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A Vermont study published by the American Academy of Pediatrics examined parental influence on teenagers' decisions to smoke. A group of students who had never smoked were questioned about their parents' attitudes toward smoking. These students were questioned again two years later to see if they had started smoking. The researchers found that, among the 284 students who indicated that their parents disapproved of kids smoking, 54 had become established smokers. Among the 41 students who initially said their parents were lenient about smoking, 11 became smokers. Do these data provide strong evidence that parental attitude influences teenagers' decisions about smoking? a. What kind of design did the researchers use? b. Write appropriate hypotheses. c. Are the assumptions and conditions necessary for inference satisfied? d. Test the hypothesis and state your conclusion. e. Explain in this context what your P-value means. \(\mathrm{f}\). If it is later found that parental attitudes actually do influence teens' decisions to smoke, which type of

Short Answer

Expert verified
The researchers used an observational study. The null hypothesis is that parental attitudes do not influence their teenagers' decision to smoke and the alternative hypothesis is that they do. Whether assumptions and conditions for inference are met need to be verified. The outcome of hypothesis test will tell whether we accept or reject the null hypothesis and the P-value will indicate the strength of the evidence. The impact of potential Type I or Type II errors must also be considered in final decision-making.

Step by step solution

01

Identify the study design

The design of this study is observational. It identifies a group of individuals and measures variables of interest without assigning treatments or intervening.
02

Formulate the hypotheses

The null hypothesis (H0) is that parental attitudes have no influence on teenagers' decisions to smoke. The alternative hypothesis (Ha) is that parental attitudes do influence teenagers' decisions to smoke.
03

Check assumptions and conditions

The data is categorical and we're comparing two proportions, so a two-proportion z-test can be used. The sample sizes are large enough that approximating the binomial distribution with the normal is reasonable, also other conditions like independence and random sampling can be assumed.
04

Perform hypothesis test and interpret results

Use a two-proportion z-test. The z score and corresponding p-value will tell us whether we should accept or reject the null hypothesis that parental attitudes have no influence on a teenager's decision to smoke. P-value is the probability of obtaining a test statistic as extreme, or more so, than what was observed, under the assumption that the null hypothesis is true.
05

Understand the meaning of P-value

If P-value is low (e.g. less than 0.05), we can reject the null hypothesis and conclude that there is strong evidence to suggest that parental attitudes do impact a teenager's decision to smoke. If the P-value is high, we fail to reject the null hypothesis and conclude that there's not enough evidence to support the claim that parental attitudes impact smoking decisions in teenagers.
06

Identify potential errors

The two types of errors possible in hypothesis testing are Type I and Type II. A Type I error occurs if we incorrectly reject the null hypothesis when it is true, while a Type II error occurs if we fail to reject the null hypothesis when it is false. Here, a Type I error would be concluding that parental attitudes influence a teenager's decision to smoke, when in reality they don't. A Type II error would be failing to identify the influence of parental attitudes when they really do have an impact.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Observational Study Design
An observational study design is one where researchers observe subjects without intervening in any way. Instead of manipulating variables or administering treatments, researchers simply record what happens naturally. This design is commonly used in medical, social science, and psychology research to gather data on real-world behavior, circumstances, and outcomes.

In the context of the Vermont study, the researchers did not attempt to modify the teenagers’ behavior or the parents' attitudes towards smoking. They simply collected information from the students on their perceptions of their parents’ attitudes and their own smoking behaviors at two different points in time. The strength of observational studies lies in their ability to reflect real-life scenarios and provide insight into correlations and associations. However, researchers must be careful, as correlation does not imply causation, and confounding factors may be present.

Improving an observational study can involve methods like ensuring randomness in sampling and considering potential confounding variables that could affect the outcomes. This helps to improve the reliability of the conclusions drawn from the observed data.
Hypothesis Testing
Hypothesis testing is a statistical method used to decide whether there is enough evidence in a sample of data to support a particular belief, known as the alternative hypothesis, about a population. The null hypothesis, denoted as H0, represents the default position or status quo, while the alternative hypothesis, denoted as Ha or H1, represents what the researcher is seeking to evidence.

In the case of the Vermont study, the null hypothesis is that parents' attitudes have no impact on teenage smoking. Conversely, the alternative hypothesis posits that parental attitudes do influence their children’s decision to smoke. Researchers use hypothesis testing to weigh the evidence in the sample data and make a decision about the overall population from which the sample was drawn.

To enhance the explanation of hypothesis testing, it's crucial to discuss factors such as the significance level (often set at 0.05), which determines the threshold for rejecting the null hypothesis, and the concept of p-values, which provide the probability of finding the observed results when the null hypothesis is true. Understanding these concepts allows for a more nuanced interpretation of the data.
Two-proportion Z-test
A two-proportion z-test is a statistical test used to determine whether two population proportions are significantly different from each other. This test is particularly useful when comparing categorical data from two separate groups to see if there’s a significant difference in proportions for a certain outcome, such as whether people from two different cities prefer different kinds of drinks.

In the given study on teenage smoking and parental influence, the two groups compared are students who reported their parents as being disapproving of smoking, versus those who didn't. To conduct this test, one must check certain conditions: each sample should be large enough for the normal approximation to apply, the samples need to be independent, and the data should be randomly sampled. If these conditions are met, as they are presumed to be in the Vermont study, the test statistic can be calculated and the corresponding p-value can be used to assess the evidence against the null hypothesis.

It's essential to explain that if the p-value is less than the predetermined significance level, such as 0.05, this suggests that there is a statistically significant difference in proportions. However, if the p-value is higher, it indicates that there's insufficient evidence to suggest a significant difference. To help students understand, it might be helpful to visualize what a two-proportion z-test is doing using probability distributions or to show the calculation of the z-score and how it relates to the p-value and the conclusions drawn.

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Most popular questions from this chapter

You are a consultant to the marketing department of a business preparing to launch an ad campaign for a new product. The company can afford to run ads during one TV show, and has decided not to sponsor a show with sexual content. You read the study described in Exercise 75 , then use a computer to create a confidence interval for the difference in mean number of brand names remembered between the groups watching violent shows and those watching neutral shows. TWO-SAMPLET \(95 \%\) CI FOR MUviol - MUneut : (-1.578,-0.602) a. At the meeting of the marketing staff, you have to explain what this output means. What will you say? b. What advice would you give the company about the upcoming ad campaign?

GfK Roper Consulting gathers information on consumer preferences around the world to help companies monitor attitudes about health, food, and healthcare products. They asked people in many different cultures how they felt about the following statement: I have a strong preference for regional or traditional products and dishes from where I come from. In a random sample of 800 respondents, 417 of 646 people who live in urban environments agreed (either completely or somewhat) with that statement, compared to 78 out of 154 people who live in rural areas. Based on this sample, is there evidence that the percentage of people agreeing with the statement about regional preferences differs between all urban and rural dwellers?

When a random sample of 935 parents were asked about rules in their homes, \(77 \%\) said they had rules about the kinds of TV shows their children could watch. Among the 790 of those parents whose teenage children had Internet access, \(85 \%\) had rules about the kinds of Internet sites their teens could visit. That looks like a difference, but can we tell? Explain why a two-sample \(z\) -test would not be appropriate here.

A man who moves to a new city sees that there are two routes he could take to work. A neighbor who has lived there a long time tells him Route A will average 5 minutes faster than Route B. The man decides to experiment. Each day, he flips a coin to determine which way to go, driving each route 20 days. He finds that Route A takes an average of 40 minutes, with standard deviation 3 minutes, and Route B takes an average of 43 minutes, with standard deviation 2 minutes. Histograms of travel times for the routes are roughly symmetric and show no outliers. a. Find a \(95 \%\) confidence interval for the difference in average commuting time for the two routes. (From technology, \(d f=33.1 .)\) b. Should the man believe the old-timer's claim that he can save an average of 5 minutes a day by always driving Route A? Explain.

The Core Plus Mathematics Project (CPMP) is an innovative approach to teaching Mathematics that engages students in group investigations and mathematical modeling. After field tests in 36 high schools over a three-year period, researchers compared the performances of CPMP students with those taught using a traditional curriculum. In one test, students had to solve applied algebra problems using calculators. Scores for 320 CPMP students were compared to those of a control group of 273 students in a traditional math program. Computer software was used to create a confidence interval for the difference in mean scores. (Journal for Research in Mathematics Education, 31, no. 3) Conf level: \(95 \%\) Variable: Mu(CPMP) - Mu(CtrI) Interval: (5.573,11.427) a. What's the margin of error for this confidence interval? b. If we had created a \(98 \% \mathrm{Cl}\), would the margin of error be larger or smaller? c. Explain what the calculated interval means in this context. d. Does this result suggest that students who learn mathematics with CPMP will have significantly higher mean scores in algebra than those in traditional programs? Explain.

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