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91Ó°ÊÓ

If random samples of the given sizes are drawn from populations with the given proportions: (a) Find the standard error of the distribution of differences in sample proportions, \(\hat{p}_{A}-\hat{p}_{B}\) (b) Determine whether the sample sizes are large enough for the Central Limit Theorem to apply. Samples of size 500 from population \(A\) with proportion 0.58 and samples of size 200 from population \(B\) with proportion 0.49

Short Answer

Expert verified
The standard error of the distribution of differences in sample proportions, \(\hat{p}_{A}-\hat{p}_{B}\), is approximately 0.050. The sample sizes are large enough for the Central Limit Theorem to apply.

Step by step solution

01

Calculate Standard Error

First, plug the given population proportions (0.58 and 0.49) and sample sizes (500 and 200) into the formula for the standard error of the distribution of differences in sample proportions. As such, this would result in \(\sqrt{[(0.58)(1 - 0.58) / 500] + [(0.49)(1 - 0.49) / 200]}\). Calculate this expression to find the standard error.
02

Determine the Central Limit Theorem Applicability

To find if the Central Limit Theorem applies, check if both \(500 * 0.58 * (1 - 0.58) \geq 10\) and \(200 * 0.49 * (1 - 0.49) \geq 10\). If both of these inequalities hold true, then the sample sizes are large enough for the Central Limit Theorem to apply.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Error
The standard error is an essential concept in statistics, as it measures the variability of a sample statistic from the population parameter. For instance, when we're estimating a population proportion from a sample, the standard error gives us an idea of how much the sample proportion might deviate from the actual population proportion.

The formula for the standard error of a proportion \(SE(\hat{p})\) is given by the square root of \(\frac{p(1-p)}{n}\), where \(p\) is the population proportion and \(n\) is the sample size. However, when comparing two sample proportions, such as \(\hat{p}_A\) and \(\hat{p}_B\), we use a modified formula:
\[SE(\hat{p}_A - \hat{p}_B) = \sqrt{\frac{p_A(1-p_A)}{n_A} + \frac{p_B(1-p_B)}{n_B}}\]

In our exercise, we have two different populations with their given proportions: 0.58 for population A and 0.49 for population B. The idea is to calculate the standard error of the difference between these two sample proportions, thus helping us understand how reliable our comparison might be.
Sample Proportion
The sample proportion, denoted as \(\hat{p}\), is a critical concept used in statistical analysis. It represents the proportion of a certain characteristic or attribute within a sample of the population. It's calculated by dividing the number of individuals in the sample with the attribute of interest by the total number of individuals in the sample.

Mathematically, it can be expressed as:
\[\hat{p} = \frac{x}{n}\]

Where \(x\) represents the number of successes (or observations with the attribute of interest), and \(n\) is the total number of observations in the sample. In this exercise, when we take a sample of size 500 from population A where the proportion is 0.58, the sample proportion will closely reflect this value if the sample is representative. Similarly, for population B with a proportion of 0.49 and a sample size of 200, the sample proportion provides an estimate of the actual proportion in the population.

The accuracy of the sample proportion as an estimate of the population proportion largely depends on the size of the sample and the variance of the population.
Population Proportion
Population proportion is a fundamental concept in statistics, as it gives us a measure of a particular characteristic over the entire population. This proportion is denoted by the symbol \(p\). For example, if you have a large population and you want to know the proportion of individuals with a specific trait, the population proportion is the key figure you need.

In our exercise, population A has a proportion of 0.58, and population B has 0.49. These values indicate that 58% of population A, and 49% of population B exhibit the characteristic we're interested in.
  • This proportion helps in determining how representative a sample is to its population.
  • A larger population proportion generally requires larger sample sizes for accurate estimation.
  • It is foundational for calculating other statistics like the sample proportion and standard error.
Understanding the population proportion is crucial for conducting large-scale studies or surveys and making predictions about population characteristics based on sample data.

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Most popular questions from this chapter

Using Data 5.1 on page \(375,\) we find a significant difference in the proportion of fruit flies surviving after 13 days between those eating organic potatoes and those eating conventional (not organic) potatoes. Exercises 6.166 to 6.169 ask you to conduct a hypothesis test using additional data from this study. \(^{40}\) In every case, we are testing $$\begin{array}{ll}H_{0}: & p_{o}=p_{c} \\\H_{a}: & p_{o}>p_{c}\end{array}$$ where \(p_{o}\) and \(p_{c}\) represent the proportion of fruit flies alive at the end of the given time frame of those eating organic food and those eating conventional food, respectively. Also, in every case, we have \(n_{1}=n_{2}=500 .\) Show all remaining details in the test, using a \(5 \%\) significance level. Effect of Organic Raisins after 15 Days After 15 days, 320 of the 500 fruit flies eating organic raisins are still alive, while 300 of the 500 eating conventional raisins are still alive.

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