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In Exercises 49 and 50 , Chapter 4 , we looked at data from an experiment to determine whether visual information about an image helped people "see" the image in \(3 D\). 2-Sample \(t\) -Interval for \(\mu 1-\mu 2\) Conf level \(=90 \%\) df \(=70\) \(\mu(\mathrm{NV})-\mu(\mathrm{VV})\) interval : (0.55,5.47) a. Interpret your interval in context. b. Does it appear that viewing a picture of the image helps people "see" the \(3 \mathrm{D}\) image in a stereogram? c. What's the margin of error for this interval? d. Explain carefully what the \(90 \%\) confidence level means. e. Would you expect a \(99 \%\) confidence interval to be wider or narrower? Explain. f. Might that change your conclusion in part b? Explain.

Short Answer

Expert verified
The interval (0.55, 5.47) denotes that with 90% confidence, using visual aids improves 'seeing' 3D images by a mean increase between 0.55 and 5.47. The margin of error is 2.46. The 90% confidence level means we expect 90 out of 100 similar experiments to yield a mean difference within this interval. A 99% confidence interval would be wider, potentially altering our previous conclusion.

Step by step solution

01

Interpret the interval

The interval (0.55, 5.47) represents the difference in means between two groups (Non-Visual and Visual viewings) with a 90% confidence level. In context, this means we can be 90% confident that people using visual aids to 'see' the image in 3D will on average see an increase in performance between 0.55 and 5.47 compared to those who don't.
02

Asses the impact of viewing a picture on 'seeing' the 3D image

Because the entire confidence interval is greater than 0 (0.55 to 5.47), it does seem like viewing a picture of the image helps people 'see' the 3D image in a stereogram.
03

Calculate the margin of error

The margin of error for this interval can be determined by taking half the length of the interval. The length is \(5.47 - 0.55 = 4.92\). So, the margin of error here is \(4.92 / 2 = 2.46\).
04

Interpret the 90% confidence level

The 90% confidence level means that if similar experiments are run 100 times, in about 90 of them the true mean difference is expected to lie within the given interval (0.55 to 5.47).
05

Expectations of a 99% confidence interval

A 99% confidence interval would be wider than a 90% one. This is because to be more confident (99% as opposed to 90%) that the true mean difference lies within the interval, the interval itself must be larger.
06

Reevaluate the conclusion

A wider interval (expected from a 99% confidence interval) might include 0, indicating that there's a possibility the visual aids may not improve the image 'seeing' performance. Hence, this could alter the earlier conclusion derived from the 90% confidence interval.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Two-Sample t-Interval
In statistics, the two-sample t-interval is a method used to compare the means of two independent groups. This approach helps determine whether there is a significant difference between the two groups. In this exercise, it was used to analyze whether visual aids help people perceive images in 3D better compared to not using such aids.
  • The observed interval (0.55, 5.47) indicates the range within which the true difference in means between the two groups resides, with a certain level of confidence, here 90%.
  • Since this interval does not include zero and is entirely positive, it suggests that visual aids effectively enhance 3D image perception.
Using two-sample t-intervals requires ensuring that the data from both groups meet the criteria of independent random samples and that the sample sizes are sufficiently large to approximate a normal distribution. Overall, this method allows researchers to make informed conclusions based on observed samples, which can be invaluable in experimental settings like the one described.
Deciphering the Margin of Error
The margin of error (MOE) is a critical statistic that quantifies the uncertainty in the estimated interval. It represents
  • the extent of variability that might affect the estimated difference between the group means.
To calculate the margin of error in this context:
  • Find the length of the confidence interval, in this case, 5.47 - 0.55 = 4.92.
  • The margin of error is half of this length, so 4.92/2 equals 2.46.
The margin of error accounts for sampling variability and provides a cushion around the estimated difference to express the level of reliability of the results. A larger margin of error reveals greater uncertainty in the results, while a smaller margin implies more precision. Understanding and calculating the MOE is crucial for correctly interpreting statistical results and communicating their reliability.
Interpreting the Confidence Level
Confidence level is a vital concept in statistics that helps determine how often you expect your estimated interval to contain the true population parameter. In this problem, a 90% confidence level was established.
  • It means that if we were to conduct this experiment multiple times, 90 out of 100 of those intervals would likely include the true difference in means.
  • This implies a 10% chance that the true difference may not lie within the given range.
Increasing the confidence level, such as adjusting to 99%, would naturally result in a wider interval. It signifies more assurance that the interval contains the true difference, but also includes a greater range of values, potentially crossing zero. It's crucial to balance the confidence level with the precision of the interval, ensuring that decisions made are statistically sound and applicable to the real-world scenario being studied.
Exploring Hypothesis Testing
Hypothesis testing is a statistical method that aids in making decisions about a population based on sample data. It's central to this exercise as it zeroes in on determining whether visual information enhances 3D image perception.
  • The null hypothesis (H0) typically suggests no effect or no difference between groups, hence \( \mu(\mathrm{NV}) - \mu(\mathrm{VV}) = 0 \).
  • The alternative hypothesis (H1) posits that there is a genuine effect, asserting that \( \mu(\mathrm{NV}) - \mu(\mathrm{VV}) eq 0 \).
If the entire confidence interval lies above zero, as in this problem, the null hypothesis can be rejected in favor of the alternative, indicating that visual aids do impact perception.A more expanded confidence interval with a 99% confidence level could potentially incorporate zero within its range. This inclusion might lead to failing to reject the null hypothesis, suggesting caution in interpreting the results as definitive. Hypothesis testing provides a structured method to test assumptions and supports making informed conclusions about the research questions at hand.

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Most popular questions from this chapter

The Consumer Reports article described in Exercise 52 ?continued their investigation of washing machines. One of the variables the article reported was "cycle time," the number of minutes it took each machine to wash a load of clothes. Among the machines rated good to excellent, the \(98 \%\) confidence interval for the difference in mean cycle time \(\left(\mu_{\text {Top }}-\mu_{\text {Front }}\right)\) is (-40,-22). a. The endpoints of this confidence interval are negative numbers. What does that indicate? b. What does the fact that the confidence interval does not contain 0 indicate? c. If we use this confidence interval to test the hypothesis that \(\mu_{\text {Top }}-\mu_{\text {Front }}=0\) what's the corresponding alpha level?

Political pundits talk about the "bounce" that a presidential candidate gets after his party's convention. In the past 40 years, it has averaged about 6 percentage points. Just before the 2004 Democratic convention, Rasmussen Reports polled 1500 likely voters at random and found that \(47 \%\) favored John Kerry. Just afterward, they took another random sample of 1500 likely voters and found that \(49 \%\) favored Kerry. That's a two percentage point increase, but the pollsters claimed that there was no bounce. Explain.

In Exercise 54 , we saw a 98\% confidence interval of (-40,-22) minutes for \(\mu_{\text {Top }}-\mu_{\text {Front }}\) the difference in time it takes top- loading and front-loading washers to do a load of clothes. Explain why you think each of the following statements is true or false: a. \(98 \%\) of top loaders are 22 to 40 minutes faster than front loaders. b. If I choose the laundromat's top loader, there's a \(98 \%\) chance that my clothes will be done faster than if I had chosen the front loader. C. If I tried more samples of both kinds of washing machines, in about \(98 \%\) of these samples l'd expect the top loaders to be an average of 22 to 40 minutes faster. d. If I tried more samples, l'd expect about \(98 \%\) of the resulting confidence intervals to include the true difference in mean cycle time for the two types of washing machines. e. I'm \(98 \%\) confident that top loaders wash clothes an average of 22 to 40 minutes faster than front-loading machines.

You are a consultant to the marketing department of a business preparing to launch an ad campaign for a new product. The company can afford to run ads during one TV show, and has decided not to sponsor a show with sexual content. You read the study described in Exercise 75 , then use a computer to create a confidence interval for the difference in mean number of brand names remembered between the groups watching violent shows and those watching neutral shows. TWO-SAMPLET \(95 \%\) CI FOR MUviol - MUneut : (-1.578,-0.602) a. At the meeting of the marketing staff, you have to explain what this output means. What will you say? b. What advice would you give the company about the upcoming ad campaign?

The Journal of the American Medical Association reported on an experiment intended to see if the drug Prozac \(^{\circledast}\) could be used as a treatment for the eating disorder anorexia nervosa. The subjects, women being treated for anorexia, were randomly divided into two groups. Of the 49 who received Prozac, 35 were deemed healthy a year later, compared to 32 of the 44 who got the placebo. a. Are the conditions for inference satisfied? b. Find a \(95 \%\) confidence interval for the difference in outcomes. c. Use your confidence interval to explain whether you think Prozac is effective.

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