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91Ó°ÊÓ

In estimating the mean score on a fitness exam, we use an original sample of size \(n=30\) and a bootstrap distribution containing 5000 bootstrap samples to obtain a \(95 \%\) confidence interval of 67 to 73 . In Exercises 3.90 to 3.95 , a change in this process is described. If all else stays the same, which of the following confidence intervals \((A, B,\) or \(C)\) is the most likely result after the change: \(\begin{array}{lll}A .66 \text { to } 74 & B .67 \text { to } 73 & \text { C. } 67.5 \text { to } 72.5\end{array}\) Using an original sample of size \(n=45\)

Short Answer

Expert verified
If everything else stays the same and the sample size is increased to 45, the most likely confidence interval is option C: 67.5 to 72.5.

Step by step solution

01

Understand the difference resulting from a larger sample size

When a larger sample size (from 30 to 45) is used, the standard error of the estimated mean decreases. Therefore, we should expect our new confidence interval to be narrower than the original one (67 to 73).
02

Examine the confidence intervals

The given options for confidence intervals are 66 to 74 (A), 67 to 73 (B), or 67.5 to 72.5 (C). Option A is wider than the original, contradicting our expectation. Option B is exactly same as the original, which also doesn't align with our expectation that the interval should be narrower. Option C is narrower than the original, meeting our expectation.
03

Choose the most likely confidence interval

From Step 2, it's clear that the most likely confidence interval when we increase the sample size to 45 is option C (67.5 to 72.5). This narrower interval suggests a greater precision in estimating our parameter due to the increased sample size.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bootstrap Distribution
The bootstrap distribution is a fundamental concept in statistics, particularly for estimating unknown parameters in a population. At its core, bootstrapping involves repeatedly sampling, with replacement, from the original dataset to create numerous 'bootstrap' samples. This process mimics the sampling distribution of a statistic, such as the mean, when you don't have access to the larger population data.

The power of the bootstrap lies in its simplicity and flexibility. It doesn't rely on assumptions about the data's distribution. Instead, it uses the actual sample data to infer the underlying properties of the population. For example:

  • By generating a large number of bootstrap samples, a distribution of the statistic of interest is created.
  • This distribution allows for the estimation of confidence intervals and standard errors.
  • It helps understand the variability and stability of the statistics derived from our sample.

In our exercise, a 5000-sample bootstrap distribution was used to estimate a confidence interval. This large number of samples ensures a more reliable estimation by capturing the possible variations in the dataset.
Sample Size
Sample size plays a pivotal role in determining the accuracy of statistical estimates. In simple terms, it refers to the number of observations or data points collected during a study. A larger sample size generally leads to more precise and stable estimates. This occurs because of the way sample size affects variability and the standard error.

Consider these points about sample size:

  • Increasing the sample size usually decreases the standard error, since more data generally provides a clearer picture of the population's characteristics.
  • A larger sample helps in reducing the width of the confidence interval, resulting in more precise estimates.

In the original problem, increasing the sample size from 30 to 45 led to a narrower confidence interval. This adjustment signifies higher precision, as the interval of 67.5 to 72.5 reflects greater certainty about the mean fitness score, compared to the previous wider interval of 67 to 73.
Standard Error
Standard error is a measure of how much a sample statistic, like the mean, is expected to vary from the true population mean. It is crucial in understanding the variability and reliability of the statistic derived from a sample. The standard error is calculated as the standard deviation of the sampling distribution of the statistic divided by the square root of the sample size: \[ SE = \frac{\sigma}{\sqrt{n}} \] where \( \sigma \) is the standard deviation of the population and \( n \) is the sample size.

Important aspects of standard error include:

  • A smaller standard error indicates greater reliability of the sample mean as an estimate of the population mean.
  • A decreased standard error results in a narrower confidence interval, providing a more precise estimate.

In our case, when the sample size was increased to 45, the standard error decreased. This reduction led to a narrower confidence interval of 67.5 to 72.5, highlighting more precise estimation of the population mean.
Estimation
Estimation in statistics refers to the process of inferring the properties of an entire population based on a sample. Essentially, it is about making educated guesses concerning population parameters. Confidence intervals are a key tool in estimation, providing a range within which a population parameter likely lies.

Why estimation is important:

  • It allows us to infer information about a population without surveying every member, saving time and resources.
  • This process provides bounds (confidence intervals) around the estimate, which indicate the reliability of the estimations.

In our problem, estimation was used to determine the mean score of a fitness exam. By increasing the sample size, the estimates became more precise, and the confidence interval narrowed. This reflects how population parameter estimation benefits from more comprehensive data, thereby enhancing the reliability of decisions based on such estimates.

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Most popular questions from this chapter

In estimating the mean score on a fitness exam, we use an original sample of size \(n=30\) and a bootstrap distribution containing 5000 bootstrap samples to obtain a \(95 \%\) confidence interval of 67 to 73 . In Exercises 3.90 to 3.95 , a change in this process is described. If all else stays the same, which of the following confidence intervals \((A, B,\) or \(C)\) is the most likely result after the change: \(\begin{array}{lll}A .66 \text { to } 74 & B .67 \text { to } 73 & \text { C. } 67.5 \text { to } 72.5\end{array}\) Using the data to find a \(99 \%\) confidence interval.

Information about a sample is given. Assuming that the sampling distribution is symmetric and bell-shaped, use the information to give a \(95 \%\) confidence interval, and indicate the parameter being estimated. $$ \hat{p}=0.32 \text { and the standard error is } 0.04 . $$

Give information about the proportion of a sample that agree with a certain statement. Use StatKey or other technology to find a confidence interval at the given confidence level for the proportion of the population to agree, using percentiles from a bootstrap distribution. StatKey tip: Use "CI for Single Proportion" and then "Edit Data" to enter the sample information. Find a \(95 \%\) confidence interval if 180 agree in a random sample of 250 people.

Topical Painkiller Ointment The use of topical painkiller ointment or gel rather than pills for pain relief was approved just within the last few years in the US for prescription use only. \(^{12}\) Insurance records show that the average copayment for a month's supply of topical painkiller ointment for regular users is \(\$ 30 .\) A sample of \(n=75\) regular users found a sample mean copayment of \(\$ 27.90\). (a) Identify each of 30 and 27.90 as a parameter or a statistic and give the appropriate notation for each. (b) If we take 1000 samples of size \(n=75\) from the population of all copayments for a month's supply of topical painkiller ointment for regularusers and plot the sample means on a dotplot, describe the shape you would expect to see in the plot and where it would be centered. (c) How many dots will be on the dotplot you described in part (b)? What will each dot represent?

Playing Video Games A new study provides some evidence that playing action video games strengthens a person's ability to translate sensory information quickly into accurate decisions. Researchers had 23 male volunteers with an average age of 20 look at moving arrays on a computer screen and indicate the direction in which the dots were moving. \(^{26}\) Half of the volunteers (11 men) reported playing action video games at least five times a week for the previous year, while the other 12 reported no video game playing in the previous year. The response time and the accuracy score were both measured. A \(95 \%\) confidence interval for the mean response time for game players minus the mean response time for non-players is -1.8 to -1.2 seconds, while a \(95 \%\) confidence interval for mean accuracy score for game players minus mean accuracy score for non-players is -4.2 to +5.8 . (a) Interpret the meaning of the \(95 \%\) confidence interval for difference in mean response time. (b) Is it likely that game players and non-game players are basically the same in response time? Why or why not? If not, which group is faster (with a smaller response time)? (c) Interpret the meaning of the \(95 \%\) confidence interval for difference in mean accuracy score. (d) Is it likely that game players and non-game players are basically the same in accuracy? Why or why not? If not, which group is more accurate?

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