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A high school senior uses the Internet to get information on February temperatures in the town where he'll be going to college. He finds a website with some statistics, but they are given in degrees Celsius. The conversion formula is \(\circ \mathrm{F}=9 / 5 \circ \mathrm{C}+32\). Determine the Fahrenheit equivalents for the summary information below. Maximum temperature \(=11 \circ \mathrm{C}\) Range \(=33\) o Mean \(=1 \circ\) Standard deviation \(=70\) Median \(=2 \circ \mathrm{IQR}=16\)

Short Answer

Expert verified
The Fahrenheit equivalents are Maximum Temperature = 51.8 °F, Mean = 33.8 °F, Median = 35.6 °F, Range = 91.4 °F, and IQR = 60.8 °F.

Step by step solution

01

Convert Maximum Temperature

The maximum temperature given is \(11 \circ \mathrm{C}\). To convert this into Fahrenheit, you need to plug it into the formula \( \circ \mathrm{F}=9 / 5 \circ \mathrm{C}+32 \). Doing this, you get \( \circ \mathrm{F}=9 / 5 11+32 = 51.8 \mathrm{F}\).
02

Convert Mean

The mean temperature given is \(1 \circ \mathrm{C}\). To convert this into Fahrenheit, you need to plug it into the formula \( \circ \mathrm{F}=9 / 5 \circ \mathrm{C}+32 \). Doing this, you get \( \circ \mathrm{F}=9 / 5 1+32 = 33.8 \mathrm{F}\).
03

Convert Median Temperature

The median temperature given is \(2 \circ \mathrm{C}\). To convert this into Fahrenheit, you need to plug it into the formula \( \circ \mathrm{F}=9 / 5 \circ \mathrm{C}+32 \). Doing this, you get \( \circ \mathrm{F}=9 / 5 2+32 = 35.6 \mathrm{F}\).
04

Convert Range

The range of temperatures given is \(33 \circ \mathrm{C}\). Remember, the range is not a specific value but the difference between highest and lowest temperatures. That difference remains the same in Fahrenheit but is expressed in Fahrenheit scale. So, to convert this into Fahrenheit, you need to plug it into the formula \( \circ \mathrm{F}=9 / 5 \circ \mathrm{C}+32 \). Doing this, you get \( \circ \mathrm{F}=9 / 5 33+32 = 91.4 \mathrm{F}\).
05

Convert IQR

The inter-quartile range (IQR) of temperatures given is \(16 \circ \mathrm{C}\). As a measure of variability, it changes with scale. So, to convert this into Fahrenheit, you need to plug it into the formula \( \circ \mathrm{F}=9 / 5 \circ \mathrm{C}+32 \). Doing this, you get \( \circ \mathrm{F}=9 / 5 16+32 = 60.8 \mathrm{F}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fahrenheit Celsius Conversion
Understanding the relationship between Fahrenheit and Celsius temperatures is crucial for comparing weather data, cooking temperatures, or any scientific work that involves thermal measurements. The formula to convert Celsius to Fahrenheit is a simple linear equation: \( \circ\mathrm{F} = \dfrac{9}{5} \circ\mathrm{C} + 32 \).

To put it into practice, if you have a temperature in Celsius, you just multiply it by 9, divide by 5, and then add 32 to get the Fahrenheit equivalent. For example, converting the maximum temperature of \(11 \circ\mathrm{C}\) to Fahrenheit involves this calculation: \( \circ\mathrm{F} = \dfrac{9}{5} \times 11 + 32 = 51.8 \circ\mathrm{F} \).

It’s important to note that this conversion formula is bilateral, meaning you can also convert Fahrenheit temperatures back into Celsius by reversing the equation: \( \circ\mathrm{C} = \dfrac{5}{9}(\circ\mathrm{F} - 32) \).
Statistical Summaries
Statistical summaries provide a quick overview of a data set, offering insights into various attributes like central tendencies and variability. Central tendency measures include the mean, which is the average of all data points; the median, representing the middle value in a sorted list; and the mode, which is the most frequently occurring value.

In our exercise, the mean temperature is given as \(1 \circ\mathrm{C}\), which translates to \(33.8 \circ\mathrm{F}\) after the conversion. These summaries help form a picture of typical conditions, but to understand the spread of the data, we look at the range and measures like the standard deviation and the inter-quartile range (IQR).

To improve the understanding of these concepts in exercises, it’s beneficial to include visual aids like graphs or charts and to provide examples from real-life datasets to illustrate their practical applications.
Inter-Quartile Range (IQR)
The inter-quartile range, or IQR, is a metric used in statistics to measure variability by depicting the middle 50% of data. It’s calculated as the difference between the third quartile (Q3) and the first quartile (Q1).

For instance, if you’re given an IQR of \(16 \circ\mathrm{C}\), this indicates that the spread of the middle half of your data set is 16 degrees Celsius. Converting IQR to Fahrenheit requires the same conversion used for individual temperatures, resulting in an IQR of \(60.8 \circ\mathrm{F}\).

Interpreting the IQR

A smaller IQR suggests less variability among the middle 50% of the data, while a larger IQR indicates more variability. Using IQR alongside other statistics like the median can give a more nuanced picture of a dataset’s spread without being influenced by outliers or extreme values.
Measures of Variability
While the mean and median can tell us about the center of our data, measures of variability show us the spread. This includes metrics like the range, variance, standard deviation, and as previously mentioned, the IQR.

The range gives us the difference between the lowest and highest values. In our exercise, converting the range from Celsius to Fahrenheit doesn’t require considering each individual temperature. Instead, we apply the conversion to the range number itself, resulting in a range of \(91.4 \circ\mathrm{F}\), implying the temperatures vary widely.

Standard deviation is another crucial concept, representing the average distance from the mean. However, there seems to be an error in the original exercise with a standard deviation of \(70\), which, considering the context, is not realistic. Addressing such issues is essential to ensure accuracy and understanding.

To aid comprehension, when dealing with measures of variability, it's beneficial to couple explanations with practical examples, demonstrate calculations step-by-step, and highlight the significance of these measures in real-world situations.

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Most popular questions from this chapter

A popular band on tour played a series of concerts in large venues. They always drew a large crowd, averaging 21,359 fans. While the band did not announce (and probably never calculated) the standard deviation, which of these values do you think is most likely to be correct: \(20,200,2000,\) or 20,000 fans? Explain your choice.

Cattle, finis Consider the Angus weights model \(N(1152,84)\) one last time. a. What weight represents the 40th percentile? b. What weight represents the 99th percentile? c. What's the IQR of the weights of these Angus steers?

One of the authors has an adopted grandson whose birth family members are very short. After examining him at his 2-year checkup, the boy's pediatrician said that the z-score for his height relative to American 2-year-olds was \(-1.88 .\) Write a sentence explaining what that means.

A tire manufacturer believes that the treadlife of its snow tires can be described by a Normal model with a mean of 32,000 miles and standard deviation of 2500 miles. a. If you buy one of these tires, would it be reasonable for you to hope it will last 40,000 miles? Explain. b. Approximately what fraction of these tires can be expected to last less than 30,000 miles? c. Approximately what fraction of these tires can be expected to last between 30,000 and 35,000 miles? d. Estimate the IQR of the treadlives. e. In planning a marketing strategy, a local tire dealer wants to offer a refund to any customer whose tires fail to last a certain number of miles. However, the dealer does not want to take too big a risk. If the dealer is willing to give refunds to no more than 1 of every 25 customers, for what mileage can he guarantee these tires to last?

For the car speed data in Exercise 30 ?, recall that the mean speed recorded was \(23.84 \mathrm{mph},\) with a standard deviation of \(3.56 \mathrm{mph}\). To see how many cars are speeding, John subtracts 20 mph from all speeds. a. What is the mean speed now? What is the new standard deviation? b. His friend in Berlin wants to study the speeds, so John converts all the original miles-perhour readings to kilometers per hour by multiplying all speeds by 1.609 (km per mile). What is the mean now? What is the new standard deviation?

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