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In Exercises 7.1 to \(7.4,\) find the expected counts in each category using the given sample size and null hypothesis. $$ \begin{aligned} &\text { 7.4 } H_{0}: p_{1}=0.7, p_{2}=0.1, p_{3}=0.1, p_{4}=0.1 ;\\\ &n=400 \end{aligned} $$

Short Answer

Expert verified
The expected counts for the categories are: \(E_1=280\), \(E_2= 40\), \(E_3= 40\) and \(E_4= 40\).

Step by step solution

01

Understand the proportions given for each category

The null hypothesis \(H_{0}\) states that the proportions of categories are \(p_{1} = 0.7,\) \(p_{2} = 0.1,\) \(p_{3} = 0.1,\) and \(p_{4} = 0.1.\)
02

Calculate expected counts for each category

The expected counts, denoted as \(E\), for each category can be calculated using the formula \(E = np\), where \(n\) is the total sample size and \(p\) is the hypothesised proportion for the category. So, the expected counts for each category are: \[E_{1} = np_{1} = 400*0.7 = 280\] \[E_{2} = np_{2} = 400*0.1 = 40\] \[E_{3} = np_{3} = 400*0.1 = 40\] \[E_{4} = np_{4} = 400*0.1 = 40\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Expected Counts
Expected counts are a fundamental part of the Chi-Square Test, a statistical method used to determine whether there is a significant difference between the observed and expected frequencies in categories. When conducting a Chi-Square Test, the expected counts for each category are calculated based on the null hypothesis, which provides the hypothesized proportions.
  • The expected count of a category is the number calculated by multiplying the hypothesized proportion of that category by the total sample size.
  • Using the formula: \( E = np \), where \( E \) is the expected count, \( n \) is the sample size, and \( p \) is the proportion.
In the given exercise, the expected counts are computed for a sample size of 400 across four categories with proportions of 0.7, 0.1, 0.1, and 0.1. Each expected count indicates how many observations are expected for each category if the null hypothesis holds true. Calculating these allows researchers to compare against actual observations and determine if deviations are due to chance or indicate a significant difference.
Null Hypothesis
The null hypothesis is a foundational concept in hypothesis testing. It represents a statement about a population parameter meant to be tested and potentially rejected based on sample data. In the context of a Chi-Square Test, the null hypothesis specifies the expected proportions of different categories.
For example, in the provided exercise, the null hypothesis \( H_0 : p_1 = 0.7, p_2 = 0.1, p_3 = 0.1, p_4 = 0.1 \) suggests that these are the true proportions of the population. Here's why the null hypothesis is crucial:
  • It creates a baseline model for your data which you aim to support or refute through testing.
  • A significant result would suggest that the proportions differ from those specified by \( H_0 \), indicating a likely falsehood.
The null hypothesis is never accepted; it's either rejected or not rejected based on the data. In hypothesis testing like Chi-Square, the process involves comparing expected counts with observed counts to see if any real difference exists.
Sample Size
Sample size is a critical component in statistical testing that affects the reliability of your results. It's the number of observations or data points you collect from your larger population and use in your analysis. In the Chi-Square Test, as shown in the problem with a sample size of 400, the sample size is used to calculate expected counts. Here's why it matters:
  • Larger sample sizes tend to create more accurate and reliable estimates of the population parameters.
  • They provide greater power to detect significant differences between observed and expected frequencies.
  • Small sample sizes might lead to misleading results due to increased variability and less precise estimates.
Thus, having a sample size of 400 allows for reasonably accurate calculations of expected counts and a more credible result in hypothesis testing. It's necessary to have a sample size large enough to ensure the test's assumptions are met, particularly the condition that expected counts should ideally be 5 or more in each category to maintain validity.

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Most popular questions from this chapter

Examining Genetic Alleles in Fast-Twitch Muscles Exercise 7.24 discusses a study investigating the \(A C T N 3\) genotypes \(R R, R X,\) and \(X X .\) The same study also examines the \(A C T N 3\) genetic alleles \(R\) and \(X,\) also associated with fast-twitch muscles. Of the 436 people in this sample, 244 were classified \(R\) and 192 were classified \(X .\) Does the sample provide evidence that the two options are not equally likely? (a) Conduct the test using a chi-square goodnessof-fit test. Include all details of the test. (b) Conduct the test using a test for a proportion, using \(H_{0}: p=0.5\) where \(p\) represents the proportion of the population classified \(R .\) Include all details of the test. (c) Compare the p-values and conclusions of the two methods.

7.53 Testing Genetic Alleles for Fast-Twitch Muscles The study on genetics and fast-twitch muscles includes a sample of elite sprinters, a sample of elite endurance athletes, and a control group of nonathletes. Is there an association between genetic allele classification \((R\) or \(X)\) and group (sprinter, endurance, control)? Computer output is shown for this chi-square test. In each cell, the top number is the observed count, the middle number is the expected count, and the bottom number is the contribution to the chi- square statistic. \(\begin{array}{lrrr} & \text { R } & \text { X } & \text { Total } \\ \text { Control } & 244 & 192 & 436 \\ & 251.42 & 184.58 & \\ & 0.219 & 0.299 & \\\ \text { Sprint } & 77 & 30 & 107 \\ & 61.70 & 45.30 & \\ & 3.792 & 5.166 & \\\ \text { Endurance } & 104 & 90 & 194 \\ & 111.87 & 82.13 & \\ & 0.554 & 0.755 & \\ \text { Total } & 425 & 312 & 737\end{array}\) \(\mathrm{Ch} \mathrm{i}-\mathrm{Sq}=10.785, \mathrm{DF}=2, \mathrm{P}\) -Value \(=0.005\) (a) How many endurance athletes were included in the study? (b) What is the expected count for sprinters with the \(R\) allele? For this cell, what is the contribution to the chi-square statistic? Verify both values by computing them yourself. (c) What are the degrees of freedom for the test? Verify this value by computing it yourself. (d) What is the chi-square test statistic? What is the p-value? What is the conclusion of the test? (e) Which cell contributes the most to the chisquare statistic? For this cell, is the observed count greater than or less than the expected count? (f) Which allele is most over-represented in sprinters? Which allele is most over-represented in endurance athletes?

In Exercises 7.1 to \(7.4,\) find the expected counts in each category using the given sample size and null hypothesis. $$ H_{0}: p_{1}=p_{2}=p_{3}=p_{4}=0.25 ; \quad n=500 $$

Can People Delay Death? A study indicates that elderly people are able to postpone death for a short time to reach an important occasion. The researchers \({ }^{10}\) studied deaths from natural causes among 1200 elderly people of Chinese descent in California during six months before and after the Harbor Moon Festival. Thirty-three deaths occurred in the week before the Chinese festival, compared with an estimated 50.82 deaths expected in that period. In the week following the festival, 70 deaths occurred, compared with an estimated 52. "The numbers are so significant that it would be unlikely to occur by chance," said one of the researchers. (a) Given the information in the problem, is the \(\chi^{2}\) statistic likely to be relatively large or relatively small? (b) Is the p-value likely to be relatively large or relatively small? (c) In the week before the festival, which is higher: the observed count or the expected count? What does this tell us about the ability of elderly people to delay death? (d) What is the contribution to the \(\chi^{2}\) -statistic for the week before the festival? (e) In the week after the festival, which is higher: the observed count or the expected count? What does this tell us about the ability of elderly people to delay death? (f) What is the contribution to the \(\chi^{2}\) -statistic for the week after the festival? (g) The researchers tell us that in a control group of elderly people in California who are not of Chinese descent, the same effect was not seen. Why did the researchers also include a control group?

Age and Frequency of Status Updates on Facebook Exercise 7.48 introduces a study about users of social networking sites such as Facebook. Table 7.35 shows the self-reported frequency of status updates on Facebook by age groups. (a) Based on the totals, if age and frequency of status updates are really unrelated, how many of the 156 users who are 18 to 22 years olds should we expect to update their status every day? (b) Since there are 20 cells in this table, we'll save some time and tell you that the chi-square statistic for this table is \(210.9 .\) What should we conclude about a relationship (if any) between age and frequency of status updates? $$ \begin{array}{l|rrrr|r} \hline \downarrow \text { Status/Age } \rightarrow & 18-22 & 23-35 & 36-49 & 50+ & \text { Total } \\ \hline \text { Every day } & 47 & 59 & 23 & 7 & 136 \\ \text { 3-5 days/week } & 33 & 47 & 30 & 7 & 117 \\ \text { 1-2 days/week } & 32 & 69 & 35 & 25 & 161 \\ \text { Every few weeks } & 23 & 65 & 47 & 34 & 169 \\ \text { Less often } & 21 & 74 & 99 & 170 & 364 \\ \hline \text { Total } & 156 & 314 & 234 & 243 & 947 \\ \hline \end{array} $$

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