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91Ó°ÊÓ

If random samples of the given size are drawn from a population with the given mean and standard deviation, find the standard error of the distribution of sample means. Samples of size 10 from a population with mean 6 and standard deviation 2

Short Answer

Expert verified
The standard error of the distribution of sample means is \(\sqrt{10}\) or approximately 0.63.

Step by step solution

01

Identify given values

From the problem, identify the given values. Here, the mean (μ) is 6, the standard deviation (σ) is 2, and the sample size (n) is 10.
02

Apply the formula for the standard error

Use the standard error formula which is SE = σ/√n. Substitute σ = 2 and n = 10 into the equation to calculate SE.
03

Calculation

Calculate the value by substituting the numbers into the formula. Using standard error formula SE = 2/√10. Perform the division to get the standard error value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Sample Means
When we talk about sample means, we refer to the average value of a set of data gathered from a subset of a larger population. It provides us with an estimate of the population mean without requiring us to assess every individual within the entire population. In practice, researchers often take multiple samples and calculate a mean for each, resulting in a distribution of sample means. This distribution is expected to form a normal shape, especially with larger sample sizes, due to the Central Limit Theorem.

The mean of the distribution of sample means will be the same as the population mean, and the dispersion of this distribution can be quantified using the standard error, which we shall discuss in the next sections. In our exercise, we consider the average of a certain characteristic within a sample of 10 observations derived from a broader population.
The Role of Standard Deviation
Standard deviation is a statistical measurement that describes the amount of dispersion or variation in a set of values. A low standard deviation means that the values tend to be close to the mean of the set, while a high standard deviation means that the values are spread out over a wider range. In the context of our exercise, the population from which samples are drawn has a standard deviation of 2. This number is crucial as it is directly used to calculate the standard error of the sample means. Understanding standard deviation helps to interpret data by indicating how much individual observations deviate from the average value. For instance, in a scenario where exam scores have a high standard deviation, students' performance varies greatly; while a low standard deviation suggests most students' scores were close to the average.
Population Mean Significance
The population mean, often denoted by the Greek letter \( \mu \), is simply the average of all measurements in the entire population. It is a summary measure that tells us the central tendency of the population data. In research or practical applications, it's often impossible or impractical to measure every individual in a population, which is why samples are used.

The population mean is used as a reference point when we are looking at sample means. In our exercise, the given population mean is 6. This value becomes the benchmark for comparing our sample means and evaluating whether our samples are accurately representing the population.
Sample Size and Its Effects
Sample size, denoted as \( n \) in statistical formulas, represents the number of observations or measurements in a sample taken from the population. The sample size is a significant factor in determining the reliability of estimated statistics like the mean and has a direct relationship with the standard error. Generally, larger sample sizes yield more reliable estimates and result in smaller standard errors, indicating that the sample means are more likely to be close to the population mean.

In the scenario provided by the exercise, a sample size of 10 is used. According to the formula for standard error, as the sample size increases, the standard error decreases, suggesting that if we were to increase the sample size from 10 to a larger number, our standard error will become smaller, implying that our estimates will be more precise.

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Most popular questions from this chapter

In Exercises 6.203 and \(6.204,\) use Stat Key or other technology to generate a bootstrap distribution of sample differences in means and find the standard error for that distribution. Compare the result to the standard error given by the Central Limit Theorem, using the sample standard deviations as estimates of the population standard deviations. Difference in mean commuting time (in minutes) between commuters in Atlanta and commuters in St. Louis, using \(n_{1}=500, \bar{x}_{1}=29.11,\) and \(s_{1}=20.72\) for Atlanta and \(n_{2}=500, \bar{x}_{2}=21.97,\) and \(s_{2}=14.23\) for St. Louis

Use a t-distribution to find a confidence interval for the difference in means \(\mu_{1}-\mu_{2}\) using the relevant sample results from paired data. Give the best estimate for \(\mu_{1}-\) \(\mu_{2},\) the margin of error, and the confidence interval. Assume the results come from random samples from populations that are approximately normally distributed, and that differences are computed using \(d=x_{1}-x_{2}\) A \(99 \%\) confidence interval for \(\mu_{1}-\mu_{2}\) using the paired data in the following table:. $$ \begin{array}{lccccc} \hline \text { Case } & \mathbf{1} & \mathbf{2} & \mathbf{3} & \mathbf{4} & \mathbf{5} \\ \hline \text { Treatment 1 } & 22 & 28 & 31 & 25 & 28 \\ \text { Treatment 2 } & 18 & 30 & 25 & 21 & 21 \\ \hline \end{array} $$

(a) Find the relevant sample proportions in each group and the pooled proportion. (b) Complete the hypothesis test using the normal distribution and show all details. Test whether males are less likely than females to support a ballot initiative, if \(24 \%\) of a random sample of 50 males plan to vote yes on the initiative and \(32 \%\) of a random sample of 50 females plan to vote yes.

The dataset ICUAdmissions, introduced in Data 2.3 on page \(69,\) includes information on 200 patients admitted to an Intensive Care Unit. One of the variables, Status, indicates whether each patient lived (indicated with a 0 ) or died (indicated with a 1 ). Use technology and the dataset to construct and interpret a \(95 \%\) confidence interval for the proportion of ICU patients who live.

Who Exercises More: Males or Females? The dataset StudentSurvey has information from males and females on the number of hours spent exercising in a typical week. Computer output of descriptive statistics for the number of hours spent exercising, broken down by gender, is given: \(\begin{array}{l}\text { Descriptive Statistics: Exercise } \\ \text { Variable } & \text { Gender } & \mathrm{N} & \text { Mean } & \text { StDev } \\\ \text { Exercise } & \mathrm{F} & 168 & 8.110 & 5.199 \\ & \mathrm{M} & 193 & 9.876 & 6.069\end{array}\) \(\begin{array}{rrrrr}\text { Minimum } & \text { Q1 } & \text { Median } & \text { Q3 } & \text { Maximum } \\ 0.000 & 4.000 & 7.000 & 12.000 & 27.000 \\\ 0.000 & 5.000 & 10.000 & 14.000 & 40.000\end{array}\) (a) How many females are in the dataset? How many males? (b) In the sample, which group exercises more, on average? By how much? (c) Use the summary statistics to compute a \(95 \%\) confidence interval for the difference in mean number of hours spent exercising. Be sure to define any parameters you are estimating. (d) Compare the answer from part (c) to the confidence interval given in the following computer output for the same data: Two-sample \(\mathrm{T}\) for Exercise Gender N Mean StDev SE Mean \(\begin{array}{lllll}\mathrm{F} & 168 & 8.11 & 5.20 & 0.40 \\ \mathrm{M} & 193 & 9.88 & 6.07 & 0.44\end{array}\) Difference \(=\operatorname{mu}(F)-\operatorname{mu}(M)\) Estimate for difference: -1.766 \(95 \%\) Cl for difference: (-2.932,-0.599)

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