voters. This means the newspaper's results were more precise. A smaller sample, like in the college class’s poll, increases variability and thus broadens the range of the confidence interval. For students learning about confidence intervals, remember that more data generally equals more confidence.
Confidence Level
Confidence levels are indicative of how confident we can be that the confidence interval truly contains the population parameter. A common confidence level in statistics is 95%, which corresponds to a Z-score of approximately 1.96. This means that if we were to take 100 different samples and make 100 confidence intervals, approximately 95 of them should contain the true population parameter. The choice of confidence level impacts the width of the confidence interval: higher confidence levels result in wider intervals because more certainty is required that the range includes the true parameter. Therefore, it is a balance between precision and reliability—higher confidence levels reduce the likelihood that the interval misses the true population parameter.
Polling Analysis
Polling analysis involves understanding and critically evaluating surveys and their results. It includes assessing the methods used to collect data, the way questions were phrased, and the sample sizes. Key points to consider in polling analysis are:
  • **Sample Size**: Larger samples yield results that more accurately reflect the population.
  • **Sample Representativeness**: The sample should represent the population demographic to avoid bias.
  • **Margin of Error**: This indicates the range within which the true value lies and should be considered when interpreting results.
  • **Confidence Interval**: A wider interval may suggest less precise results.
In polling analysis, these factors help predict outcomes, such as election results, and inform decisions in business, policy, and other fields. Understanding how these elements interact is foundational to making informed interpretations of poll results.

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Most popular questions from this chapter

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Conditions For each situation described below, identify the population and the sample, explain what \(p\) and \(\hat{p}\) represent, and tell whether the methods of this chapter can be used to create a confidence interval. a) Police set up an auto checkpoint at which drivers are stopped and their cars inspected for safety problems. They find that 14 of the 134 cars stopped have at least one safety violation. They want to estimate the percentage of all cars that may be unsafe, b) A TV talk show asks viewers to register their opinions on prayer in schools by logging on to a website. Of the 602 people who voted, 488 favored prayer in schools. We want to estimate the level of support among the general public. c) A school is considering requiring students to wear uniforms. The PTA surveys parent opinion by sending a questionnaire home with all 1245 students; 380 surveys are returned, with 228 families in favor of the change. d) A college admits 1632 freshmen one year, and four years later 1388 of them graduate on time. The college wants to estimate the percentage of all their freshman enrollees who graduate on time.

Teachers A 2011 Gallup poll found that \(76 \%\) of Americans believe that high achieving high school students should be recruited to become teachers. This poll was based on a random sample of 1002 Americans. a) Find a \(90 \%\) confidence interval for the proportion of Americans who would agree with this. b) Interpret your interval in this context. c) Explain what "90\% confidence" means. d) Do these data refute a pundit's claim that \(2 / 3\) of Americans believe this statement? Explain.

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