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In Exercises 6.139 to \(6.142,\) use the normal distribution to find a confidence interval for a difference in proportions \(p_{1}-p_{2}\) given the relevant sample results. Give the best estimate for \(p_{1}-p_{2},\) the margin of error, and the confidence interval. Assume the results come from random samples. A \(95 \%\) confidence interval for \(p_{1}-p_{2}\) given that \(\hat{p}_{1}=0.72\) with \(n_{1}=500\) and \(\hat{p}_{2}=0.68\) with \(n_{2}=300 .\)

Short Answer

Expert verified
The best estimate for the difference in proportions is 0.04, the standard error is the obtained SE value, and the margin of error is calculated as the z-value (1.96 for 95% confidence) times the standard error. The confidence interval for a difference in proportions is calculated as \(0.04 \pm ME\).

Step by step solution

01

Calculating Sample Proportions

First, you need to calculate the sample proportions \(\hat{p}_{1}\) and \(\hat{p}_{2}\) if not given. They can be calculated as the number of success out of the total number of trials. For this question we have, \(\hat{p}_{1}=0.72\) and \(\hat{p}_{2}=0.68\) which means that out of all trials 72% and 68% were successful respectively.
02

Calculating Best Estimate for Difference in Proportions

The best estimate for the difference in proportions \(p_{1}-p_{2}\) is the difference of the observed/sampled proportions \(\hat{p}_{1}-\hat{p}_{2}\). For this question, the best estimate for the difference in proportions would be calculated as \(0.72 - 0.68 = 0.04\)
03

Calculate the Standard Error

The standard error of the difference in two proportions is calculated using the formula:\( SE = \sqrt{\hat{p}_{1} (1-\hat{p}_{1})/n_{1}+\hat{p}_{2} (1-\hat{p}_{2})/n_{2}}.\) In this case, substituting the relevant values we get:\(SE = \sqrt{0.72*(1-0.72)/500 + 0.68*(1-0.68)/300}\)
04

Calculating Margin of Error

The margin of error for the difference of proportions can be calculated as \(\text{ME} = z * SE,\) where \(z\) is the z-value corresponding to the given level of confidence (for 95%, it is approximately 1.96). \(\text{So ME} = 1.96 * SE\)
05

Calculating Confidence Interval

Finally, the confidence interval for the difference of sample proportions can be calculated using the formula: \(\hat{p}_{1} - \hat{p}_{2} \pm z * SE\). So the confidence interval = \(0.04 \pm ME\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
The concept of normal distribution is fundamental in statistics and plays a key role in calculating confidence intervals. A normal distribution is a symmetric, bell-shaped curve where most of the observations cluster around the central peak. The totals at either extreme taper off equally. This distribution is essential because it describes how data values are dispersed. Normal distribution is characterized by two parameters: the mean (average) and the standard deviation (a measure of the spread). When we draw samples and calculate statistics like proportions or means, they form a pattern resembling a normal distribution, especially when the sample size is large enough due to the Central Limit Theorem.
  • Mean: The average value which the data points approach as a whole.
  • Standard Deviation: Indicates the variability or spread of the dataset.
In our context, the normal distribution aids us in finding the Z-score, which helps in determining the margin of error for a confidence interval. For a 95% confidence level, the Z-score used is approximately 1.96.
Difference in Proportions
When comparing two groups, we often want to see how their proportions differ. A difference in proportions is simply the difference between the percentage of two different groups that share a particular characteristic. In the example of the exercise, we have two proportions:
  • \(\hat{p}_{1} = 0.72\), representing the proportion in group 1.
  • \(\hat{p}_{2} = 0.68\), representing the proportion in group 2.
To find the difference in proportions, we subtract one proportion from the other: \[\hat{p}_{1} - \hat{p}_{2} = 0.72 - 0.68 = 0.04\]This difference tells us that, in the sample, group 1 has a 4% higher proportion than group 2. When calculating the confidence interval, this difference is our best estimate of the difference in the population proportions. Over larger samples, our estimate gets closer to the true difference.
Standard Error
The standard error is a crucial statistical tool that measures the accuracy with which a sample-based statistic (like a difference in proportions) approximates a population parameter. Essentially, it tells us how close our sample statistic is likely to be to the true population value.In this context, the standard error for a difference in proportions is calculated as:\[SE = \sqrt{\frac{\hat{p}_{1}(1 - \hat{p}_{1})}{n_{1}} + \frac{\hat{p}_{2}(1 - \hat{p}_{2})}{n_{2}}}\]Here, \(\hat{p}_{1}\) and \(\hat{p}_{2}\) are the sample proportions, and \(n_{1}\) and \(n_{2}\) are the respective sample sizes. The standard error reflects how much our sample results may vary from the actual population difference due to random sampling errors. By plugging in the numbers from our exercise:\[SE = \sqrt{\frac{0.72(1 - 0.72)}{500} + \frac{0.68(1 - 0.68)}{300}} \]A smaller standard error indicates a more precise estimate of the population proportion difference, making our confidence intervals narrower and more reliable.

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Most popular questions from this chapter

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