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Candy Someone hands you a box of a dozen chocolatecovered candies, telling you that half are vanilla creams and the other half peanut butter. You pick candies at random and discover the first three you eat are all vanilla. a. If there really were 6 vanilla and 6 peanut butter candies in the box, what is the probability that you would have picked three vanillas in a row? b. Do you think there really might have been 6 of each? Explain. c. Would you continue to believe that half are vanilla if the fourth one you try is also vanilla? Explain.

Short Answer

Expert verified
The probability is about 0.091 or 9 in 100 repeats of the experiment. Drawing three or even four vanilla candies in a row, doesn't necessarily imply that there are more than 6 vanilla candies in the box, but we might start to question that assumption if we continue to draw more vanilla candies.

Step by step solution

01

Calculate the probability for a single draw

Initially, there are 6 vanilla and 6 peanut butter candies, giving us a total of 12 candies. For the first draw, the probability of getting a vanilla candy is therefore \(\frac{6}{12} = 0.5\).
02

Calculate the cumulative probability

To find the probability of picking vanilla on the three draws in a row, it's necessary to multiply the probabilities of each draw. After the first candy is drawn, there are only 11 candies left, with 5 of them being vanilla. The probability of the second candy being vanilla is \(\frac{5}{11}\). The third draw has now a total of 10 candies with 4 of them being vanilla, which gives us a probability of \(\frac{4}{10}\). The cumulative probability for the three draws hence is \(\frac{6}{12} * \(\frac{5}{11} * \(\frac{4}{10} = 0.091.\)
03

Interpret the result

After calculating the probability, it's important to understand its implications. The calculated probability of 0.091 indicates that, on average, the scenario of drawing three vanillas in a row would happen about 9 out of 100 times when pulling randomly from the box. Thus, just because we drew three vanillas right now, we shouldn't assume that there are more than 6 vanilla candies. As for drawing a fourth vanilla, it can happen but it is unlikely as the probability is \(\frac{4}{10}\) or 0.4, and drawing a fourth one wouldn't necessarily mean that there are more vanilla candies, but we may start questioning the assumption.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cumulative Probability
Cumulative probability refers to the likelihood of an event or series of events occurring sequentially in specific conditions. It's akin to a chain, where each link represents an individual event and the strength of the chain (the cumulative probability) is determined by the combined strength of all links. In our exercise involving the selection of vanilla candies, calculating the cumulative probability required considering the decreasing number of candies after each draw.

It's essential to view this as a multi-stage process. After enjoying the first candy, the box now contains 11 candies with 5 vanillas. The probability for this next stage is then recalculated based on the new numbers. This step-wise reduction continues, affecting the probability of each subsequent event. Understanding this concept is crucial in a plethora of fields, from quality control to decision making under uncertainty. The principle has wide-reaching implications, whether it's forecasting weather events or analyzing the likelihood of a medical treatment leading to consecutive successful outcomes.
Probability Calculations
Probability calculations are fundamental tools used to quantify the likelihood of an event. These calculations can become complex when dealing with multiple events, especially in conditional probabilities or when the outcome of one event affects another. In our sweet dilemma with the candies, the initial probability for picking a vanilla was simple: \(\frac{6}{12} = 0.5\). However, we needed to adjust our calculations as each candy was selected.

The key to undertaking probability calculations is recognizing the evolving nature of the scenario – each draw changed the total number of candies and the vanilla count. By systematically adjusting our probability calculations after each draw, we arrived at a composite or cumulative probability that reflected the likelihood of selecting three vanillas consecutively. Performing these layered calculations, one must pay careful attention to each step to ensure an accurate overall assessment of probabilities.
Probability Interpretation
Interpreting the results of probability calculations is as important as the calculations themselves. While the numbers provide raw data, interpreting them gives us insight into the context and potential implications. From the exercise, we determined a cumulative probability of 0.091, or about 9% chance, of picking three vanilla candies consecutively. This interpretation suggests that while it is possible to pick three vanillas in a row, it is a relatively unlikely event.

The interpretation can influence our belief in the initial assumption that there are an equal number of vanilla and peanut butter candies. If such a scenario seemed more likely than calculated (for example, if we pulled three vanillas out of the box several times in a row), one might suspect that the box might actually contain more than six vanilla candies. However, the occurrence of one unlikely event does not nullify the original assumption; other supporting evidence would be needed to form a more definitive judgment. The interpretation of probability merges mathematical results with critical thinking, guiding our decisions and expectations.

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