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A confidence interval for a sample is given, followed by several hypotheses to test using that sample. In each case, use the confidence interval to give a conclusion of the test (if possible) and also state the significance level you are using. A \(90 \%\) confidence interval for \(p_{1}-p_{2}: 0.07\) to 0.18 (a) \(H_{0}: p_{1}=p_{2}\) vs \(H_{a}: p_{1} \neq p_{2}\) (b) \(H_{0}: p_{1}=p_{2}\) vs \(H_{a}: p_{1}>p_{2}\) (c) \(H_{0}: p_{1}=p_{2}\) vs \(H_{a}: p_{1}

Short Answer

Expert verified
Based on the given 90% confidence interval, we reject the hypotheses \(H_{0}: p_{1}=p_{2}\) for alternatives \(H_{a}: p_{1} \neq p_{2}\) and \(H_{a}: p_{1}>p_{2}\), but fail to reject it for \(H_{a}: p_{1}<p_{2}\). The significance level used is 10%.

Step by step solution

01

Analysis of the 90% Confidence Interval

First of all, analyze the 90% confidence interval of \(p_{1}-p_{2}\) which ranges from 0.07 to 0.18. A \(90 \%\) confidence interval means that we can be \(90 \%\) confident that the true difference between \(p_{1}\) and \(p_{2}\) lies within this range.
02

Testing Hypothesis (a)

Test the hypothesis \(H_{0}: p_{1}=p_{2}\) against \(H_{a}: p_{1} \neq p_{2}\). If \(p_{1}=p_{2}\), then \(p_{1}-p_{2}=0\). However, 0 is not within the provided confidence interval of 0.07 to 0.18. Therefore, we reject \(H_{0}\) at the \(10 \%\) significance level.
03

Testing Hypothesis (b)

Now test the hypothesis \(H_{0}: p_{1}=p_{2}\) against \(H_{a}: p_{1}>p_{2}\). If \(p_{1}=p_{2}\), then \(p_{1}-p_{2}=0\). The entire confidence interval is above 0, so we reject \(H_{0}\) at the \(10 \%\) significance level.
04

Testing Hypothesis (c)

Lastly, test the hypothesis \(H_{0}: p_{1}=p_{2}\) against \(H_{a}: p_{1}<p_{2}\). If \(p_{1}<p_{2}\), then \(p_{1}-p_{2}<0\). The entire confidence interval is above 0, so we fail to reject \(H_{0}\) at the \(10 \%\) significance level.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Intervals
Confidence intervals are a range of values, derived from sample data, that are believed to contain the true parameter of the population with a certain probability. In hypothesis testing, they serve as an alternative way to test the hypothesis, especially when you do not have access to the original dataset or enough information to perform a standard test.

In the given exercise, a 90% confidence interval for the difference between two proportions, labeled as \( p_{1} \) and \( p_{2} \), was provided. The interval from 0.07 to 0.18 implies that we are 90% confident that the true difference between \( p_{1} \) and \( p_{2} \) lies within this range. By interpreting this confidence interval, one can draw conclusions about the plausibility of the null hypothesis (in this case, that \( p_{1} = p_{2} \) or \( p_{1}-p_{2} = 0 \) ). If the interval does not contain the value under the null hypothesis (0 in this scenario), we have evidence to reject the null hypothesis. Since the interval does not include 0, we can conclude that there is a statistically significant difference between \( p_{1} \) and \( p_{2} \).
Significance Level
The significance level, often denoted by \( \alpha \), is a threshold used to decide whether a statistical hypothesis should be rejected. It is the probability of making a Type I error, which occurs when the null hypothesis is true, but is incorrectly rejected.

In hypothesis testing, if the p-value is less than \( \alpha \), the null hypothesis is rejected. A common significance level used is 0.05, but in the provided exercise, a 90% confidence interval corresponds to a significance level of \( \alpha = 0.10 \). This means there is a 10% risk of wrongly rejecting the null hypothesis \( H_{0}: p_{1} = p_{2} \). When deciding whether to reject \( H_{0} \) based on the confidence interval, you're essentially testing it at the 10% significance level.
Difference Between Two Proportions
When dealing with two separate groups, researchers often want to compare the proportions between these groups, for example, the proportion of success in one group versus another. The difference between two proportions is a measure of how much the proportions in two groups differ from one another.

In this context, the hypothesis tests are structured to examine whether the proportions from two different populations, \( p_{1} \) and \( p_{2} \), are the same or not (null hypothesis) or whether one is larger or smaller than the other (alternative hypothesis). The exercise provided uses a 90% confidence interval to test three different hypotheses related to the difference between two proportions. Each hypothesis (a, b, and c) examines a different relationship (equal, greater than, or less than) between \( p_{1} \) and \( p_{2} \) and draws conclusions based on whether 0 is included in the confidence interval.

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Most popular questions from this chapter

Could owning a cat as a child be related to mental illness later in life? Toxoplasmosis is a disease transmitted primarily through contact with cat feces, and has recently been linked with schizophrenia and other mental illnesses. Also, people infected with Toxoplasmosis tend to like cats more and are 2.5 times more likely to get in a car accident, due to delayed reaction times. The CDC estimates that about \(22.5 \%\) of Americans are infected with Toxoplasmosis (most have no symptoms), and this prevalence can be as high as \(95 \%\) in other parts of the world. A study \(^{37}\) randomly selected 262 people registered with the National Alliance for the Mentally Ill (NAMI), almost all of whom had schizophrenia, and for each person selected, chose two people from families without mental illness who were the same age, sex, and socioeconomic status as the person selected from NAMI. Each participant was asked whether or not they owned a cat as a child. The results showed that 136 of the 262 people in the mentally ill group had owned a cat, while 220 of the 522 people in the not mentally ill group had owned a cat. (a) This is known as a case-control study, where cases are selected as people with a specific disease or trait, and controls are chosen to be people without the disease or trait being studied. Both cases and controls are then asked about some variable from their past being studied as a potential risk factor. This is particularly useful for studying rare diseases (such as schizophrenia), because the design ensures a sufficient sample size of people with the disease. Can casecontrol studies such as this be used to infer a causal relationship between the hypothesized risk factor (e.g., cat ownership) and the disease (e.g., schizophrenia)? Why or why not? (b) In case-control studies, controls are usually chosen to be similar to the cases. For example, in this study each control was chosen to be the same age, sex, and socioeconomic status as the corresponding case. Why choose controls who are similar to the cases? (c) For this study, calculate the relevant difference in proportions; proportion of cases (those with schizophrenia) who owned a cat as a child minus proportion of controls (no mental illness) who owned a cat as a child. (d) For testing the hypothesis that the proportion of cat owners is higher in the schizophrenic group than the control group, use technology to generate a randomization distribution and calculate the p-value. (e) Do you think this provides evidence that there is an association between owning a cat as a child and developing schizophrenia? \(^{38}\) Why or why not?

A study \(^{54}\) shows that relationship status on Facebook matters to couples. The study included 58 college-age heterosexual couples who had been in a relationship for an average of 19 months. In 45 of the 58 couples, both partners reported being in a relationship on Facebook. In 31 of the 58 couples, both partners showed their dating partner in their Facebook profile picture. Men were somewhat more likely to include their partner in the picture than vice versa. However, the study states: "Females' indication that they are in a relationship was not as important to their male partners compared with how females felt about male partners indicating they are in a relationship." Using a population of college-age heterosexual couples who have been in a relationship for an average of 19 months: (a) A \(95 \%\) confidence interval for the proportion with both partners reporting being in a relationshipon Facebook is about 0.66 to 0.88 . What is the conclusion in a hypothesis test to see if the proportion is different from \(0.5 ?\) What significance level is being used? (b) A \(95 \%\) confidence interval for the proportion with both partners showing their dating partner in their Facebook profile picture is about 0.40 to \(0.66 .\) What is the conclusion in a hypothesis test to see if the proportion is different from \(0.5 ?\) What significance level is being used?

In a test to see whether males, on average, have bigger noses than females, the study indicates that " \(p<0.01\)."

Using the complete voting records of a county to see if there is evidence that more than \(50 \%\) of the eligible voters in the county voted in the last election.

A confidence interval for a sample is given, followed by several hypotheses to test using that sample. In each case, use the confidence interval to give a conclusion of the test (if possible) and also state the significance level you are using. A \(95 \%\) confidence interval for \(p: 0.48\) to 0.57 (a) \(H_{0}: p=0.5\) vs \(H_{a}: p \neq 0.5\) (b) \(H_{0}: p=0.75\) vs \(H_{a}: p \neq 0.75\) (c) \(H_{0}: p=0.4\) vs \(H_{a}: p \neq 0.4\)

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