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In Exercises 5.15 to 5.17 , find the specified areas for a normal distribution. For a \(N(160,25)\) distribution (a) The area to the right of 140 (b) The area to the left of 200

Short Answer

Expert verified
For part (a), the area to the right of 140 is 0.99997, and for part (b), the area to the left of 200 is 1.

Step by step solution

01

Find the Z-score for part (a)

The formula to calculate Z-score is \(Z = (X - μ) / σ\). For part (a) we need to find the Z-score for X = 140. Therefore, the Z-score will be \(Z = (140 - 160) / √25 = -4\).
02

Find the area to the right of Z-score for part (a)

We can find the area to the left of the Z-score from the standard normal distribution table, which for Z = -4 is 0.00003. But we want the area to the right, which is given by \(1 - 0.00003 = 0.99997\).
03

Find the Z-score for part (b)

Again, we use the Z-score formula. For part (b) we need to find the Z-score for X = 200. Hence, the Z-score will be \(Z = (200 - 160) / √25 = 8\).
04

Find the area to the left of Z-score for part (b)

For Z = 8, the area to its left on the standard normal distribution table is 1 because the table does not consider Z-scores above 3.4. Since the question is asking for the area to the left, our answer is \(1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-score
The Z-score, also known as the standard score, is a critical concept in statistics when dealing with normal distributions. It helps us determine how far away a particular data point is from the mean in terms of standard deviations.
To calculate the Z-score for a given data point, we use the formula:
  • \[ Z = \frac{X - \mu}{\sigma} \]
  • \(X\) is the data point in question,
  • \(\mu\) is the mean of the distribution,
  • and \(\sigma\) is the standard deviation of the distribution.
The Z-score tells us how many standard deviations a data point (\(X\)) is from the mean. A positive Z-score indicates that the data point is above the mean, while a negative Z-score shows it's below the mean. For example, a Z-score of -4, as calculated for the value 140 from the exercise, indicates that 140 is 4 standard deviations below the mean of 160.
Standard Normal Distribution
The standard normal distribution is a special case of the normal distribution. It has a mean of 0 and a standard deviation of 1. This distribution is represented by the Z-scores. The standard normal distribution allows us to standardize different normal distributions and apply to them a single set of probabilities.
When we transform a normal distribution into a standard normal distribution using the Z-score formula, we're effectively converting the data points into Z-scores.
These Z-scores then tell us where the data points lie in terms of standard deviations relative to the mean.
The standard normal distribution table, or Z-table, is a tool that helps find the probability of a Z-score being less than (to the left of) a given value. For instance, a Z-score of 8 would be far to the right on the standard normal distribution curve, meaning it covers almost all typical values so its probability to the left is practically 1.
Area Calculation
Calculating areas under the normal distribution curve is key when trying to find out the probability of certain events. These areas represent probabilities.
For a distribution \(N(\mu, \sigma^2)\), areas under the curve can tell us about the proportion of data points that lie above or below a certain value.
For example, in the exercise:
  • The area to the right of a Z-score represents the probability of a value being greater than the Z-score.
  • The area to the left indicates the probability of a value being less or equal to the Z-score.
We often use tables of the standard normal distribution to find these areas. For instance, for a Z-score of -4, the area to the left is very small (0.00003), and the area to the right can be calculated as 1 minus this value (0.99997).
This demonstrates how extremely rare it is to find such a low score compared to the mean in a normal distribution.

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