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In April 2012, the Gallup Poll reported that in a random sample of 1016 US adults, only \(17 \%\) approve of the way Congress is handling its job. \({ }^{17}\) (a) Use the poll results to estimate the proportion of all US adults who approve of the way Congress is doing its job. What is the margin of error, with \(99 \%\) confidence, for this estimate? (b) If the Gallup Poll wants the estimate to be accurate to within \(\pm 1 \%\), with \(99 \%\) confidence, how large a sample must they use?

Short Answer

Expert verified
a) The estimate of the proportion of all US adults who approve of the way Congress is handling its job is \(17\%\), and the margin of error for this estimate with 99% confidence can be obtained using the formula mentioned in the solution. b) The sample size necessary to ensure an accuracy of \(\pm 1 \%\), with 99% confidence, can be calculated with the use of the formula as detailed in the solution steps.

Step by step solution

01

Part a: Estimation of proportion and margin of error

Firstly, it will be useful to recall that the margin of error for a proportion is given by: \(E = Z \sqrt { (p(1-p)) / n }\), where Z is the Z-score associated with the desired level of confidence, p is the sample proportion, and n is the sample size. For this problem, the Z-score for a 99% confidence interval is about 2.576 (obtained from standard statistical tables), the sample proportion \(p = 0.17\), and \(n = 1016\). Plug these values into the formula to get the margin of error: \(E = 2.576 \sqrt { (0.17(1-0.17)) / 1016 }\).
02

Margin of error calculation

After plugging the values into the formula, simplify the equation to calculate the margin of error. Keep in mind that the answer needs to be in percentage.
03

Part b: determination of the sample size

To find the sample size needed for an accuracy of \(\pm 1 \%\) with 99% confidence, use the formula for the margin of error, but this time solve for n: \(n = (Z^2 * p * (1-p)) / E^2 \). Here the margin of error \(E = 0.01\) since we want the estimate to be accurate to within \(\pm 1 \%\). Plug the values into the formula and solve for n. Note that the value obtained for n will likely not be a whole number. In such cases, always round up to the nearest whole number because we can't have a fraction of a person.
04

Sample size calculation

After plugging in the values into the sample size formula, simplify the equation to get the required sample size. This value should then be rounded up to the nearest whole number, as we can't sample a fraction of a person.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Size Determination
Understanding how to determine the optimal sample size for a survey or study is crucial for obtaining reliable and accurate results. Sample size determination involves calculating how many respondents are needed to ensure that the statistical estimations made from the sample are reflective of the entire population.

Let's consider the example from the Gallup Poll. The analysts wish to have a margin of error of \(\pm 1 \%\) with a 99% confidence level. To find the necessary sample size for these conditions, the formula \[n = (Z^2 * p * (1-p)) / E^2\] is used. Here, \(Z\) represents the Z-score correlating with the specified confidence level, \(p\) is the estimated proportion of the population, and \(E\) stands for the desired margin of error.

Calculation simplification tips include rounding intermediate steps to a reasonable number of decimal places to avoid rounding error accumulation. Upon determining the required sample size, if the result is not a whole number, round up to ensure the sample isn't smaller than needed. This approach guarantees the desired accuracy of the survey's conclusions is sustained.
Confidence Intervals
Confidence intervals represent the range within which we expect a population parameter to fall, with a certain degree of certainty. The percentage that indicates this level of certainty is called the confidence level.

For the Gallup Poll example, an approval rating for Congress was estimated based on a sample. The confidence interval, alongside the estimate (sample proportion), helps us understand the estimate's accuracy. In this case, a 99% confidence level was chosen. Typically, popular choices for confidence levels are 90%, 95%, or 99%, each corresponding to a specific Z-score, which adjusts the width of the interval.

The confidence interval adds and subtracts the margin of error from the sample proportion. This process provides a range within which the true population proportion likely falls. The formula for the margin of error, \(E = Z \sqrt { (p(1-p)) / n }\), is essential for creating that interval, with \(p\) being the sample proportion, \(n\) the sample size, and \(Z\) the Z-score associated with the desired level of confidence. Understanding how to calculate and interpret confidence intervals empowers students to critically analyse statistical claims and understand the uncertainties inherent in sample-based estimates.
Gallup Poll Analysis
Gallup Poll analysis involves interpreting the data collected from samples to make inferences about the overall population's opinions and behaviours. The key is recognizing that every statistical analysis carries a degree of error due to the limitations of sample-based studies.

In the exercise involving the Gallup Poll, the analysis aimed to estimate the proportion of US adults approving of Congress's performance. To interpret the poll's findings correctly, we would consider the calculated confidence interval. The margin of error, calculated from the sample proportion and size, informs us about the potential range of error surrounding the approval rating.

To improve comprehension when interpreting such polls, it is helpful to remember that the reported figures are not exact representations but estimates with a certain probability of capturing the true population parameter. The margin of error and the confidence level together provide a context for understanding how much faith we can put into these estimates. Polls can influence public perception and policy decisions, so understanding their analysis is important for students, policymakers, and the general public alike.

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Most popular questions from this chapter

Random samples of the given sizes are drawn from populations with the given means and standard deviations. For each scenario: (a) Find the mean and standard error of the distribution of differences in sample means, \(\bar{x}_{1}-\bar{x}_{2}\) (b) If the sample sizes are large enough for the Central Limit Theorem to apply, draw a curve showing the shape of the sampling distribution. Include at least three values on the horizontal axis. Samples of size 50 from Population 1 with mean 3.2 and standard deviation 1.7 and samples of size 50 from Population 2 with mean 2.8 and standard deviation 1.3

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Involve scores from the high school graduating class of 2010 on the SAT (Scholastic Aptitude Test). The distribution of sample means \(\bar{x}_{N}-\bar{x}_{E},\) where \(\bar{x}_{N}\) represents the mean Critical Reading score for a sample of 100 people for whom the native language is not English and \(\bar{x}_{E}\) represents the mean Critical Reading score for a sample of 100 people whose native language is English, is centered at -41 with a standard deviation of 16.0. Give notation and define the quantity we are estimating with these sample differences. In the population of all students taking the test, who scored higher on average, non-native English speakers or native English speakers?

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