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91Ó°ÊÓ

Find the \(z^{*}\) values based on a standard normal distribution for each of the following. (a) An \(86 \%\) confidence interval for a correlation. (b) A \(94 \%\) confidence interval for a difference in proportions. (c) A \(96 \%\) confidence interval for a proportion.

Short Answer

Expert verified
The \(z^{*}\) values for the given conditions are: (a) 1.48 for an 86% confidence interval, (b) 1.88 for a 94% confidence interval, (c) 2.05 for a 96% confidence interval.

Step by step solution

01

Calculation for 86% Confidence Interval

Since the data is symmetrical about the mean 0, the value of ‘a’ is calculated. Then the remaining percentage 1 - 0.86 = 0.14 is divided by 2, leaving 0.07 in each tail of the distribution. Thus, \(a = 0.86 + 0.07 = 0.93\) or \(93\% \).Now,looking this value from a Z table or by using an online calculator, the \(z^{*}\) value that corresponds to \(93\% \) is found as \(1.48\).
02

Calculation for 94% Confidence Interval

For the 94% confidence interval, again the remaining percentage from 1 is divided by 2. Therefore, \(a = 0.94 + (1 - 0.94)/2 = 0.97\) (or 97% ). Using the Z table or online calculator again gives the \(z^{*}\) value of \(1.88\) for \(97\% \).
03

Calculation for 96% Confidence Interval

Similarly, for the 96% confidence interval, calculate \(a = 0.96 + (1 - 0.96)/2 = 0.98\) (or 98% ). From the Z-table or online calculator, the \(z^{*}\) value that corresponds to \(98%\) is found to be \(2.05\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Normal Distribution
The standard normal distribution is a special kind of normal distribution that has a mean of 0 and a standard deviation of 1. It is represented by the letter 'Z' and is often referred to as the Z-distribution. This distribution is crucial when calculating confidence intervals, such as in our example, because it allows us to find the critical value, represented as \(z^{*}\), for a given confidence level.

Here's how it works: the Z-distribution is symmetrical around its mean, which means if you are looking for the value that marks the edge of the confidence interval, you can use a Z-table or an online calculator. The Z-table helps in finding probabilities and percentiles associated with Z-scores. Depending on the confidence level, you find \(z^{*}\) by determining the percentage of the distribution that lies within the interval.
  • For example, for an 86% confidence interval, you would calculate 1 - 0.86 = 0.14. This 0.14 is the remaining percentage that is outside the interval, equally split into each tail, so 0.07 per tail. You then add this amount to the confidence level to find the cumulative probability (0.93 or 93%).
  • By using the Z-table or calculator, you would look up this percentage to find the corresponding \(z^{*}\) value, which in this case is 1.48.
Understanding this concept is a key step in performing statistical analysis because it helps in determining the range of possible values that a parameter can take with a certain level of confidence.
Correlation
Correlation is a statistical measure that describes the extent to which two variables change together. It is typically measured by the correlation coefficient, which ranges from -1 to +1. A value of +1 indicates a perfect positive relationship, 0 indicates no relationship, and -1 indicates a perfect negative relationship.

In the context of the exercise, using confidence intervals for correlation helps in assessing the reliability of the correlation coefficient obtained from sample data. This confidence interval gives a range of values within which the true population correlation is likely to lie, considering sample size and variation.
  • When calculating a confidence interval for a correlation, like the 86% confidence interval in the exercise, you use critical \(z^{*}\) values derived from the standard normal distribution to determine how much the sample correlation could vary if the study were repeated.
  • Understanding this helps to ensure that conclusions drawn about the strength and direction of a relationship between two variables are statistically significant and not due to random chance.
Being proficient with calculating and interpreting correlation and its confidence intervals allows for robust conclusions in research studies and real-world data analysis.
Difference in Proportions
The difference in proportions refers to the comparison between two proportions, typically from two different groups. This comparison seeks to determine if there is a statistically significant difference between the two groups. For this analysis, confidence intervals are used, and \(z^{*}\) values are crucial for finding these intervals.

Calculating such a confidence interval involves:
  • Estimating the standard error of the difference between the two proportions.
  • Multiplying the standard error by the critical \(z^{*}\) value to find the margin of error.
  • Adding and subtracting this margin of error to/from the observed difference gives the range within which the true difference likely lies.
For instance, in the exercise for a 94% confidence interval, you subtract 0.94 from 1 and divide by 2, resulting in 0.03 added to the cumulative percentage for finding \(z^{*}\) = 1.88.

This approach is key when assessing hypotheses about differences in proportions, such as in medical studie or public opinion polls. It helps to assert with confidence the likelihood of any observed disparities in the population.

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Most popular questions from this chapter

How Often Do You Use Cash? In a survey \(^{13}\) of 1000 American adults conducted in April 2012 . \(43 \%\) reported having gone through an entire week without paying for anything in cash. Test to see if this sample provides evidence that the proportion of all American adults going a week without paying cash is greater than \(40 \%\). Use the fact that a randomization distribution is approximately normally distributed with a standard error of \(S E=0.016 .\) Show all details of the test and use a \(5 \%\) significance level.

Effect of Organic Potatoes after 11 Days After 11 days, the proportion of fruit flies eating organic potatoes still alive is 0.68 , while the proportion still alive eating conventional potatoes is \(0.66 .\) The standard error for the difference in proportions is \(0.030 .\)

Exercise and Gender The dataset ExerciseHours contains information on the amount of exercise (hours per week) for a sample of statistics students. The mean amount of exercise was 9.4 hours for the 30 female students in the sample and 12.4 hours for the 20 male students, A randomization distribution of differences in means based on these data, under a null hypothesis of no difference in mean exercise time between females and males, is centered near zero and reasonably normally distributed. The standard error for the difference in means, as estimated from the randomization distribution, is \(S E=2.38\). Use this information to test, at a \(5 \%\) level, whether the data show that the mean exercise time for female statistics students is less than the mean exercise time of male statistics students.

Effect of Organic Bananas after 25 Days After 25 days, the proportion of fruit flies eating organic bananas still alive is \(0.42,\) while the proportion still alive eating conventional bananas is \(0.40 .\) The standard error for the difference in proportions is 0.031 .

Exercises 5.7 to 5.12 include a set of hypotheses, some information from one or more samples, and a standard error from a randomization distribution. Find the value of the standardized \(z\) -test statistic in each situation. Test \(H_{0}: \mu=80\) vs \(H_{a}: \mu>80\) when the sample has \(n=20, \bar{x}=82.4,\) and \(s=3.5,\) with \(S E=0.8\).

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