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Give a two-way table and specify a particular cell for that table. In each case find the expected count for that cell and the contribution to the chi- square statistic for that cell. (Group 3. Yes) cell $$ \begin{array}{l|rr|r} \hline & \text { Yes } & \text { No } & \text { Total } \\ \hline \text { Group 1 } & 56 & 44 & 100 \\ \text { Group 2 } & 132 & 68 & 200 \\ \text { Group 3 } & 72 & 28 & 100 \\ \hline \text { Total } & 260 & 140 & 400 \\ \hline \end{array} $$

Short Answer

Expert verified
The expected count for the cell 'Group 3, Yes' is 65 and the contribution of this cell to the Chi-square statistic is 0.74.

Step by step solution

01

Calculate the Expected Count

The expected count for a cell in a contingency table is calculated by taking the product of the sum of rows and sum of columns for that cell, divided by the total sum. Hence, for Group 3, Yes cell, the Expected count \(E_{ij}\) is calculated as: \[E_{ij} = \left(\frac{{\text{Sum of row 3} * \text{Sum of 'Yes' column}}}{\text{Total}}\right)\] \[E_{ij} = \left(\frac{{100 * 260}}{400}\right) = 65\]
02

Calculate the Contribution to the Chi-square Statistic

The contribution to the Chi-square statistic for a particular cell is given by: \[X^2_{ij} = \frac{{(O_{ij} - E_{ij})^2}}{E_{ij}}\] where \(O_{ij}\) is the observed count (actual value from the table). Thus, for the Group 3, Yes cell, the Chi-square contribution \(X^2_{ij}\) is: \[X^2_{ij} = \frac{{(72 - 65)^2}}{65} = 0.74\]
03

Interpret the Results

The expected count for the cell corresponding to Group 3, Yes is 65. This is the count that we would expect if there was no association between the group and the response. The Chi-square contribution from this cell is 0.74. This value contributes to the total Chi-square statistic, which helps evaluate if there is a significant association between the variables in the table. If the Chi-square statistic is large, it means the observed counts deviate significantly from the expected counts, implying a potential association.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chi-square Test
The Chi-square test is a popular method used in statistics to determine if there is a significant association between two categorical variables. It is often used with contingency tables, which are tables that help display the frequency distribution of the variables. When you calculate the Chi-square statistic, you’re essentially comparing the observed frequencies with the frequencies that would be expected if there was no association between the variables.

To perform a Chi-square test, the formula used is:\[X^2 = \sum \frac{(O_{ij} - E_{ij})^2}{E_{ij}}\]Here:
  • \(O_{ij}\) is the observed frequency of the cells.
  • \(E_{ij}\) is the expected frequency if the variables are independent.

Each cell in your contingency table contributes to the Chi-square statistic, and when you sum up these contributions, you get the overall Chi-square value. This value is compared against a critical value from the Chi-square distribution table, given the degrees of freedom, to decide if the association between variables is statistically significant.
Expected Count
The expected count is a fundamental concept when performing a Chi-square test. It represents the frequency you would expect in each cell of a contingency table if the two variables were completely independent. Calculating the expected count involves taking into account both the row and column totals and the grand total of the table.

For any cell in the contingency table, the expected count \(E_{ij}\) is computed as:\[E_{ij} = \left(\frac{{\text{(Sum of relevant row)} \times \text{(Sum of relevant column)}}}{\text{Total number of observations}}\right)\]The formula helps distribute the total frequency across each cell evenly, assuming no relationship between the variables.

For example, in a two-way table, if you're looking at the `Group 3, Yes` cell, and you find the expected count to be 65, this is the value you'd expect if your variables (group and response) do not influence each other. This knowledge helps in understanding discrepancies between what is observed and what would be expected if everything were random.
Statistical Association
Statistical association refers to a relationship or dependency between two or more variables, often examined in studies to find meaningful patterns or links. In the context of a contingency table, determining statistical association often involves the use of the Chi-square test.

If variables are associated, the observed frequencies in the contingency table won’t match the expected frequencies calculated under the assumption of no association. Identifying association is crucial because it helps to draw conclusions about potential relationships or interactions between different groups or categories within the dataset.

When examining the Chi-square statistic and its corresponding p-value, researchers determine whether deviations from the expected counts are due to random chance or if there is indeed a significant association. A low p-value could suggest a strong association, while a high p-value might indicate that any observed association could simply be due to random fluctuations in the data.
  • A large overall Chi-square statistic suggests a strong association.
  • A small overall Chi-square statistic suggests weak or no association.
In essence, statistical association provides insight into how certain factors might influence each other, opening doors to further research and understanding of the phenomena.

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Most popular questions from this chapter

Treatment for Cocaine Addiction Cocaine addiction is very hard to break. Even among addicts trying hard to break the addiction, relapse is common. (A relapse is when a person trying to break out of the addiction fails and uses cocaine again.) Data 4.7 on page 323 introduces a study investigating the effectiveness of two drugs, desipramine and lithium, in the treatment of cocaine addiction. The subjects in the six-week study were cocaine addicts seeking treatment. The 72 subjects were randomly assigned to one of three groups (desipramine, lithium, or a placebo, with 24 subjects in each group) and the study was double-blind. In Example 4.34 we test lithium vs placebo, and in Exercise 4.181 we test desipramine vs placebo. Now we are able to consider all three groups together and test whether relapse rate differs by drug. Ten of the subjects taking desipramine relapsed, 18 of those taking lithium relapsed, and 20 of those taking the placebo relapsed. (a) Create a two-way table of the data. (b) Find the expected counts. Is it appropriate to analyze the data with a chi-square test? (c) If it is appropriate to use a chi-square test, complete the test. Include hypotheses, and give the chi-square statistic, the p-value, and an informative conclusion. (d) If the results are significant, which drug is most effective? Can we conclude that the choice of treatment drug causes a change in the likelihood of a relapse?

Give a two-way table and specify a particular cell for that table. In each case find the expected count for that cell and the contribution to the chi- square statistic for that cell. \((\) Group \(2,\) No \()\) $$ \begin{array}{l|rr} \hline & \text { Yes } & \text { No } \\ \hline \text { Group 1 } & 720 & 280 \\ \text { Group 2 } & 1180 & 320 \\ \hline \end{array} $$

Exercises 7.9 to 7.12 give a null hypothesis for a goodness-of-fit test and a frequency table from a sample. For each table, find: (a) The expected count for the category labeled B. (b) The contribution to the sum of the chi-square statistic for the category labeled \(\mathrm{B}\). (c) The degrees of freedom for the chi-square distribution for that table. $$ \begin{aligned} &H_{0}: p_{a}=p_{b}=p_{c}=p_{d}=0.25\\\ &H_{a}:\\\ &\text { Some } p_{i} \neq 0.25\\\ &\begin{array}{lccc|c} \hline \text { A } & \text { B } & \text { C } & \text { D } & \text { Total } \\\ \text { 40 } & 36 & 49 & 35 & 160 \\ \hline \end{array} \end{aligned} $$

Handedness and Occupation Is the career someone chooses associated with being left- or right-handed? In one study \(^{20}\) a sample of Americans from a variety of professions were asked if they consider themselves left-handed, right-handed, or ambidextrous (equally skilled with the left and right hand). The results for five professions are shown in Table \(7.33 .\) (a) In this sample, what profession had the greatest proportion of left-handed people? What profession had the greatest proportion of right-handed people? (b) Test for an association between handedness and career for these five professions. State the null and alternative hypotheses, calculate the test statistic, and find the p-value. (c) What do you conclude at the \(5 \%\) significance level? What do you conclude at the \(1 \%\) significance level? $$ \begin{array}{l|rrr|r} \hline & \text { Right } & \text { Left } & \text { Ambidextrous } & \text { Total } \\ \hline \text { Psychiatrist } & 101 & 10 & 7 & 118 \\ \text { Architect } & 115 & 26 & 7 & 148 \\ \text { Orthopedic surgeon } & 121 & 5 & 6 & 132 \\ \text { Lawyer } & 83 & 16 & 6 & 105 \\ \text { Dentist } & 116 & 10 & 6 & 132 \\ \hline \text { Total } & 536 & 67 & 32 & 635 \\ \hline \end{array} $$

In Exercises 7.1 to \(7.4,\) find the expected counts in each category using the given sample size and null hypothesis. $$ \begin{aligned} &\text { 7.4 } H_{0}: p_{1}=0.7, p_{2}=0.1, p_{3}=0.1, p_{4}=0.1 ;\\\ &n=400 \end{aligned} $$

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