/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 The Centers for Disease Control ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The Centers for Disease Control and Prevention reported a survey of randomly selected Americans age 65 and older, which found that 411 of 1012 men and 535 of 1062 women suffered from some form of arthritis. a. Are the assumptions and conditions necessary for inference satisfied? Explain. b. Create a \(95 \%\) confidence interval for the difference in the proportions of senior men and women who have this disease. c. Interpret your interval in this context. d. Does this confidence interval suggest that arthritis is more likely to afflict women than men? Explain.

Short Answer

Expert verified
The answers depend on the calculated values for proportions and the confidence interval. Step 3 will yield the numeric answer for the interval, which can be interpreted (Step 4) and used to compare the proportions (Step 5).

Step by step solution

01

Check Assumptions

The assumptions for a two-proportion z-test include: (1) the samples must be independent, (2) the sampling method for each population is simple random sampling, and (3) the counts of successes and failures in each sample are both at least 10. Here, the samples are assumed to be independent and randomly chosen. The number of successes and failure (both men and women with and without arthritis) are all larger than 10.
02

Calculate The Proportions

Calculate the proportions of men and women who suffered from arthritis: \(p_m = \frac{411}{1012}\) for men and \(p_w = \frac{535}{1062}\) for women.
03

Compute The Confidence Interval

Now calculate the 95% confidence interval for the difference in proportions. We apply the formula for the confidence interval for the difference of two proportions: \[CI = (p_w - p_m) \pm z*SE\] where \(SE = \sqrt{(\frac{p_m(1 - p_m)}{n_m}) + (\frac{p_w(1 - p_w)}{n_w})}\) is the standard error of the difference, \(n_m\) and \(n_w\) represent the number of men and women in the samples respectively, and \(z\) corresponds to the z-value from the standard normal distribution for a 95% confidence interval, which is approximately 1.96.
04

Interpret The Interval

Depending on the confidence interval calculated, we need to interpret it in the context of the problem. If the interval does not contain 0, that means the proportions are significantly different, suggesting that men and women have different rates of arthritis.
05

Compare Proportions

To answer the question whether arthritis is more likely to afflict women than men, we need to see if the confidence interval is entirely positive. If so, it suggests that women have significantly higher rates of arthritis than men.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Two-proportion z-test
The two-proportion z-test is a statistical method used to determine if there is a significant difference between the proportions of two groups or populations. This test is especially useful when analyzing categorical data from two separate samples. The main goal here is to compare the proportions to see if they are equal or if there's a significant difference between them.

To conduct a two-proportion z-test, certain assumptions must be met:
  • The samples must be independent, meaning the selection of one sample doesn't influence the other.
  • The sampling method for each population should be simple random sampling to ensure representative samples.
  • Both samples must be large enough so that the count of successes and failures in each sample is at least 10.
In our exercise, these conditions are satisfied, allowing us to proceed with the z-test confidently.
Confidence Interval
A confidence interval provides a range of values within which we expect the true difference in proportions to fall. It is crucial because it offers a degree of certainty about our estimate. In general, a confidence interval is expressed with a percentage, such as 95%, indicating that we expect 95% of such intervals to contain the true parameter.

For the difference in proportions, the confidence interval is calculated using the formula:
\[CI = (p_w - p_m) \pm z*SE\]
where \(p_w\) and \(p_m\) are the proportions of women and men who have arthritis, respectively, \(z\) is the z-value for the desired confidence level (approximately 1.96 for 95%), and \(SE\) is the standard error of the difference between the two proportions.

By calculating the confidence interval, you can determine a range that likely contains the true difference between the two groups. This understanding helps inform decisions and interpretations, like determining if women suffer more from arthritis than men.
Difference in Proportions
The difference in proportions is a measure that helps quantify how much one group's proportion differs from another's. It's calculated simply as the proportion of interest in one group minus the proportion of interest in the other. In the context of our arthritis example, this would be \(p_w - p_m\), where \(p_w\) is the proportion of women with arthritis, and \(p_m\) is the proportion of men with arthritis.

Interpreting this difference is straightforward:
  • If the difference is positive, it suggests that more women than men have arthritis.
  • If the difference is negative, it implies more men than women have arthritis.
  • If the difference is zero or very close to zero, it indicates similar proportions.
The concept of difference in proportions is powerful as it directly points to the direction and magnitude of disparity between two populations, guiding further analysis or health interventions.
Sample Assumptions
Sample assumptions are the foundational requirements that ensure the validity of statistical tests and constructs, like the two-proportion z-test or confidence intervals. If these assumptions are violated, the results can be misleading in terms of precision and accuracy.

In our case, the critical assumptions include:
  • Independence of samples: The results from each sample (men and women) should not affect each other.
  • Random sampling: Each group should be a representative random sample to generalize findings effectively.
  • Sufficient sample size: To achieve accurate estimates, there should be at least 10 successes and 10 failures in each subgroup.
Maintaining these assumptions helps improve the reliability of the statistical conclusions drawn, like understanding whether arthritis rates significantly differ between elderly men and women.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Do people who work for non-profit organizations differ from those who work at for-profit companies when it comes to personal job satisfaction? Separate random samples were collected by a polling agency to investigate the difference. Data collected from 422 employees at non-profit organizations revealed that 377 of them were "highly satisfied." From the for-profit companies, 431 out 518 employees reported the same level of satisfaction. Find the standard error of the difference in sample proportions.

Data collected in 2015 by the Behavioral Risk Factor Surveillance System revealed that in the state of New Jersey, \(27.3 \%\) of whites and \(47.2 \%\) of blacks were cigarette smokers. Suppose these proportions were based on samples of 3607 whites and 485 blacks. a. Create a \(90 \%\) confidence interval for the difference in the percentage of smokers between black and white adults in New Jersey. b. Does this survey indicate a race-based difference in smoking among American adults? Explain, using your confidence interval to test an appropriate hypothesis. c. What alpha level did your test use?

You are a consultant to the marketing department of a business preparing to launch an ad campaign for a new product. The company can afford to run ads during one TV show, and has decided not to sponsor a show with sexual content. You read the study described in Exercise 75 , then use a computer to create a confidence interval for the difference in mean number of brand names remembered between the groups watching violent shows and those watching neutral shows. TWO-SAMPLET \(95 \%\) CI FOR MUviol - MUneut : (-1.578,-0.602) a. At the meeting of the marketing staff, you have to explain what this output means. What will you say? b. What advice would you give the company about the upcoming ad campaign?

The Journal of the American Medical Association reported a study examining the possible impact of air pollution caused by the \(9 / 11\) attack on New York's World Trade Center on the weight of babies. Researchers found that \(8 \%\) of 182 babies born to mothers who were exposed to heavy doses of soot and ash on September 11 were classified as having low birthweight. Only \(4 \%\) of 2300 babies born in another New York City hospital whose mothers had not been near the site of the disaster were similarly classified. Does this indicate a possibility that air pollution might be linked to a significantly higher proportion of low-weight babies? a. Test an appropriate hypothesis at \(\alpha=0.10\) and state your conclusion. b. If you concluded there is a difference, estimate that difference with a confidence interval and interpret that interval in context.

Researchers investigated how the size of a bowl affects how much ice cream people tend to scoop when serving themselves. \({ }^{12}\) At an "ice cream social," people were randomly given either a 17 -oz or a 34 -oz bowl (both large enough that they would not be filled to capacity). They were then invited to scoop as much ice cream as they liked. Did the bowl size change the selected portion size? Here are the summaries: 12Brian Wansink, Koert van Ittersum, and James E. Painter, "Ice Cream Illusions: Bowls, Spoons, and Self-Served Portion Sizes," Am. J. Prev. Med. 2006 . Test an appropriate hypothesis and state your conclusions. For assumptions and conditions that you cannot test, you may assume that they are sufficiently satisfied to proceed.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.