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Researchers at the National Cancer Institute released the results of a study that investigated the effect of weed-killing herbicides on house pets. They examined 827 dogs from homes where an herbicide was used on a regular basis, diagnosing malignant lymphoma in 473 of them. Of the 130 dogs from homes where no herbicides were used, only 19 were found to have lymphoma. a. What's the standard error of the difference in the two proportions? b. Construct a \(95 \%\) confidence interval for this difference. c. State an appropriate conclusion.

Short Answer

Expert verified
After calculating the proportions for each group, the standard error of their difference can be computed. The 95% confidence interval for this difference is then calculated. Depending on whether or not this interval contains zero, a conclusion about the statistical significance of the difference in lymphoma rates in dogs from homes where herbicides are used versus not used is made.

Step by step solution

01

Calculation of proportions

Calculate the proportions of dogs with lymphoma for both groups. The proportion for the group with herbicide usage, say \(p_1\), will be \(\frac{473}{827}\). Similarly, the proportion for the group with no herbicide usage, say \(p_2\), will be \(\frac{19}{130}\).
02

Calculate the standard error of the difference in proportions

We calculate the standard error of the difference between the two proportions using the formula \[\sqrt{\frac{p_1(1 - p_1)}{n_1} + \frac{p_2(1 - p_2)}{n_2}},\] where \(n_1 = 827\) and \(n_2 = 130\) are the sizes of the groups with and without herbicide usage, respectively.
03

Calculate the 95% confidence interval

The 95% confidence interval for the difference in the two proportions is given by \[p_1 - p_2 \pm 1.96 \times SE,\] where \(SE\) is the standard error calculated in step 2.
04

Draw a conclusion

Interpret the 95% confidence interval. If zero is not within this interval, then the difference in lymphoma rates between dogs from homes where herbicides are used and those from homes where no herbicides are used is statistically significant. A discussion on the health implications of this finding can then be made.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Error Calculation
Understanding the standard error in the context of statistics is crucial for evaluating the precision of an estimate. In the problem concerning the incidence of malignant lymphoma in dogs exposed to herbicides, the standard error of the difference in the two proportions provides a measure of the variability of that difference. To calculate the standard error (SE), we use the formula:
\[SE = \sqrt{\frac{{p_1(1 - p_1)}}{{n_1}} + \frac{{p_2(1 - p_2)}}{{n_2}}}\]
where \(p_1\) and \(p_2\) are the proportions of dogs with lymphoma in the herbicide-exposed group and the non-exposed group respectively, and \(n_1\) and \(n_2\) denote the sizes of these two groups. This calculation provides insight into the variability of our proportion estimates and is a cornerstone of inferential statistics when comparing two groups.
Confidence Interval Construction
After obtaining the standard error, we can then construct a confidence interval, which is a range of values that likely contains the true difference between the population proportions. A \(95\%\) confidence interval gives us a range that we are \(95\%\) sure includes the actual difference if we were to repeat the study many times.
To build the confidence interval for the difference in proportions, we calculate it using the formula:
\[p_1 - p_2 \pm Z_{\alpha/2} \times SE\]
The \(Z_{\alpha/2}\) value is derived from the standard normal distribution (for a \(95\%\) confidence interval, it is usually 1.96). The SE here is the standard error we computed earlier. The resulting confidence interval can then serve as the basis for making statistical inferences about the impact of herbicides on the prevalence of lymphoma in pets.
Statistical Significance
Statistical significance comes into play when we want to determine whether the observed difference in proportions is due to chance or is genuinely indicative of an effect. In this case, we look at the 95% confidence interval and check if it includes zero. If zero is not within the interval, it suggests that there is a statistically significant difference between the two proportions and that the effect observed (influence of herbicides on lymphoma rates) is unlikely to have occurred by random variation alone. This concept helps researchers to draw conclusions that extend beyond the sample studied to the broader population, with a certain level of confidence.
Proportions in Statistics
Proportions are frequently used in statistics to represent the fraction of the dataset that adheres to a certain criterion. In the canine lymphoma study, proportions help quantify the extent of the condition in both the herbicide-exposed and unexposed groups. Assessing differences in proportions between two groups allows researchers to investigate potential associations or causal relationships between a factor (like herbicide exposure) and an outcome (such as lymphoma). In our study, the proportions act as a pivotal tool for understanding the potential risks associated with herbicide exposure for pets, underscoring the practical applications of proportions in real-world statistical analyses.

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