/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 In Exercises 3.49 and 3.50 , a \... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Exercises 3.49 and 3.50 , a \(95 \%\) confidence interval is given, followed by possible values of the population parameter. Indicate which of the values are plausible values for the parameter and which are not. A \(95 \%\) confidence interval for a mean is 112.1 to \(128.2 .\) Is the value given a plausible value of \(\mu ?\) (a) \(\mu=121\) (b) \(\mu=113.4\) (c) \(\mu=105.3\)

Short Answer

Expert verified
The plausible values are \(\mu = 121\) and \(\mu = 113.4\) as they both lie within the \(95\%\) confidence interval of 112.1 to 128.2. The value \(\mu = 105.3\) is not plausible as it falls outside of the confidence interval.

Step by step solution

01

- Assessing Plausibility for \(\mu = 121\)

Firstly, assess whether \(\mu = 121\) is a plausible value for the mean. As the value 121 lies within the given confidence interval of 112.1 to 128.2, this means it is plausible that the true population mean could be 121.
02

- Assessing Plausibility for \(\mu = 113.4\)

Next, assess whether \(\mu = 113.4\) is a plausible value for the mean. As the value 113.4 also falls within the confidence interval of 112.1 to 128.2, it is plausible that 113.4 could be the true mean for the population.
03

- Assessing Plausibility for \(\mu = 105.3\)

Lastly, assess whether \(\mu = 105.3\) is a plausible value for \(\mu\). Since value 105.3 falls outside the given confidence interval of 112.1 to 128.2, it is not plausible that the true population mean \(\mu\) is 105.3.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Parameter
When discussing statistics, a population parameter is a crucial concept. It refers to any measurable characteristic of a statistical population. These are the summaries that describe aspects such as the mean or variance of the entire group you're interested in studying. However, since actual population parameters are typically unknown, we often estimate them using sample data. Understanding population parameters is vital because it allows you to generalize your findings from a sample to the broader population. When we talk about a 95% confidence interval, it implies that there's a 95% chance the interval contains the true population parameter. This is helpful in giving insights into where the actual value lies, although we never know it for sure. In our example, the population parameter we are focusing on is the mean, \(\mu\), of the data set.
Mean
The mean is one of the most commonly used measures of central tendency. It gives us an average value of a set of numbers, calculated by summing all data points and then dividing by the number of data points. In the context of statistical analysis, especially when discussing confidence intervals, the mean offers an insightful estimate of the central or typical value of the dataset. For our example, a 95% confidence interval of the mean ranged from 112.1 to 128.2. This interval implies that the average of our population is likely to fall within this range.
  • The mean helps us understand typical behavior or characteristics in the data set.
  • It's sensitive to outliers, so it's crucial to consider it alongside other measures like median and mode if there are extreme values.
  • In our specific case, \(\mu = 121\) and \(\mu = 113.4\) were considered plausible as they fell within the interval, but \(\mu = 105.3\) did not.
Plausibility Assessment
The concept of plausibility assessment is about determining the likelihood of certain values being true based on your confidence interval. In simple terms, it's about checking which values fit well within your estimated range and which ones don’t. When you have a confidence interval, such as 112.1 to 128.2 for the population mean, assessing plausibility tells you whether proposed values like \(\mu = 121\) or \(\mu = 113.4\) are reasonable estimates based on your data. To do this, you check if the values are within the given interval:
  • Values within the interval (e.g., 121 and 113.4) are plausible because they adhere to the range dictated by our confidence level.
  • Values outside the interval (e.g., 105.3) aren't plausible, indicating they are less likely to be the actual mean based on our sample data.
Assessing plausibility is a beneficial exercise in statistics, as it aids in understanding the confidence of our estimates and how well they capture the reality of the population.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Small Sample Size and Outliers As we have seen, bootstrap distributions are generally symmetric and bell-shaped and centered at the value of the original sample statistic. However, strange things can happen when the sample size is small and there is an outlier present. Use StatKey or other technology to create a bootstrap distribution for the standard deviation based on the following data: \(8 \quad 10\) 72 \(13 \quad 8\) \(\begin{array}{ll}10 & 50\end{array}\) Describe the shape of the distribution. Is it appropriate to construct a confidence interval from this distribution? Explain why the distribution might have the shape it does.

Standard Deviation of NHL Penalty Minutes Exercise 3.102 describes data on the number of penalty minutes for Ottawa Senators NHL players. The sample has a fairly large standard deviation, \(s=27.3\) minutes. Use StatKey or other technology to create a bootstrap distribution, estimate the standard error, and give a \(95 \%\) confidence interval for the standard deviation of penalty minutes for NHL players. Assume that the data in OttawaSenators can be viewed as a reasonable sample of all NHL players.

Topical Painkiller Ointment The use of topical painkiller ointment or gel rather than pills for pain relief was approved just within the last few years in the US for prescription use only. \({ }^{13}\) Insurance records show that the average copayment for a month's supply of topical painkiller ointment for regular users is \$30. A sample of \(n=75\) regular users found a sample mean copayment of \(\$ 27.90\). (a) Identify each of 30 and 27.90 as a parameter or a statistic and give the appropriate notation for each. (b) If we take 1000 samples of size \(n=75\) from the population of all copayments for a month's supply of topical painkiller ointment for regular users and plot the sample means on a dotplot, describe the shape you would expect to see in the plot and where it would be centered. (c) How many dots will be on the dotplot you described in part (b)? What will each dot represent?

Predicting Election Results Throughout the US presidential election of \(2016,\) polls gave regular updates on the sample proportion supporting each candidate and the margin of error for the estimates. This attempt to predict the outcome of an election is a common use of polls. In each case below, the proportion of voters who intend to vote for each of two candidates is given as well as a margin of error for the estimates. Indicate whether we can be relatively confident that candidate A would win if the election were held at the time of the poll. (Assume the candidate who gets more than \(50 \%\) of the vote wins.) \(\begin{array}{lll}\text { (a) Candidate A: } 54 \% & \text { Candidate }\end{array}\) B: \(46 \%\) Margin of error: \(\pm 5 \%\) (b) Candidate A: \(52 \%\) Candidate B: \(48 \%\) Margin of error: \(\pm 1 \%\) \(\begin{array}{ll}\text { (c) Candidate A: } 53 \% & \text { Candidate }\end{array}\) B: \(47 \%\) Margin of error: \(\pm 2 \%\) \(\begin{array}{lll}\text { (d) Candidate A: } 58 \% & \text { Candidate }\end{array}\) B: \(42 \%\) Margin of error: \(\pm 10 \%\)

Are Female Rats More Compassionate Than Male Rats? Exercise 3.88 describes a study in which rats showed compassion by freeing a trapped rat. In the study, all six of the six female rats showed compassion by freeing the trapped rat while 17 of the 24 male rats did so. Use the results of this study to give a best estimate for the difference in proportion of rats showing compassion, between female rats and male rats. Then use StatKey or other technology to estimate the standard error \(^{44}\) and use it to compute a \(95 \%\) confidence interval for the difference in proportions. Use the interval to determine whether it is plausible that male and female rats are equally compassionate (i.e., that the difference in proportions is zero). The data are available in the dataset CompassionateRats.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.