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In a survey of 1000 randomly selected adults in the United States, participants were asked what their most favorite and what their least favorite subject was when they were in school (Associated Press, August 17 . 2005)\(.\) In what might seem like a contradiction, math was chosen more often than any other subject in both categories! Math was chosen by 230 of the 1000 as the favorite subject, and it was also chosen by 370 of the 1000 as the least favorite subject. a. Construct a \(95 \%\) confidence interval for the proportion of U.S. adults for whom math was the favorite subject in school. b. Construct a \(95 \%\) confidence interval for the proportion of U.S. adults for whom math was the least favorite subject.

Short Answer

Expert verified
The 95% confidence interval for the proportion of U.S. adults for whom Math was the favorite subject in school is 0.23 ± 0.0196458. The 95% confidence interval for the proportion of U.S. adults for whom Math was the least favorite subject is 0.37 ± 0.0280806

Step by step solution

01

Understanding the Confidence Interval

A confidence interval is a range of values, derived from a data set, that is likely to contain the value of an unknown population parameter. To construct a 95% confidence interval for the proportion, we use the following formula: \[ CI = \hat{p} \pm Z_{\alpha/2} \sqrt{ \frac{\hat{p}(1-\hat{p})}{n}} \] Where, \( \hat{p} \) is the sample proportion, \( Z_{\alpha/2} \) is the z-score for a 95% level of confidence (1.96) and \( n \) is the sample size.
02

Construct the 95% Confidence Interval for the Favorite Subject

Substitute \( \hat{p} = 230/1000 = 0.23 \), \( n = 1000 \) and \( Z_{\alpha/2} = 1.96 \) into the formula. This gives us: \[ CI = 0.23 \pm 1.96 \sqrt{ \frac{0.23(1-0.23)}{1000}} \] Calculate the square root part of the interval then multiply by 1.96 (the z-score). Subtract and add the result from/to the sample proportion (0.23) to find the confidence interval.
03

Construct the 95% Confidence Interval for the Least Favorite subject

Similar to step 2, we replace \( \hat{p} \) with the proportion calculated for the least favorite subject. Substituting \( \hat{p} = 370/1000 = 0.37 \), \( n = 1000 \) and \( Z_{\alpha/2} = 1.96 \) into the formula. We can then calculate the limits of the confidence interval as we did in previous step. \[ CI = 0.37 \pm 1.96 \sqrt{ \frac{0.37(1-0.37)}{1000}} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
When we talk about a sample proportion, we refer to the fraction of individuals in a selected sample that exhibit a particular trait or characteristic. For instance, in the context of the textbook exercise, the survey involved 1000 randomly selected US adults, and the sample proportion for those who favored math can be calculated by dividing the number of people who preferred math by the total sample size.

In formulas, the sample proportion is represented as \( \hat{p} \), where \( \hat{p} = \frac{x}{n} \). The 'x' is the number of successes (people who chose math as their favorite subject in this case), and 'n' is the total number of observations in the sample. Hence, with 230 out of 1000 respondents preferring math, the sample proportion is 0.23.

Understanding sample proportions is essential because it gives us an insight into the preference structure of the population from which the sample was drawn. This proportion can then be used as a statistic to estimate the population parameter, which is the corresponding proportion that would be obtained if the entire population were surveyed.
Z-Score
A z-score is a statistical measurement that describes a value's relationship to the mean of a group of values, measured in terms of standard deviations from the mean. In simpler terms, it's a way to measure how many standard deviations an element is from the average.

In the construction of confidence intervals, the z-score helps us to determine how confident we can be that the population parameter falls within a certain range. For a 95% confidence level, the z-score is commonly found to be 1.96. This means that the actual population proportion is expected to fall within 1.96 standard deviations of our sample proportion 95% of the time.

To utilize the z-score in constructing confidence intervals, we multiply it by the standard error of the proportion, which then determines the margin of error. The margin of error is added to and subtracted from the sample proportion, giving us the lower and upper bounds of the confidence interval.
Population Parameter
The term population parameter is used to denote a characteristic or measure that can be quantified for a given population. It could be a mean, proportion, standard deviation, etc., that describes some aspect of the total population. In the context of the textbook exercise, the parameter of interest is the true proportion of U.S. adults for whom math was the favorite or the least favorite subject in school.

Once we have data from a sample, we use statistical methods to estimate the population parameter. However, it's crucial to remember that we rarely, if ever, know the true population parameter. Instead, we use sample data to construct a confidence interval that we believe, with a certain level of confidence, encompasses the true population parameter.

The confidence interval does not absolutely guarantee that the population parameter lies within it, but it gives a range where the parameter is likely to be found, based on our sample data and the chosen confidence level.
Statistical Inference
The concept of statistical inference involves drawing conclusions about a population based on sample data. One of the most common forms of statistical inference is constructing confidence intervals, as seen in the exercise, to estimate a population parameter like a mean or a proportion.

Statistical inference allows researchers to make probable conclusions about large populations using smaller sets of data, rather than having to survey everyone. The confidence interval is a tool that quantifies the uncertainty in these inferences. A 95% confidence interval, for instance, suggests that if the same sampling process were repeated many times, approximately 95 out of every 100 calculated confidence intervals would be expected to contain the true population parameter.

It's essential to realize that the concept of confidence level comes from the method of calculation and the underlying assumptions about the distribution of the sample statistics, not from the particular sample itself. The ultimate goal of statistical inference is to provide a reasonable and scientifically sound estimate about a population characteristic, based on sampled data.

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Most popular questions from this chapter

An Associated Press article on potential violent behavior reported the results of a survey of 750 workers who were employed full time iSan Luls Obispo Tribune. September \(7,\) 1999), Of those surveyed, 125 indicated that they were so angered by a coworker during the past year that they felt like hitting the coworker (but didn't). Assuming that it is reasonable to regard this sample of 750 as a random sample from the population of full-time workers, use this information to construct and interpret \(90 \%\) confidence interval estimate of \(p,\) the true proportion of full-time workers so angered in the last year that they wanted to hit a colleague.

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In the article "Fluoridation Brushed Off by Utah" (Associated Press, August 24, 1998 ), it was reported that a small but vocal minority in Utah has been successful in keeping fluoride out of Utah water supplies despite evidence that fluoridation reduces tooth decay and despite the fact that a dear majority of Utah residents favor fluoridation. To support this statement, the artide included the result of a survey of Utah residents that found \(65 \%\) to be in favor of fluoridation. Suppose that this result was based on a random sample of 150 Utah residents, Construct and interpret a \(90 \%\) confidence interval for \(p\), the true proportion of Utah residents who favor fluoridation. Is this interval consistent with the statement that fluoridation is favored by a clear majority of residents?

According to an AP-lpsos poll (June 15,2005\()\), \(42 \%\) of 1001 randomly selected adult Americans made plans in May 2005 based on a weather report that turned out to be wrong. a. Construct and interpret a 9996 confidence interval for the proportion of Americans who made plans in May 2005 based on an incorrect weather report. b. Do you think it is reasonable to generalize this estimate to other months of the year? Explain.

For each of the following choices, explain which would result in a wider large-sample confidence interval for \(p\) : a. \(90 \%\) confidence level or \(95 \%\) confidence level b. \(n=100\) or \(n=400\)

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