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You are dealt a hand of three cards, one at a time. Find the probability of each of the following. a. The first heart you get is the third card dealt. b. Your cards are all red (that is, all diamonds or hearts). c. You get no spades. d. You have at least one ace.

Short Answer

Expert verified
a. The probability is \( \frac{{C^{26}_{2} * C^{13}_{1}}}{{C^{52}_{3}}} \) b. The probability is \( \frac{{C^{26}_{3}}}{{C^{52}_{3}}} \) c. The probability is \( \frac{{C^{39}_{3}}}{{C^{52}_{3}}} \) d. The probability is \( 1 - \frac{{C^{48}_{3}}}{{C^{52}_{3}}} \)

Step by step solution

01

Solution Part-a

First two cards be anything but Hearts and third card be a Heart. So, the Probability \( P(A) = \frac{{C^{26}_{2} * C^{13}_{1}}}{{C^{52}_{3}}} \) where \( C^{n}_{r} \) is the combination function, which finds the number of ways to choose r items from a total of n items.
02

Solution Part-b

All the cards drawn are red, i.e either they are Hearts or Diamonds. So, the Probability \( P(B) = \frac{{C^{26}_{3}}}{{C^{52}_{3}}} \).
03

Solution Part-c

The drawn cards are anything but Spades. So, only Hearts, Diamonds, and Clubs are allowed. So, the Probability \( P(C) = \frac{{C^{39}_{3}}}{{C^{52}_{3}}} \).
04

Solution Part-d

We calculate probability of getting no Aces and subtract it from 1. No Aces means cards can be drawn from the remaining 48 cards. So, the Probability \( P(D) = 1 - \frac{{C^{48}_{3}}}{{C^{52}_{3}}} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combination Function
Understanding the combination function, also known as 'combinations' or 'binomial coefficients', is crucial when calculating probabilities in card games. This mathematical concept is represented by the notation \( C^{n}_{r} \), where \( n \) is the total number of items, and \( r \) is the number of items to choose. It tells us how many ways we can select \( r \) items from a larger set of \( n \) items without considering the order.

For example, if a deck of cards has 52 cards and we want to know how many ways we can select 3 cards from it, we'd use the combination function to calculate \( C^{52}_{3} \). This mathematical operation avoids duplication that would occur if we considered different orders of the same cards as separate outcomes, which is not relevant in most card games since a hand of '2♥, 5♠, 10♦' is the same as '5♠, 2♥, 10♦'.
Conditional Probability
Conditional probability is a measure of the probability of an event occurring given that another event has already occurred. In card games, this often comes into play when we draw cards sequentially without replacement. For instance, if we want to know the probability that the third card we draw is a heart, given that the first two were not hearts, we apply conditional probability.

When calculating conditional probabilities, it's important to update our perspective of the situation after each event. In the example from the exercise where the first heart appears as the third card, our initial probability calculation would ignore hearts as possible outcomes for the first two cards. This changes the sample space (the set of all possible outcomes) for each subsequent draw, thus altering the probability of future events.
Non-Replacement Probability
In the context of card games, non-replacement probability refers to the likelihood of drawing certain cards given that previously drawn cards are not returned to the deck. Essentially, we're considering a shrinking sample space because the deck's composition changes with each draw.

When we calculate the probability of drawing cards from a deck without replacement, we must adjust for the number of cards remaining in the deck. For example, if you are trying to draw a heart and you know that hearts haven't been drawn in the previous picks, the probability of picking a heart increases with each draw because there are fewer cards left from which to choose. This is different from drawing with replacement, where the deck's composition remains unchanged after each draw.
Combinatorics
Combinatorics is the branch of mathematics dealing with counting, both as a means and an end in obtaining results, and certain properties of finite structures. It is the foundation of combinatorial probability, which includes problems of selecting, arranging, and counting — all of which are important in understanding outcomes in card games.

In our card game problems, we use combinatorics to figure out all the possible combinations of draws from the deck. For example, calculating the number of ways we can receive no spades or at least one ace involves using combinatorial principles to determine the total number of satisfactory combinations of cards compared to the total possible combinations. This is the heart of solving probability problems in games of chance.

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