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Exercise and the Brain It is well established that exercise is beneficial for our bodies. Recent studies appear to indicate that exercise can also do wonders for our brains, or, at least, the brains of mice. In a randomized experiment, one group of mice was given access to a running wheel while a second group of mice was kept sedentary. According to an article describing the study, "The brains of mice and rats that were allowed to run on wheels pulsed with vigorous, newly born neurons, and those animals then breezed through mazes and other tests of rodent IQ"10 compared to the sedentary mice. Studies are examining the reasons for these beneficial effects of exercise on rodent (and perhaps human) intelligence. High levels of BMP (bone- morphogenetic protein) in the brain seem to make stem cells less active, which makes the brain slower and less nimble. Exercise seems to reduce the level of BMP in the brain. Additionally, exercise increases a brain protein called noggin, which improves the brain's ability. Indeed, large doses of noggin turned mice into "little mouse geniuses," according to Dr. Kessler, one of the lead authors of the study. While research is ongoing in determining which effects are significant, all evidence points to the fact that exercise is good for the brain. Several tests involving these studies are described. In each case, define the relevant parameters and state the null and alternative hypotheses. (a) Testing to see if there is evidence that mice allowed to exercise have lower levels of BMP in the brain on average than sedentary mice (b) Testing to see if there is evidence that mice allowed to exercise have higher levels of noggin in the brain on average than sedentary mice (c) Testing to see if there is evidence of a negative correlation between the level of BMP and the level of noggin in the brains of mice

Short Answer

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Scenario (a) Null Hypothesis (\(H_0\)): There is no difference between the average BMP levels of exercising and sedentary mice.\nAlternative Hypothesis (\(H_A\)): Exercising mice have lower levels of BMP on average than sedentary mice.\nScenario (b) Null Hypothesis (\(H_0\)): There is no difference between the average noggin levels of exercising and sedentary mice.\nAlternative Hypothesis (\(H_A\)): Exercising mice have higher levels of noggin in the brain on average than sedentary mice.\nScenario (c) Null Hypothesis (\(H_0\)): There is no correlation between the level of BMP and the level of noggin.\nAlternative Hypothesis (\(H_A\)): There is a negative correlation between the level of BMP and the level of noggin in the brains of mice.

Step by step solution

01

Define Hypothesis for Scenario (a)

For scenario (a), the relevant parameter could be the average levels of BMP in the brains of mice. The null hypothesis (\(H_0\)) would be that exercise does not affect the average levels of BMP in the brains of mice, stating that there is no difference between the average BMP levels of exercising and sedentary mice. The alternative hypothesis (\(H_A\)) would be that exercise affects the average levels of BMP in the mice brains, stating that exercising mice have lower levels of BMP on average than sedentary mice.
02

Define Hypothesis for Scenario (b)

For scenario (b), the relevant parameter could be the average levels of noggin in mice's brains. The null hypothesis (\(H_0\)) would be that exercise doesn't affect the average levels of noggin in the mice brains, stating there is no difference between the average noggin levels in exercising and sedentary mice. The alternative hypothesis (\(H_A\)) would be that exercise affects the average levels of noggin in the brains of the mice, stating that exercising mice have higher levels of noggin in the brain on average than sedentary mice.
03

Define Hypothesis for Scenario (c)

For scenario (c), the relevant parameters is the correlation between the level of BMP and the level of noggin in the brains of mice. The null hypothesis (\(H_0\)) would be that there's no correlation between the level of BMP and the level of noggin. The alternative hypothesis (\(H_A\)) would be that there is a negative correlation between the level of BMP and the level of noggin in the brains of mice.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null and Alternative Hypotheses
In the realm of statistics, understanding the null and alternative hypotheses is fundamental to hypothesis testing. When researchers want to check the validity of a claim or assess the effect of an intervention, such as exercise on brain function, they begin by setting up these hypotheses.

The null hypothesis (\(H_0\)), is the default assumption that there is no effect or no difference; it serves as a benchmark for comparing the observed data. In our example regarding exercise and brain function in mice, the null hypothesis asserts that exercise does not influence the average levels of BMP or noggin in the brain.

Conversely, the alternative hypothesis (\(H_A\) or \(H_1\) corresponds to the research hypothesis and reflects the effect or difference that the study aims to investigate, such as lower BMP levels or higher noggin levels in exercising mice.

Importance of Clear Definitions

Clear definitions of these hypotheses are crucial for designing the experiment and interpreting results. If the results gathered from an experiment with mice suggest that exercising mice indeed have different levels of these brain proteins compared to sedentary ones, researchers may reject the null hypothesis in favor of the alternative.

Binary Nature of Hypotheses

It's essential to note that these hypotheses are mutually exclusive—only one can be true in the context of the study. Moreover, they must be formulated before any data collection to avoid bias and ensure the integrity of the research process.
Correlation in Statistics
Correlation holds immense significance in statistics as it gauges the strength and direction of a relationship between two variables. When we speak of correlation, particularly in scientific research, we are often probing how closely two variables move in relation to one another.

In the context of the brain function study, researchers might investigate the correlation between BMP and noggin levels in mice brains. If a negative correlation is present, as one variable increases (BMP), the other (noggin) tends to decrease, and vice versa. Detecting such patterns is fundamental to understanding biological interactions and can provide insights into mechanisms through which exercise impacts brain function.

Distinguishing Correlation from Causation

Importantly, correlation does not imply causation. Just because two things are correlated, it doesn't necessarily mean that one causes the other. There could be other lurking variables or the possibility of a coincidental relationship. In our mice example, even if a negative correlation between BMP and noggin is found, further experimentation is necessary to determine if exercise directly causes the changes observed.
Effect of Exercise on Brain Function
Delving into the biological effects of exercise on the brain, it is fascinating to observe how physical activity can influence cognitive function and structural brain changes. Research, like the mouse study in the exercise, suggests that exercise can boost brain health by modifying protein levels that regulate brain development and neuronal activity—a topic of great interest in both neuroscience and psychology.

Proteins like BMP and noggin serve as biological indicators of brain health. Variations in their levels could impact how brain cells function and communicate, suggesting that increasing physical activity might lead to improved cognitive abilities through biological pathways.

Practical Implications for Humans

Exploring the effects observed in mice may also have implications for human health. Exercise is often touted for its myriad benefits on physical health, but studies like the one described could pave the way to understanding how lifestyle choices like regular physical activity could have a similarly profound impact on our mental acuity and neuroplasticity—the brain's ability to reorganize itself by forming new neural connections.

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Most popular questions from this chapter

Classroom Games Two professors \(^{18}\) at the University of Arizona were interested in whether having students actually play a game would help them analyze theoretical properties of the game. The professors performed an experiment in which students played one of two games before coming to a class where both games were discussed. Students were randomly assigned to which of the two games they played, which we'll call Game 1 and Game \(2 .\) On a later exam, students were asked to solve problems involving both games, with Question 1 referring to Game 1 and Question 2 referring to Game 2 . When comparing the performance of the two groups on the exam question related to Game 1 , they suspected that the mean for students who had played Game 1 ( \(\mu_{1}\) ) would be higher than the mean for the other students \(\mu_{2},\) so they considered the hypotheses \(H_{0}: \mu_{1}=\mu_{2}\) vs \(H_{a}: \mu_{1}>\mu_{2}\) (a) The paper states: "test of difference in means results in a p-value of \(0.7619 . "\) Do you think this provides sufficient evidence to conclude that playing Game 1 helped student performance on that exam question? Explain. (b) If they were to repeat this experiment 1000 times, and there really is no effect from playing the game, roughly how many times would you expect the results to be as extreme as those observed in the actual study? (c) When testing a difference in mean performance between the two groups on exam Question 2 related to Game 2 (so now the alternative is reversed to be \(H_{a}: \mu_{1}<\mu_{2}\) where \(\mu_{1}\) and \(\mu_{2}\) represent the mean on Question 2 for the respective groups), they computed a p-value of \(0.5490 .\) Explain what it means (in the context of this problem) for both p-values to be greater than \(0.5 .\)

Watch Out for Lions after a Full Moon Scientists studying lion attacks on humans in Tanzania \(^{34}\) found that 95 lion attacks happened between \(6 \mathrm{pm}\) and \(10 \mathrm{pm}\) within either five days before a full moon or five days after a full moon. Of these, 71 happened during the five days after the full moon while the other 24 happened during the five days before the full moon. Does this sample of lion attacks provide evidence that attacks are more likely after a full moon? In other words, is there evidence that attacks are not equally split between the two five-day periods? Use StatKey or other technology to find the p-value, and be sure to show all details of the test. (Note that this is a test for a single proportion since the data come from one sample.)

State the null and alternative hvpotheses for the statistical test described. Testing to see if there is evidence that the correlation between two variables is negative

In Exercises 4.146 to \(4.149,\) hypotheses for a statistical test are given, followed by several possible confidence intervals for different samples. In each case, use the confidence interval to state a conclusion of the test for that sample and give the significance level used. Hypotheses: \(H_{0}: p=0.5\) vs \(H_{a}: p \neq 0.5\) (a) \(95 \%\) confidence interval for \(p: \quad 0.53\) to 0.57 (b) \(95 \%\) confidence interval for \(p: \quad 0.41\) to 0.52 (c) 99\% confidence interval for \(p: \quad 0.35\) to 0.55

Arsenic in Chicken Data 4.5 on page 228 introduces a situation in which a restaurant chain is measuring the levels of arsenic in chicken from its suppliers. The question is whether there is evidence that the mean level of arsenic is greater than 80 ppb, so we are testing \(H_{0}: \mu=80\) vs \(H_{a}: \mu>80\), where \(\mu\) represents the average level of arsenic in all chicken from a certain supplier. It takes money and time to test for arsenic so samples are often small. Suppose \(n=6\) chickens from one supplier are tested, and the levels of arsenic (in ppb) are: \(68, \quad 75\) 81, \(\quad 93\) 134 (a) What is the sample mean for the data? (b) Translate the original sample data by the appropriate amount to create a new dataset in which the null hypothesis is true. How do the sample size and standard deviation of this new dataset compare to the sample size and standard deviation of the original dataset? (c) Write the six new data values from part (b) on six cards. Sample from these cards with replacement to generate one randomization sample. (Select a card at random, record the value, put it back, select another at random, until you have a sample of size \(6,\) to match the original sample size.) List the values in the sample and give the sample mean. (d) Generate 9 more simulated samples, for a total of 10 samples for a randomization distribution. Give the sample mean in each case and create a small dotplot. Use an arrow to locate the original sample mean on your dotplot.

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