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Are You "In a Relationship"? A new study \(^{45}\) shows that relationship status on Facebook matters to couples. The study included 58 college-age heterosexual couples who had been in a relationship for an average of 19 months. In 45 of the 58 couples, both partners reported being in a relationship on Facebook. In 31 of the 58 couples, both partners showed their dating partner in their Facebook profile picture. Men were somewhat more likely to include their partner in the picture than vice versa. However, the study states: "Females' indication that they are in a relationship was not as important to their male partners compared with how females felt about male partners indicating they are in a relationship." Using a population of college-age heterosexual couples who have been in a relationship for an average of 19 months: (a) A \(95 \%\) confidence interval for the proportion with both partners reporting being in a relationship on Facebook is about 0.66 to \(0.88 .\) What is the conclusion in a hypothesis test to see if the proportion is different from \(0.5 ?\) What significance level is being used? (b) A 95\% confidence interval for the proportion with both partners showing their dating partner in their Facebook profile picture is about 0.40 to 0.66. What is the conclusion in a hypothesis test to see if the proportion is different from \(0.5 ?\) What significance level is being used?

Short Answer

Expert verified
For the first confidence interval (0.66 to 0.88), we would reject the hypothesis that the true proportion is 0.5, as it does not fall within this range. The significance level is 0.05. For the second confidence interval (0.40 to 0.66), we would not reject the hypothesis that the true proportion is 0.5, as it does fall within this range. The significance level is also 0.05.

Step by step solution

01

Evaluating the first confidence interval

This step focuses on assessing whether 0.5 could be a plausible value for the proportion of couples both reporting being in a relationship on Facebook. The 95% confidence interval is from 0.66 to 0.88. Since 0.5 does not fall into this range, we would conclude that, at a 95% confidence level, the proportion of couples both reporting being in a relationship on Facebook is significantly different from 0.5. This would lead us to reject the null hypothesis that the proportion is 0.5. The significance level associated with a 95% confidence level is 0.05.
02

Evaluating the second confidence interval

Following the same procedures as in Step 1, we turn our attention to the proportion of couples both exhibiting their dating partner in their profile picture on Facebook. The statement provides a 95% confidence interval from 0.40 to 0.66. Since 0.5 is within this range, it is a plausible value for the population parameter at a 95% confidence level. Therefore, we would not reject the null hypothesis that the proportion is 0.5 in this instance. The significance level for this test is also 0.05 as the confidence level is stated as 95%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
When we talk about confidence intervals in statistics, we are referring to the range within which we expect a certain population parameter to fall, with a specific level of certainty. Essentially, it is an educated guess about where an unknown population parameter (e.g., a mean or proportion) can lie based on a sample statistic.

For example, in our exercise regarding relationship statuses on Facebook, a 95% confidence interval for the proportion of couples both reporting being in a relationship is given as from 0.66 to 0.88. This interval was constructed from sampled data, and it suggests with 95% confidence that the true proportion of such couples in the entire population would fall within this range.

If we were to take many samples and calculate a range like this from each one, we'd expect the true population parameter to be within this range 95% of the time. The '95%' is what we call the 'confidence level' and directly reflects how sure we are that our interval contains the true parameter. Meanwhile, the 'confidence interval' offers a visual understanding of where the parameter lies, indicating, for instance, if a hypothesized value (like 0.5 in the exercise) is plausible or not.
Null Hypothesis
In hypothesis testing, the null hypothesis, often denoted as H0, is a statement suggesting there is no effect or no difference, and it serves as the starting point for statistical significance testing. It is the hypothesis that the researcher tries to disprove or reject.

In the context of the Facebook relationship status study, the null hypothesis might be that the true proportion of couples who display their relationship status or feature their partner in their profile picture is equal to 0.5 – essentially saying that it's equally likely as not. Hypothesis testing then assesses whether the sample data provide enough evidence to reject this hypothesis. If the confidence interval does not include the hypothesized value (0.5 in this case), like it doesn't in part (a) of the exercise, this suggests there is a significant difference, thus leading to the rejection of the null hypothesis.
Significance Level
The significance level, denoted by the Greek letter alpha (α), is the threshold used to determine whether a statistical result is not likely due to chance. This level represents the probability of rejecting the null hypothesis when it is in fact true, a scenario known as a 'Type I error'.

In most social science research, including our Facebook relationship status scenario, a common significance level used is 0.05, or 5%. This means there is a 5% risk of concluding that a difference exists when there is no actual difference. If the confidence interval excludes the hypothesized value, as it is in the (a) part of the Facebook study, and if we're using the 5% significance level, then we have strong evidence against the null hypothesis. Conversely, part (b) of the study demonstrates a scenario where the null hypothesis is not rejected, hence implying that there isn't strong evidence to suggest a difference from the hypothesized value, within the accepted risk of 0.05.

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Most popular questions from this chapter

Guilty Verdicts in Court Cases A reporter on cnn.com stated in July 2010 that \(95 \%\) of all court cases that go to trial result in a guilty verdict. To test the accuracy of this claim, we collect a random sample of 2000 court cases that went to trial and record the proportion that resulted in a guilty verdict. (a) What is/are the relevant parameter(s)? What sample statistic(s) is/are used to conduct the test? (b) State the null and alternative hypotheses. (c) We assess evidence by considering how likely our sample results are when \(H_{0}\) is true. What does that mean in this case?

Weight Loss Program Suppose that a weight loss company advertises that people using its program lose an average of 8 pounds the first month and that the Federal Trade Commission (the main government agency responsible for truth in advertising) is gathering evidence to see if this advertising claim is accurate. If the FTC finds evidence that the average is less than 8 pounds, the agency will file a lawsuit against the company for false advertising. (a) What are the null and alternative hypotheses the FTC should use? (b) Suppose that the FTC gathers information from a very large random sample of patrons and finds that the average weight loss during the first month in the program is \(\bar{x}=7.9\) pounds with a p-value for this result of \(0.006 .\) What is the conclusion of the test? Are the results statistically significant? (c) Do you think the results of the test are practically significant? In other words, do you think patrons of the weight loss program will care that the average is 7.9 pounds lost rather than 8.0 pounds lost? Discuss the difference between practical significance and statistical significance in this context.

In Exercises 4.71 to \(4.74,\) using the p-value given, are the results significant at a \(10 \%\) level? At a \(5 \%\) level? At a 1\% level? $$ \text { p-value }=0.0320 $$

State the null and alternative hvpotheses for the statistical test described. Testing to see if there is evidence that the correlation between two variables is negative

Exercises 4.117 to 4.122 give null and alternative hypotheses for a population proportion, as well as sample results. Use StatKey or other technology to generate a randomization distribution and calculate a p-value. StatKey tip: Use "Test for a Single Proportion" and then "Edit Data" to enter the sample information. Hypotheses: \(H_{0}: p=0.6\) vs \(H_{a}: p>0.6\) Sample data: \(\hat{p}=52 / 80=0.65\) with \(n=80\)

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