/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 57 Test \(H_{0}: p=0.3\) vs \(H_{a}... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Test \(H_{0}: p=0.3\) vs \(H_{a}: p<0.3\) using the sample results \(\hat{p}=0.21\) with \(n=200\)

Short Answer

Expert verified
Calculate the test statistic using the given sample proportion, assumed population proportion and sample size. Then compare this test statistic with the critical Z value to decide whether to reject or not reject the null hypothesis.

Step by step solution

01

Compute the Test Statistic

The formula for the Z-test statistic in a one-proportion hypothesis test is \(Z = \frac{\hat{p} - p}{\sqrt{\frac{p(1 - p)}{n}}}\). Substitute the given values: \(\hat{p}=0.21\), \(p=0.3\) and \(n=200\), then carry out the calculations. This value of Z represents how many standard deviations the sample proportion is from the population proportion.
02

Find the Critical Z Value

Since this is a one-tailed test (\(H_{a}: p<0.3\)), and the level of confidence is not mentioned, conventionally a 5% significance level is assumed. Thus, the critical value of Z for a one-tailed test with a significance level of 0.05 is -1.645. This is the cutoff value that the test statistic is compared with to make a decision about the null hypothesis.
03

Making the Decision

If the test statistic computed in Step 1 is less than the critical Z value found in Step 2 (-1.645), then reject the null hypothesis (\(H_{0}\)). If not, fail to reject the null hypothesis (\(H_{0}\)).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-test
A Z-test is a powerful tool used in statistics when comparing a sample statistic to a population parameter. It's most commonly implemented when the sample size is large, typically n > 30. This test helps us determine if there is a significant difference between the sample data and what we expect based on the population data. In hypothesis testing, the Z-test enables us to calculate a Z-value, which tells us how far the sample proportion is from the population proportion in terms of standard deviations.
For a one-proportion Z-test, like the exercise here, we use the formula: \[ Z = \frac{\hat{p} - p}{\sqrt{\frac{p(1 - p)}{n}}} \]where \( \hat{p} \) is the sample proportion, \( p \) is the hypothesized population proportion, and \( n \) is the sample size.
With these values, we can determine if the observed difference is significant enough to question our initial assumption or hypothesis.
One-Proportion Test
The one-proportion test is a type of Z-test. It is utilized when we seek to compare the proportion of a single sample to a known population proportion. The objective is to understand if the sample proportion is statistically significantly different from what we expect.
In the context of the exercise, the null hypothesis \( H_0: p = 0.3 \) suggests that the sample proportion should match the population parameter, while the alternative hypothesis \( H_a: p < 0.3 \) indicates our interest is directed towards determining if the sample proportion is smaller than the population proportion.
To perform this test, we calculate the test statistic using the Z-test formula and compare it against a critical value to draw conclusions. This approach provides a robust method of hypothesis testing, answering questions about likelihoods anchored in statistical evidence.
Significance Level
The significance level, often denoted as \( \alpha \), is a crucial concept in hypothesis testing. It represents the probability of rejecting the null hypothesis when it is, in fact, true. It's the threshold at which you decide whether an observed effect is statistically significant.
In many cases, a 5% significance level (\( \alpha = 0.05 \)) is conventionally used. This implies there's a 5% risk of concluding that there is an effect when there isn't one. The choice of \( \alpha \) affects how conservative or liberal our test is.
In the exercise example, the critical Z-value for a one-tailed test at a 5% significance level is -1.645. This means that if our calculated Z statistic falls below -1.645, we reject the null hypothesis. Understanding significance levels helps balance the risk of false positives or negatives, thus providing confidence in the test conclusions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A sample with \(n=10, \bar{x}=508.5,\) and \(s=21.5\)

Exercise B.5 on page 305 introduces a study examining the effect of diet cola consumption on calcium levels in women. A sample of 16 healthy women aged 18 to 40 were randomly assigned to drink 24 ounces of either diet cola or water. Their urine was collected for three hours after ingestion of the beverage and calcium excretion (in mg) was measured. The summary statistics for diet cola are \(\bar{x}_{C}=56.0\) with \(s_{C}=4.93\) and \(n_{C}=8\) and the summary statistics for water are \(\bar{x}_{W}=49.1\) with \(s_{W}=3.64\) and \(n_{W}=8\). Figure 6.26 shows dotplots of the data values. Test whether there is evidence that diet cola leaches calcium out of the system, which would increase the amount of calcium in the urine for diet cola drinkers. In Exercise B.5, we used a randomization distribution to conduct this test. Use a t-distribution here, after first checking that the conditions are met and explaining your reasoning. The data are stored in ColaCalcium.

Of the 50 states in the Unites States, Alaska has the largest percentage of males and Rhode Island has the largest percentage of females. (Interestingly, Alaska is the largest state and Rhode Island is the smallest). According to the 2010 US Census, the population of Alaska is \(52.0 \%\) male and the population of Rhode Island is \(48.3 \%\) male. If we randomly sample 300 people from Alaska and 300 people from Rhode Island, what is the approximate distribution of \(\hat{p}_{a}-\hat{p}_{r i}\), where \(\hat{p}_{a}\) is the proportion of males in the Alaskan sample and \(\hat{p}_{r i}\) is the proportion of males in the Rhode Island sample?

Test \(H_{0}: \mu_{1}=\mu_{2}\) vs \(H_{a}: \mu_{1} \neq \mu_{2}\) using the paired difference sample results \(\bar{x}_{d}=-2.6, s_{d}=4.1\) \(n_{d}=18\)

A \(95 \%\) confidence interval for \(\mu_{1}-\mu_{2}\) using the paired difference sample results \(\bar{x}_{d}=3.7, s_{d}=\) 2.1, \(n_{d}=30\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.