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Use the t-distribution and the sample results to complete the test of the hypotheses. Use a \(5 \%\) significance level. Assume the results come from a random sample, and if the sample size is small, assume the underlying distribution is relatively normal. Test \(H_{0}: \mu=500\) vs \(H_{a}: \mu \neq 500\) using the sample results \(\bar{x}=432, s=118,\) with \(n=75\).

Short Answer

Expert verified
After calculating the t-value and comparing with t-critical value, the decision can be made whether to reject or not reject the null hypothesis \(H_{0}: \mu=500\).

Step by step solution

01

Setting Up the Hypotheses

The null hypothesis, \(H_{0}: \mu=500\) and the alternative hypothesis, \(H_{a}: \mu \neq 500\) are already set up. We will test these hypotheses using the given sample results.
02

Calculating the Test Statistic

Next, calculate the test statistic (t) using the formula: \[t = \frac{\bar{x} - \mu_0}{\frac{s}{\sqrt{n}}}\]where:\(\bar{x} = 432\) is the sample mean,\(\mu_0 = 500\) is the value from null hypothesis,\(s = 118\) is the sample standard deviation,\(n = 75\) is the sample size.Substitute these values into the equation to get the t-value.
03

Determine Critical Values and Make a Decision

From the t-distribution table (or using a t-distribution calculator), find the t-critical value corresponding to 5% significance level (0.025 in each tail because this is a two-tailed test) and the degrees of freedom, which is \(n-1 = 75-1 = 74\). If the absolute value of the sample t-value is greater than the t-critical value, reject null hypothesis. Otherwise, do not reject null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the t-Distribution
In hypothesis testing, the t-distribution often plays a starring role, especially when dealing with smaller sample sizes or unknown population standard deviations. The t-distribution is a type of probability distribution that is symmetric and bell-shaped, similar to the normal distribution, but with heavier tails. These heavier tails mean it tends to produce more extreme values, making it ideal to use when dealing with factors such as:**
  • Small sample sizes: When the sample size is small (typically n < 30), the Central Limit Theorem tells us regular assumptions may not apply. Thus, the t-distribution is more appropriate.
  • Unknown population standard deviation: Often, we don't know the population's standard deviation, so we estimate it using the sample standard deviation as is the case here with s = 118.
  • Degrees of freedom (df): The shape of the t-distribution changes with different sample sizes, characterized by its degrees of freedom which is calculated as n-1. In this exercise, with n=75, we have 74 degrees of freedom.
These points make the t-distribution robust and suitable for tests concerning sample means, such as the one in our example.
Grasping the Concept of Significance Level
The significance level in hypothesis testing is a measure of how willing we are to risk making a Type I error - that is, rejecting a true null hypothesis. It is usually represented by the Greek letter alpha (α). In this exercise, our significance level is set at 5% or 0.05.

A significance level of 5% means there is a 5% risk of concluding that a difference exists when there is actually none. This threshold helps to decide whether the test results are significant enough to reject the null hypothesis (Hâ‚€). In a two-tailed test like this one, this 5% is split into two tails, giving us 0.025 in each tail.

  • Choice of significance level is subjective: Common levels include 1%, 5%, and 10% and the choice may depend on the field of study or consequences of an error.
  • Critical value determination: This is derived using the significance level and is key in deciding the fate of our hypothesis.
By understanding how and why we choose a certain significance level, it becomes easier to interpret results accurately and contextually.
Decoding the Test Statistic
The test statistic is a crucial component in hypothesis testing, acting as the basis for decision-making. For comparing means, the t-test is a popular choice. The test statistic, denoted as t in this context, quantifies the difference between the sample mean and the hypothesized population mean in units of standard error.

To compute the test statistic, the formula used is:\[t = \frac{\bar{x} - \mu_0}{\frac{s}{\sqrt{n}}} \]where:
  • \(\bar{x}\) is the sample mean, here 432.
  • \(\mu_0\) is the claim about the population mean from the null hypothesis, here 500.
  • \(s\) is the sample standard deviation, here 118.
  • \(n\) is the sample size, here 75.
This calculation provides a t-value, which you then compare with the t-critical values from the t-distribution table at your given significance level. If the absolute t-value obtained from calculations surpasses the critical t-values from the table, the null hypothesis is rejected. Otherwise, it is not rejected. Understanding this process confirms the role the test statistic plays in hypothesis testing - bridging sample data with statistical decisions.

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Most popular questions from this chapter

Approximately \(10 \%\) of Americans are left-handed (we will treat this as a known population parameter). A study on the relationship between handedness and profession found that in a random sample of 105 lawyers, 16 of them were left-handed. \({ }^{21}\) Test the hypothesis that the proportion of left-handed lawyers differs from the proportion of left-handed Americans. (a) Clearly state the null and alternative hypotheses. (b) Calculate the test statistic and p-value. (c) What do we conclude at the \(5 \%\) significance level? At the \(10 \%\) significance level?

If random samples of the given sizes are drawn from populations with the given proportions: (a) Find the mean and standard error of the distribution of differences in sample proportions, \(\hat{p}_{A}-\hat{p}_{B}\) (b) If the sample sizes are large enough for the Central Limit Theorem to apply, draw a curve showing the shape of the sampling distribution. Include at least three values on the horizontal axis. Samples of size 80 from population \(A\) with proportion 0.40 and samples of size 60 from population \(B\) with proportion 0.10

Find endpoints of a t-distribution with 0.025 beyond them in each tail if the sample has size \(n=25 .\)

Exercise B.5 on page 305 introduces a study examining the effect of diet cola consumption on calcium levels in women. A sample of 16 healthy women aged 18 to 40 were randomly assigned to drink 24 ounces of either diet cola or water. Their urine was collected for three hours after ingestion of the beverage and calcium excretion (in mg) was measured. The summary statistics for diet cola are \(\bar{x}_{C}=56.0\) with \(s_{C}=4.93\) and \(n_{C}=8\) and the summary statistics for water are \(\bar{x}_{W}=49.1\) with \(s_{W}=3.64\) and \(n_{W}=8\). Figure 6.26 shows dotplots of the data values. Test whether there is evidence that diet cola leaches calcium out of the system, which would increase the amount of calcium in the urine for diet cola drinkers. In Exercise B.5, we used a randomization distribution to conduct this test. Use a t-distribution here, after first checking that the conditions are met and explaining your reasoning. The data are stored in ColaCalcium.

Refer to a study on hormone replacement therapy. Until 2002 , hormone replacement therapy (HRT), taking hormones to replace those the body no longer makes after menopause, was commonly prescribed to post-menopausal women. However, in 2002 the results of a large clinical trial \(^{56}\) were published, causing most doctors to stop prescribing it and most women to stop using it, impacting the health of millions of women around the world. In the experiment, 8506 women were randomized to take HRT and 8102 were randomized to take a placebo. Table 6.16 shows the observed counts for several conditions over the five years of the study. (Note: The planned duration was 8.5 years. If Exercises 6.205 through 6.208 are done correctly, you will notice that several of the p-values are just below \(0.05 .\) The study was terminated as soon as HRT was shown to significantly increase risk (using a significance level of \(\alpha=0.05)\), because at that point it was unethical to continue forcing women to take HRT). Does HRT influence the chance of a woman getting invasive breast cancer? $$ \begin{array}{lcc} \hline \text { Condition } & \text { HRT Group } & \text { Placebo Group } \\ \hline \text { Cardiovascular Disease } & 164 & 122 \\ \text { Invasive Breast Cancer } & 166 & 124 \\ \text { Cancer (all) } & 502 & 458 \\ \text { Fractures } & 650 & 788 \\ \hline \end{array} $$

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