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Use a t-distribution. Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the endpoints of the t-distribution with \(2.5 \%\) beyond them in each tail if the samples have sizes \(n_{1}=15\) and \(n_{2}=25\)

Short Answer

Expert verified
The degrees of freedom used are 14 and the endpoints of the t-distribution with 2.5% beyond them in each tail are approximately \( \pm 2.145 \).

Step by step solution

01

Identify Necessary Information

The necessary information given in the problem are the sample sizes (\(n_{1}=15\) and \(n_{2}=25\)) and the percentage (2.5%) beyond the endpoints in each tail.
02

Calculate Degrees of Freedom

For this instance, with two samples, the number of degrees of freedom is calculated by subtracting one from each sample size and taking the smaller number. So, here it will be \(\min(n_{1}-1, n_{2}-1)\), which will be \(\min(15-1, 25-1) = \min(14, 24) = 14.\)
03

Determine the Endpoints

With 2.5% in each tail, the associated t-score for 95% confidence (middle area) can be found using a t-distribution table (or a t-score calculator). For a DOF of 14, the t-score is approximately 2.145.
04

Find the Endpoints in t-Distribution

The endpoints of the t-distribution will simply be \( \pm 2.145 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Degrees of Freedom
Degrees of freedom are an essential component of many statistical calculations, especially within the context of inferential statistics. They refer to the number of independent values that can vary in an analysis without breaking any constraints. In the context of the t-distribution, degrees of freedom (often abbreviated as DOF) are crucial when determining the shape of the distribution.

When dealing with two samples, like in the exercise, you calculate the degrees of freedom based on the sample sizes. For independent sample t-tests (like comparing two sample means), you often use the formula \( \min(n_1 - 1, n_2 - 1) \).

In our scenario, with sample sizes \( n_1 = 15 \) and \( n_2 = 25 \), the degrees of freedom come out to be 14 because it's the smaller of \( n_1 - 1 = 14 \) and \( n_2 - 1 = 24 \).

Using this smaller number ensures that the estimate is conservative, accounting for potential variability and uncertainty. Degrees of freedom directly influence the critical value of the t-statistic, which in turn, affects confidence intervals and hypothesis tests.
The Role of Sample Means
Sample means are central to the process of comparing two samples. They represent the average value from each sample and serve as focal points in hypothesis testing.

Consider two datasets: one comprising 15 observations and the other 25. The sample means of these datasets are the arithmetic averages of each. These means are used to assess the difference between the populations from which they're drawn.

When conducting a t-test, the difference in sample means helps evaluate whether observed discrepancies are statistically significant or merely due to random sampling variability.

Essential elements when calculating the means involve:
  • Summing up all the values in a sample.
  • Dividing by the number of observations in the sample.
Accurate estimation of sample means is vital for drawing meaningful inferences. It forms the basis for calculating the t-statistic, which checks if there is a substantial difference between the two groups.
Decoding the T-Statistic
The t-statistic is a critical tool in inferential statistics, particularly when working with small sample sizes or unknown population variances. It's used to determine how far the sample mean deviates from a hypothesized population mean in units of standard error.

The formula for the t-statistic, when comparing two sample means, is:\[ t = \frac{\bar{x}_1 - \bar{x}_2}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}} \]where:
  • \( \bar{x}_1 \) and \( \bar{x}_2 \) are the sample means.
  • \( s_1 \) and \( s_2 \) are the sample standard deviations.
  • \( n_1 \) and \( n_2 \) are the sample sizes.
The t-statistic tells you whether a significant difference exists between sample means relative to the variability and size of each sample. In our original exercise, you determined the critical t-value with 14 degrees of freedom as approximately 2.145 for a 95% confidence interval.

This approach provides insights into whether we can reject a null hypothesis or not, based on the magnitude and direction of the calculated t-value compared to critical values found in t-distribution tables.

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Most popular questions from this chapter

A margin of error within \(\pm 2 \%\) with \(95 \%\) confidence. An initial small sample has \(\hat{p}=0.78\).

Refer to a study on hormone replacement therapy. Until 2002 , hormone replacement therapy (HRT), taking hormones to replace those the body no longer makes after menopause, was commonly prescribed to post-menopausal women. However, in 2002 the results of a large clinical trial \(^{56}\) were published, causing most doctors to stop prescribing it and most women to stop using it, impacting the health of millions of women around the world. In the experiment, 8506 women were randomized to take HRT and 8102 were randomized to take a placebo. Table 6.16 shows the observed counts for several conditions over the five years of the study. (Note: The planned duration was 8.5 years. If Exercises 6.205 through 6.208 are done correctly, you will notice that several of the p-values are just below \(0.05 .\) The study was terminated as soon as HRT was shown to significantly increase risk (using a significance level of \(\alpha=0.05)\), because at that point it was unethical to continue forcing women to take HRT). Does HRT influence the chance of a woman getting cancer of any kind? $$ \begin{array}{lcc} \hline \text { Condition } & \text { HRT Group } & \text { Placebo Group } \\ \hline \text { Cardiovascular Disease } & 164 & 122 \\ \text { Invasive Breast Cancer } & 166 & 124 \\ \text { Cancer (all) } & 502 & 458 \\ \text { Fractures } & 650 & 788 \\ \hline \end{array} $$

Find endpoints of a t-distribution with 0.025 beyond them in each tail if the sample has size \(n=25 .\)

Find the area in a t-distribution above 2.3 if the sample has size \(n=6\).

Drinking tea appears to offer a strong boost to the immune system. In a study introduced in Exercise 3.82 on page \(203,\) we see that production of interferon gamma, a molecule that fights bacteria, viruses, and tumors, appears to be enhanced in tea drinkers. In the study, eleven healthy non-tea- drinking individuals were asked to drink five or six cups of tea a day, while ten healthy nontea- and non-coffee-drinkers were asked to drink the same amount of coffee, which has caffeine but not the \(L\) -theanine that is in tea. The groups were randomly assigned. After two weeks, blood samples were exposed to an antigen and production of interferon gamma was measured. The results are shown in Table 6.23 and are available in ImmuneTea. The question of interest is whether the data provide evidence that production is enhanced in tea drinkers. (a) Is this an experiment or an observational study? (b) What are the null and alternative hypotheses? (c) Find a standardized test statistic and use the t-distribution to find the p-value and make a conclusion. (d) Always plot your data! Look at a graph of the data. Does it appear to satisfy a normality condition? (e) A randomization test might be a more appropriate test to use in this case. Construct a randomization distribution for this test and use it to find a p-value and make a conclusion. (f) What conclusion can we draw? $$ \begin{array}{lrrrrrr} \hline \text { Tea } & 5 & 11 & 13 & 18 & 20 & 47 \\ & 48 & 52 & 55 & 56 & 58 & \\ \hline \text { Coffee } & 0 & 0 & 3 & 11 & 15 & 16 \\ & 21 & 21 & 38 & 52 & & \\ \hline \end{array} $$

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