/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 153 Approval Rating for Congress In ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Approval Rating for Congress In a Gallup poll \(^{42}\) conducted in August \(2010,\) a random sample of \(n=1013\) American adults were asked "Do you approve or disapprove of the way Congress is handling its job?" The proportion who said they approve is \(\hat{p}=0.19,\) and a \(95 \%\) confidence interval for Congressional job approval is 0.166 to 0.214 . If we use a \(5 \%\) significance level, what is the conclusion if we are: (a) Testing to see if there is evidence that the job approval rating is different than \(20 \%\). (This happens to be the average sample approval rating from the six months prior to this poll.) (b) Testing to see if there is evidence that the job approval rating is different than \(14 \%\). (This happens to be the lowest sample Congressional approval rating Gallup ever recorded through the time of the poll.)

Short Answer

Expert verified
For the test regarding a job approval rating of 20%, there is not enough evidence to conclude that the approval rating is different from this value. Hence, the conclusion is that the approval rating could be 20%. For the test regarding a job approval rating of 14%, there is enough evidence to conclude that the approval rating is different from this value. Therefore, the approval rating is likely not 14%.

Step by step solution

01

Setting Up the Hypotheses

For both questions, we need to set up the null and alternative hypotheses. The null hypothesis will state that the population proportion (\(p\)) is equal to the given hypothesized approval rate, and the alternative hypothesis will state that the population proportion is different than the hypothesized approval rate.\n\n(a) Here, the null hypothesis (\(H_0\)) is \(p = 0.20\), and the alternative hypothesis (\(H_a\)) is \(p \neq 0.20\).\n(b) For this part, the null hypothesis (\(H_0\)) is \(p = 0.14\), and the alternative hypothesis (\(H_a\)) is \(p \neq 0.14\).
02

Comparing The Sample Proportion to Hypothesized Values

Next, we need to compare the sample proportion (\(\hat{p}=0.19\)) and 95% confidence interval (0.166, 0.214) to the hypothesized value in each scenario.\n\n(a) For \(p = 0.20\), we see that this value lies within the 95% confidence interval for the sample proportion. Therefore, we do not have evidence to reject the null hypothesis.\n(b) Conversely, for \(p = 0.14\), this value lies outside the 95% confidence interval for the sample proportion. Therefore, we have evidence to reject the null hypothesis.
03

Drawing Conclusions

Finally, based on the results from the comparison, we draw conclusions.\n\n(a) Since we do not have evidence to reject the null hypothesis that \(p = 0.20\), we fail to reject the null hypothesis. This means there is not enough evidence to conclude the job approval rating is different than 20%.\n(b) Since we do have evidence to reject the null hypothesis that \(p = 0.14\), we reject the null hypothesis. This means there is evidence to conclude the job approval rating is different than 14%.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null and Alternative Hypotheses
Understanding the null and alternative hypotheses is crucial in hypothesis testing. In the context of the exercise, the null hypothesis (\(H_0\)) represents the default position or status quo, suggesting that there is no difference or effect. It posits that the approval rating for Congress is equal to a specific value, based on what has been historically observed.

For instance, when testing against an approval rate of 20%, \(H_0: p = 0.20\) assumes that there has been no change. On the other hand, the alternative hypothesis (\(H_a\) or \(H_1\) challenges this by positing that the approval rating is not equal to the historical average; \(H_a: p eq 0.20\) in part (a).

This alternate stance is what researchers aim to support with evidence from data. Increasing or declining approval ratings would indicate significant changes in public opinion, hence the importance of the alternative hypothesis in driving investigations.
Confidence Interval
A confidence interval is a range of values used to estimate the true population parameter, such as a mean or proportion. It is constructed from sample data and gives a range within which we are 'confident' the true parameter lies. The exercise provides a 95% confidence interval for Congressional job approval, which ranges from 0.166 to 0.214.

This interval indicates that if the same poll were conducted again and again, 95% of the time, the calculated confidence intervals from those polls would contain the true population proportion of approval for Congress. Since confidence intervals capture the uncertainty in estimation, they are more informative than single point estimates like \(\hat{p}\).

Interpreting the Confidence Interval

When considering if a hypothesized value like 20% is supported by data, seeing that value within the 95% confidence interval suggests there's no substantial reason to doubt the hypothesized rate, as is the case in part (a) of the exercise.
Sample Proportion
The sample proportion (\(\hat{p}\)) is the estimated proportion of the population that has a particular characteristic, based on sampled data. It is calculated by dividing the number of individuals in the sample with the characteristic by the total sample size. In our example, \(\hat{p}=0.19\) indicates that 19% of the sampled adults approve of Congress's job.

Importance of Sample Proportion

Sample proportion acts as the empirical evidence against which hypotheses are tested. It is crucial in calculating confidence intervals and test statistics, and making decisions about hypotheses. Its accuracy depends on the randomness of the sample and the sample size, among other factors.
Significance Level
The significance level (\(\alpha\)) is the probability of making a type I error, which occurs when the null hypothesis is wrongly rejected when it is actually true. A 5% significance level, as used in this exercise, means there is a 5% risk of concluding that a difference exists when there is none.

Determining the significance level is part of designing a hypothesis test and sets the threshold for how extreme sample results must be to reject the null hypothesis. It is a crucial decision point, as a low significance level reduces the risk of type I errors but increases the risk of type II errors (failing to reject a false null hypothesis).

Role in Hypothesis Testing

The selected significance level influences the construction of confidence intervals and test statistic cutoffs. For example, had the significance level been 1%, our conclusions about Congressional job approval could differ because a more stringent criterion for rejecting the null hypothesis would be applied.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Car Window Skin Cancer? A new study suggests that exposure to UV rays through the car window may increase the risk of skin cancer. \(^{43}\) The study reviewed the records of all 1050 skin cancer patients referred to the St. Louis University Cancer Center in 2004 . Of the 42 patients with melanoma, the cancer occurred on the left side of the body in 31 patients and on the right side in the other 11 . (a) Is this an experiment or an observational study? (b) Of the patients with melanoma, what proportion had the cancer on the left side? (c) A bootstrap \(95 \%\) confidence interval for the proportion of melanomas occurring on the left is 0.579 to \(0.861 .\) Clearly interpret the confidence interval in the context of the problem. (d) Suppose the question of interest is whether melanomas are more likely to occur on the left side than on the right. State the null and alternative hypotheses. (e) Is this a one-tailed or two-tailed test? (f) Use the confidence interval given in part (c) to predict the results of the hypothesis test in part (d). Explain your reasoning. (g) A randomization distribution gives the p-value as 0.003 for testing the hypotheses given in part (d). What is the conclusion of the test in the context of this study? (h) The authors hypothesize that skin cancers are more prevalent on the left because of the sunlight coming in through car windows. (Windows protect against UVB rays but not UVA rays.) Do the data in this study support a conclusion that more melanomas occur on the left side because of increased exposure to sunlight on that side for drivers?

In Exercises 4.107 to \(4.111,\) null and alternative hypotheses for a test are given. Give the notation \((\bar{x},\) for example) for a sample statistic we might record for each simulated sample to create the randomization distribution. $$ H_{0}: p=0.5 \text { vs } H_{a}: p \neq 0.5 $$

A situation is described for a statistical test. In each case, define the relevant parameter(s) and state the null and alternative hypotheses. Testing to see if there is evidence that a correlation between height and salary is significant (that is, different than zero)

In Exercises 4.150 to \(4.152,\) a confidence interval for a sample is given, followed by several hypotheses to test using that sample. In each case, use the confidence interval to give a conclusion of the test (if possible) and also state the significance level you are using. A 99\% confidence interval for \(\mu: 134\) to 161 (a) \(H_{0}: \mu=100\) vs \(H_{a}: \mu \neq 100\) (b) \(H_{0}: \mu=150\) vs \(H_{a}: \mu \neq 150\) (c) \(H_{0}: \mu=200\) vs \(H_{a}: \mu \neq 200\)

Indicate whether the analysis involves a statistical test. If it does involve a statistical test, state the population parameter(s) of interest and the null and alternative hypotheses. Testing 100 right-handed participants on the reaction time of their left and right hands to determine if there is evidence for the claim that the right hand reacts faster than the left.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.