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Use a t-distribution. Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the endpoints of the t-distribution with \(2.5 \%\) beyond them in each tail if the samples have sizes \(n_{1}=15\) and \(n_{2}=25\)

Short Answer

Expert verified
The degrees of freedom used are 14 and the endpoints of the t-distribution with 2.5% beyond them in each tail are approximately \( \pm 2.145 \).

Step by step solution

01

Identify Necessary Information

The necessary information given in the problem are the sample sizes (\(n_{1}=15\) and \(n_{2}=25\)) and the percentage (2.5%) beyond the endpoints in each tail.
02

Calculate Degrees of Freedom

For this instance, with two samples, the number of degrees of freedom is calculated by subtracting one from each sample size and taking the smaller number. So, here it will be \(\min(n_{1}-1, n_{2}-1)\), which will be \(\min(15-1, 25-1) = \min(14, 24) = 14.\)
03

Determine the Endpoints

With 2.5% in each tail, the associated t-score for 95% confidence (middle area) can be found using a t-distribution table (or a t-score calculator). For a DOF of 14, the t-score is approximately 2.145.
04

Find the Endpoints in t-Distribution

The endpoints of the t-distribution will simply be \( \pm 2.145 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Degrees of Freedom
Degrees of freedom are an essential component of many statistical calculations, especially within the context of inferential statistics. They refer to the number of independent values that can vary in an analysis without breaking any constraints. In the context of the t-distribution, degrees of freedom (often abbreviated as DOF) are crucial when determining the shape of the distribution.

When dealing with two samples, like in the exercise, you calculate the degrees of freedom based on the sample sizes. For independent sample t-tests (like comparing two sample means), you often use the formula \( \min(n_1 - 1, n_2 - 1) \).

In our scenario, with sample sizes \( n_1 = 15 \) and \( n_2 = 25 \), the degrees of freedom come out to be 14 because it's the smaller of \( n_1 - 1 = 14 \) and \( n_2 - 1 = 24 \).

Using this smaller number ensures that the estimate is conservative, accounting for potential variability and uncertainty. Degrees of freedom directly influence the critical value of the t-statistic, which in turn, affects confidence intervals and hypothesis tests.
The Role of Sample Means
Sample means are central to the process of comparing two samples. They represent the average value from each sample and serve as focal points in hypothesis testing.

Consider two datasets: one comprising 15 observations and the other 25. The sample means of these datasets are the arithmetic averages of each. These means are used to assess the difference between the populations from which they're drawn.

When conducting a t-test, the difference in sample means helps evaluate whether observed discrepancies are statistically significant or merely due to random sampling variability.

Essential elements when calculating the means involve:
  • Summing up all the values in a sample.
  • Dividing by the number of observations in the sample.
Accurate estimation of sample means is vital for drawing meaningful inferences. It forms the basis for calculating the t-statistic, which checks if there is a substantial difference between the two groups.
Decoding the T-Statistic
The t-statistic is a critical tool in inferential statistics, particularly when working with small sample sizes or unknown population variances. It's used to determine how far the sample mean deviates from a hypothesized population mean in units of standard error.

The formula for the t-statistic, when comparing two sample means, is:\[ t = \frac{\bar{x}_1 - \bar{x}_2}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}} \]where:
  • \( \bar{x}_1 \) and \( \bar{x}_2 \) are the sample means.
  • \( s_1 \) and \( s_2 \) are the sample standard deviations.
  • \( n_1 \) and \( n_2 \) are the sample sizes.
The t-statistic tells you whether a significant difference exists between sample means relative to the variability and size of each sample. In our original exercise, you determined the critical t-value with 14 degrees of freedom as approximately 2.145 for a 95% confidence interval.

This approach provides insights into whether we can reject a null hypothesis or not, based on the magnitude and direction of the calculated t-value compared to critical values found in t-distribution tables.

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Most popular questions from this chapter

Has Support for Capital Punishment Changed over Time? The General Social Survey (GSS) has been collecting demographic, behavioral, and attitudinal information since 1972 to monitor changes within the US and to compare the US to other nations. \({ }^{46}\) Support for capital punishment (the death penalty) in the US is shown in 1974 and in 2006 in the two-way table in Table \(6.6 .\) Find a \(95 \%\) confidence interval for the change in the proportion supporting capital punishment between 1974 and 2006. Is it plausible that the proportion supporting capital punishment has not changed? $$ \begin{array}{rrcl} \hline \text { Year } & \text { Favor } & \text { Oppose } & \text { Total } \\\ \hline 1974 & 937 & 473 & 1410 \\ 2006 & 1945 & 870 & 2815 \\ \hline \end{array} $$

(a) Find the relevant sample proportions in each group and the pooled proportion. (b) Complete the hypothesis test using the normal distribution and show all details. Table 6.10 gives flight arrival numbers from a random sample of flights for two airlines. Test whether there is a difference between the two airlines in the percent of flights that arrive late.

Use the t-distribution and the sample results to complete the test of the hypotheses. Use a \(5 \%\) significance level. Assume the results come from a random sample, and if the sample size is small, assume the underlying distribution is relatively normal. Test \(H_{0}: \mu=500\) vs \(H_{a}: \mu \neq 500\) using the sample results \(\bar{x}=432, s=118,\) with \(n=75\).

Find endpoints of a t-distribution with 0.005 beyond them in each tail if the sample has size \(n=40 .\)

In a nationwide poll of 1000 randomly sampled adults conducted in June \(2011,83 \%\) said they think children spend too much time on their computers and other electronic devices (but \(37 \%\) say time spent on a computer is better than time spent in front of a \(\mathrm{TV}) .{ }^{9}\) Find and interpret a \(95 \%\) confidence interval for the proportion of adults who believe children spend too much time on electronic devices. What is the margin of error for this result? Is it plausible that the proportion of all adults who feel this way is less than \(80 \%\) ? Is it plausible that the proportion is greater than \(85 \% ?\)

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