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18 - to 24 -year-olds The survey included 194 young adults (ages 18 to 24 ) and 53 of them said that they had used online dating. If we use this sample to estimate the proportion of all young adults to use online dating, the standard error is 0.032 . Find a \(95 \%\) confidence interval for the proportion of all US adults ages 18 to 24 to use online dating.

Short Answer

Expert verified
After calculating, we will obtain a confidence interval. This will be presented as a range, stating that we are 95% confident that the true proportion of young adults (18-24 years) in the US who use online dating falls within the range calculated, provided there are no systematic errors in data collection.

Step by step solution

01

- Determine Sample Proportion

Calculate the sample proportion (\(p\)) from our data. This obtained by taking the number who have used online dating, 53, and dividing by the total number of respondents, 194. So, \(p = 53 / 194\)
02

- Calculate the Confidence Interval

We utilize the definition of a confidence interval for a proportion: \((p - Z*SE, p + Z*SE)\). Where p is the sample proportion, Z is the z-value, and SE is the standard error. For a 95% confidence interval, the z-value, Z, is approximately 1.96. As given, Standard Error (SE) = 0.032. Insert these values into the formula to find the confidence interval.
03

- Result Interpretation

The result obtained is a range or interval which gives us a degree of surety (in this case, 95%) that the actual proportion of all young adults ages 18 to 24 who use online dating in the US is within this range. This interval provides estimates upper and lower limits, between which the true proportion lies with a 95% probability.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
When conducting a study about a large population, it's not always feasible to collect data from every individual. Instead, researchers take a smaller group known as a sample to represent the larger population. The sample proportion is then an estimate of the proportion in the full population who possess a particular trait, based on the sample.

For example, from the given exercise, if we're looking at the use of online dating among young adults, the sample proportion is the number of individuals who indicated they have used online dating services divided by the total number of individuals in the sample. This provides an estimate, however imperfect, of the actual proportion of all young adults who use online dating services.
Standard Error
Understanding standard error is crucial when interpreting the reliability of an estimate. It measures how much a sample statistic, like the sample mean or proportion, is likely to differ from the true population statistic. It's tied inextricably to the concept of sampling variability: even with a perfect sampling method, different samples yield different estimates.

Think of the standard error as a way to quantify uncertainty. In the exercise, the standard error of 0.032 doesn't tell us that the sample proportion is off by that exact amount, but it gives us a way to gauge the precision of our sample proportion. A smaller standard error implies a more reliable estimate — hence, it is a critical component in the construction of confidence intervals.
Z-Value
The z-value is a number that represents a particular position in a normal distribution and is used in the process of statistical inference. It's linked to the confidence level one chooses for an interval estimate. For instance, a z-value of 1.96 corresponds roughly to a 95% confidence level, which is commonly used in statistical analysis.

This value is crucial because it standardizes scores, allowing interpretation of data using the normal distribution. In the case of forming a confidence interval for a proportion, the z-value scales the standard error to give margins on either side of the sample estimate, ensuring that, under the assumption of normality, the true population proportion is captured within that range with the given degree of confidence (e.g., 95% confidence).
Statistical Inference
Finally, let's delve into the world of statistical inference, the process of using data from a sample to make conclusions about the bigger population. This often involves drawing conclusions about population parameters, like a proportion or mean, based on sample statistics.

In your exercise, constructing a confidence interval is a form of statistical inference. This interval is a range of values that likely includes the true population proportion of interest. The inclusion of a 95% confidence level in the interval means we can say there is a 95% chance that the interval created from these sample data contains the actual proportion. Thus, despite inherent uncertainties, statistical inference allows us to make educated guesses about a population trait, with a quantifiable level of confidence on how accurate those guesses likely are.

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Most popular questions from this chapter

Exercises 5.7 to 5.12 include a set of hypotheses, some information from one or more samples, and a standard error from a randomization distribution. Find the value of the standardized \(z\) -test statistic in each situation. Test \(H_{0}: \mu=80\) vs \(H_{a}: \mu>80\) when the sample has \(n=20, \bar{x}=82.4,\) and \(s=3.5,\) with \(S E=0.8\).

55- to 64-year-olds The survey included 411 adults between the ages of 55 and \(64,\) and 50 of them said that they had used online dating. If we use this sample to estimate the proportion of all American adults ages 55 to 64 to use online dating, the standard error is \(0.016 .\) Find a \(95 \%\) confidence interval for the proportion of all US adults ages 55 to 64 to use online dating.

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Find the indicated confidence interval. Assume the standard error comes from a bootstrap distribution that is approximately normally distributed. A \(95 \%\) confidence interval for a difference in proportions \(p_{1}-p_{2}\) if the samples have \(n_{1}=50\) with \(\hat{p}_{1}=0.68\) and \(n_{2}=80\) with \(\hat{p}_{2}=0.61,\) and the standard error is \(S E=0.085\).

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