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The study "Digital Footprints" (Pew Internet \& American Life Project, www.pewinternet.org. 2007\()\) reported that \(47 \%\) of Internet users have searched for information about themselves online. The \(47 \%\) figure was based on a random sample of Internet users. For purposes of this exercise, suppose that the sample size was \(n=300\) (the actual sample size was much larger). Construct and interpret a \(90 \%\) confidence interval for the proportion of Internet users who have searched online for information about themselves.

Short Answer

Expert verified
For example, if the calculated confidence interval came out as (0.42, 0.52), it would mean there is a 90% level of confidence that the proportion of Internet users who have searched online for themselves is between 42% and 52%.

Step by step solution

01

Determine the sample proportion and size

The sample proportion (p) of Internet users who have searched online for information about themselves is given as \(p = 0.47\). The sample size (n) is given as \(n = 300\).
02

Identify the confidence level

The problem requires a 90% confidence interval, which means the confidence level (c) is \(c = 0.90\). The critical value for a 90% confidence level is \(Z=1.645\) when using a standard normal (Z) distribution.
03

Calculate the confidence interval

The formula for the confidence interval of a proportion is \[\(p \pm Z \sqrt{ (p(1 - p) \div n)}\], where \(\sqrt{ (p(1 - p) \div n)}\) is the standard deviation of the proportion. Substituting the known values gives \[0.47 \pm 1.645\sqrt{(0.47 \times 0.53) \div 300}\]. Calculating this expression will give the lower and upper limits of the confidence interval.
04

Interpret the confidence interval

Once calculated, the 90% confidence interval will provide an estimate of the range within which the true proportion of Internet users who have searched for information about themselves online falls 90% of the time.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
A sample proportion is a key statistical concept used to make inferences about a population based on a sample. It's a simple ratio, obtained by dividing the number of favorable outcomes in a sample by the total number of observations in the sample.For instance, in the given study, 47% of the Internet users sampled had searched for information about themselves. This directly gives us the sample proportion,which is calculated as \( p = \frac{x}{n} \), where \( x \) is the count of favorable outcomes, and \( n \) is the sample size.
  • In this example: \( p = 0.47 \)
  • Sample size \( n = 300 \)
Understanding this concept is essential because it forms the basis for constructing confidence intervals and other statistical analyses.Thus, the sample proportion serves as an estimate of the unknown actual proportion in the population.This metric is fundamental in statistical sampling and critical in determining the likelihood of various outcomes when generalizing from the sample to the larger population.
Critical Value
The critical value is an essential component in constructing confidence intervals.It represents the point on the standard normal distribution that corresponds with the desired confidence level. In this context, we're aiming for a 90% confidence level. To find the critical value for our confidence interval, we refer to the standard normal (\( Z \)) distribution.
  • For a 90% confidence interval, the critical value is typically \( Z = 1.645 \).
This value can be located using a standard normal distribution table or a statistical calculator.Knowing the critical value is crucial because it determines the width of the confidence interval. Larger critical values will result in wider intervals, providing a more conservative estimate of where the true proportion might fall.The critical value helps you gauge how sure you can be about your interval estimation, making it a fundamental part of inferential statistics.
Standard Normal Distribution
The standard normal distribution is a special type of normal distribution with a mean of 0 and a standard deviation of 1.It plays a vital role in statistics, especially in scenarios that involve standardizing other normal distributions for comparison and analysis.In the context of confidence intervals, the standard normal distribution helps translate the confidence level into a critical value.
When sample sizes are large, the distribution of sample proportions approximates the standard normal.This approximation permits the application of \( Z \)-scores to calculate confidence intervals and perform hypothesis testing.For instance:
  • A 90% confidence interval requires a \( Z \)-score from the distribution, which is \( 1.645 \)
Understanding the standard normal distribution is key to accurately interpreting statistical results and ensuring valid inferences about populations from sample data.Its role in standardizing data means that we can compare results across different studies and ensure consistency in data analysis.
Standard Deviation of the Proportion
The standard deviation of the proportion, often called the "standard error," provides a measure of the variability or spread of the sample proportion relative to the true population proportion.It's essential in calculating the confidence interval, helping determine the margin of error for the estimate.
The formula to calculate this is:\[\text{Standard deviation of the proportion} = \sqrt{ \frac{p(1-p)}{n} }\]where \( p \) is the sample proportion and \( n \) is the sample size.
  • In this exercise: \( p = 0.47 \), \( n = 300 \)
The standard deviation of the proportion indicates how much the sample proportion is expected to fluctuate from the actual population proportion.It allows us to compute the range, or confidence interval, in which the true proportion likely exists.This is crucial as it offers insight into the reliability of our sample proportion and helps in making sound statistical conclusions.

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Most popular questions from this chapter

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