/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 51 Cattle, finis Consider the Angus... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Cattle, finis Consider the Angus weights model \(N(1152,84)\) one last time. a. What weight represents the 40th percentile? b. What weight represents the 99th percentile? c. What's the IQR of the weights of these Angus steers?

Short Answer

Expert verified
The 40th percentile weight is represented by approximately 1130 pounds. The 99th percentile weight is approximately 1311 pounds. The IQR of the weights of these Angus steers is approximately 113 pounds.

Step by step solution

01

Step 1. Finding the 40th percentile

To find the 40th percentile, we first need to find its corresponding Z-score. From the Z-table, the Z-score close to 40th percentile is -0.25. Now, we plug in the mean, standard deviation and the Z-score into the formula for the Z-score: \( X = Z*SD + Mean \). So, \( X = -0.25*84 + 1152 \)
02

Step 2. Finding the 99th percentile

Similarly, to find the 99th percentile, we first need to find its corresponding Z-score. The Z-score close to 99th percentile is 2.33. We use the same formula \( X = Z*SD + Mean \). So, \( X = 2.33*84 + 1152 \)
03

Step 3. Finding the IQR of the weights

The Interquartile Range (IQR) is the difference between the 75th and 25th percentiles. First we find the Z-scores for both percentiles from the Z-table: for the 75th percentile it's 0.67 and for the 25th percentile it's -0.67. Then we use the same formula \( X = Z*SD + Mean \) to get the two weights. The IQR is the difference between the weights of the 75th percentile and the 25th percentile which is \( IQR = X_{75} - X_{25} \)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

normal distribution
The normal distribution is a fundamental concept in statistics, often depicted as a bell-shaped curve. It describes how data is spread around a mean (average), and is symmetric about this mean. This kind of distribution is characterized by its mean (\( \mu \)) and standard deviation (\( \sigma \)). For example, the Angus weights model in the exercise follows a normal distribution with a mean of 1152 pounds and a standard deviation of 84 pounds.

The mean is the point where the highest peak of the curve is. As we move away from the mean, the frequency of data points decreases, which is why the curve tapers off on both sides. Most data points fall within three standard deviations from the mean, capturing approximately 99.7% of the observations.
  • The area under the curve represents the total probability of all possible outcomes, equaling 1.
  • The symmetry means the distribution is mirror-like about the mean.
  • It is an idealized version of how many natural phenomena distribute.
Understanding normal distribution is crucial because many statistical tests are based on this assumption. It allows us to estimate the likelihood of certain outcomes occurring, as well as to locate percentiles, which are key metrics in data analysis.
Z-score
A Z-score is a statistical measurement that describes a value's relationship to the mean of a group of values. It is expressed in terms of standard deviations from the mean.

In simpler terms, a Z-score tells you how far away a particular score is from the mean, and in which direction. The formula for calculating a Z-score is: \[ Z = \frac{X - \mu}{\sigma} \]where \( X \) is the value in question, \( \mu \) is the mean, and \( \sigma \) is the standard deviation.

For example, in the exercise, to find the weight corresponding to the 40th and 99th percentiles, we first determine the Z-scores from a Z-table. Then, using the Z-score formula reversed:\[ X = Z \times \sigma + \mu \]we find the actual weight values. Z-scores are beneficial because they allow comparisons across different distributions, making diverse datasets comparable.
  • Z-scores can be positive or negative, indicating whether the value is above or below the mean.
  • A Z-score of 0 means the value matches the mean exactly.
  • Z-scores are dimensionless, providing a reliable way to standardize scores.
interquartile range (IQR)
The Interquartile Range (IQR) is a measure of statistical dispersion, which is the spread of your data. Specifically, the IQR measures the spread in the middle 50% of your data.

It is calculated as the difference between the 75th percentile (the third quartile \( Q_3 \)) and the 25th percentile (the first quartile \( Q_1 \)):\[ IQR = Q_3 - Q_1 \]This range is useful because it is not affected by outliers or extreme values, making it a robust measure of variability.

In the given exercise, finding the IQR involves determining the weights that correspond to the 75th and 25th percentiles using the Z-score method, and then subtracting these two values.
  • It's an excellent measure for understanding the data's central tendency.
  • Helps identify outliers since data points outside of\[ Q_1 - 1.5 \times IQR \]and \[ Q_3 + 1.5 \times IQR \]are often considered outliers.
  • The IQR gives insight into the middle half of a distribution, disregarding upper and lower extremes.
standard deviation
Standard deviation is a measure that quantifies the amount of variation or dispersion in a set of data values. It answers the question, "On average, how far are the data points from the mean?"

The formula to calculate the standard deviation (\( \sigma \)) is:\[ \sigma = \sqrt{\frac{\sum (X_i - \mu)^2}{N}} \]where \( X_i \) is each value in the dataset, \( \mu \) is the mean, and \( N \) is the number of values.

In the context of the exercise, the standard deviation of 84 pounds helps determine how widely the cattle weights are spread about the mean of 1152 pounds.
  • A small standard deviation means the data points are close to the mean.
  • A larger standard deviation indicates that the data points are spread out over a wider range.
  • Standard deviation is a fundamental component in many statistical techniques.
Knowing the standard deviation provides insight into the reliability of mean as a measure of central tendency and is also key to calculating Z-scores, which further facilitate understanding percentile rankings.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Chapter 2? (Exercise 16 ) we saw data on shoe sizes of students, reported in European sizes. For the men, the mean size wasis 44.65 with a standard deviation of 2.03. To convert euro shoe sizes to U.S. sizes for men, use the equation USsize \(=\) EuroSize \(\times 0.7865-24\) a. What is the mean men's shoe size for these respondents in U.S. units? b. What is the standard deviation in U.S. units?

Assume the cholesterol levels of adult American women can be described by a Normal model with a mean of \(188 \mathrm{mg} / \mathrm{dL}\) and a standard deviation of \(24 .\) a. Draw and label the Normal model. b. What percent of adult women do you expect to have cholesterol levels over \(200 \mathrm{mg} / \mathrm{dL} ?\)

More IQs In the Normal model \(N(100,15)\) from Exercise 10 ?, what cutoff value bounds a. the highest \(5 \%\) of all IQs? b. the lowest \(30 \%\) of the IQs? c. the middle \(80 \%\) of the IQs?

Based on the Normal model \(N(100,15)\) describing IQ scores, what percent of people's IQs would you expect to be a. over \(80 ?\) b. under \(90 ?\) c. between 112 and \(132 ?\)

A specialty foods company sells "gourmet hams" by mail order. The hams vary in size from 4.15 to 7.45 pounds, with a mean weight of 6 pounds and standard deviation of 0.65 pounds. The quartiles and median weights are \(5.6,6.2,\) and 6.55 pounds. a. Find the range and the IQR of the weights. b. Do you think the distribution of the weights is symmetric or skewed? If skewed, which way? Why? c. If these weights were expressed in ounces \((1\) pound \(=16\) ounces \()\) what would the mean, standard deviation, quartiles, median, IQR, and range be? d. When the company ships these hams, the box and packing materials add 30 ounces. What are the mean, standard deviation, quartiles, median, IQR, and range of weights of boxes shipped (in ounces)? e. One customer made a special order of a 10 -pound ham. Which of the summary statistics of part d might not change if that data value were added to the distribution?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.