/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 A pizza shop sells pizzas in fou... [FREE SOLUTION] | 91Ó°ÊÓ

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A pizza shop sells pizzas in four different sizes. The 1000 most recent orders for a single pizza gave the following proportions for the various sizes: \(\begin{array}{lllll}\text { Size } & 12 \text { in. } & 14 \text { in. } & 16 \text { in. } & 18 \text { in. }\end{array}\) Proportion \(\begin{array}{cccc}.20 & .25 & .50 & .05\end{array}\) With \(x\) denoting the size of a pizza in a single-pizza order, the given table is an approximation to the population distribution of \(x\). a. Construct a relative frequency histogram to represent the approximate distribution of this variable. b. Approximate \(P(x<16)\). c. Approximate \(P(x \leq 16)\). d. It can be shown that the mean value of \(x\) is approximately 14.8 inches. What is the approximate probability that \(x\) is within 2 inches of this mean value?

Short Answer

Expert verified
a. The relative frequency histogram can be draw with pizza sizes on the x-axis and proportions on the y-axis. b. \(P(x<16) = .45\), c. \(P(x \leq 16) = .95\), d. The probability that \(x\) falls between 12.8 and 16.8 inches (within 2 inches of the mean) is .75.

Step by step solution

01

Constructing Relative Frequency Histogram

The histogram can be drawn with pizza sizes (12, 14, 16 and 18 inches) on the x-axis and their corresponding proportions (.20, .25, .50, and .05) on the y-axis. Draw rectangles with these heights at their respective x-values (pizza sizes).
02

Approximating \(P(x

To approximate \(P(x<16)\), sum the proportions of sizes less than 16. So, \(P(x<16) = P(12) + P(14) = .20 + .25 = .45\)
03

Approximating \(P(x \leq 16)\)

To approximate \(P(x\leq16)\), include the proportion of 16 along with sizes less than 16. So, \(P(x\leq16) = P(x<16) + P(16) = .45 + .50 = .95\)
04

Probablity within 2 inches of the mean

Pizza sizes within 2 inches of the mean value (14.8) are 14 inches and 16 inches. So, calculate the sum of their proportions. Therefore, \(P(12.8 <= x <= 16.8) = P(14) + P(16) = .25 + .50 = .75\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relative Frequency Histogram
The relative frequency histogram is a visual representation of the probability distribution for a discrete random variable, such as the size of a pizza. It is similar to a typical bar chart, except that it shows the relative frequency (or proportion) of the data falling into each category.

To create this type of histogram, one would plot the sizes of the pizzas on the horizontal axis (the x-axis) and their corresponding proportions or relative frequencies on the vertical axis (the y-axis). Each pizza size category would have a bar (or rectangle) whose height represents the proportion of orders for that size. For example, in the problem statement, the 12-inch pizza would be represented by a bar with a height of 0.20 since 20% of the recent orders were for that size. Similarly, heights of 0.25, 0.50, and 0.05 would represent the 14-inch, 16-inch, and 18-inch pizzas respectively. This visual tool is invaluable for quickly understanding how the sizes of pizzas are distributed among the orders.
Cumulative Probability
Cumulative probability refers to the probability that a random variable is less than or equal to a particular value. It gives us insight into the likelihood of a variable falling within a certain range up to a point. In this case, the exercise requires calculating the cumulative probability of pizza orders being less than 16 inches and less than or equal to 16 inches.

To calculate cumulative probability, you sum up the probabilities of all outcomes up to and including the one of interest. For example, to find \(P(x<16)\), one would add the probabilities of ordering a 12-inch pizza and a 14-inch pizza, which ultimately equals 0.45 or 45%. If one wants to calculate \(P(x \<= 16)\), one would include the probability of the 16-inch pizza in the sum as well, leading to a cumulative probability of 0.95, or 95%. This gives customers a comprehensive idea of the likelihood of ordering pizza sizes up to 16 inches.
Mean Value Approximation
The mean value approximation in a probability distribution is an estimate of the 'center' or 'average' outcome. It provides a single number that summarizes the central tendency of the data. In our pizza shop example, the mean size of an ordered pizza is given as approximately 14.8 inches.

One common question is: what is the probability that an observation is within a certain range around this mean? In the provided exercise, the task is to approximate the probability that the size of a pizza \(x\) is within 2 inches of this mean value, thus between 12.8 inches and 16.8 inches. Since only 14 inches and 16 inches fall within this range, we add their probabilities, resulting in 0.75 or 75%. This method of approximation gives us a way to understand variability relative to the mean, offering practical insights into the spread of the data around the average value.

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Most popular questions from this chapter

Suppose that fund-raisers at a university call recent graduates to request donations for campus outreach programs. They report the following information for last year's graduates: $$ \begin{array}{lllll} \text { Size of donation } & \$ 0 & \$ 10 & \$ 25 & \$ 50 \\ \text { Proportion of calls } & .45 & .30 & .20 & .05 \end{array} $$ Three attempts were made to contact each graduate; a donation of \(\$ 0\) was recorded both for those who were contacted but who declined to make a donation and for those who were not reached in three attempts. Consider the variable \(x=\) amount of donation for the population of last year's graduates of this university. a. Construct a relative frequency histogram to represent the population distribution of this variable. b. What is the most common value of \(x\) in this population? c. What is \(P(x \geq 25)\) ? d. What is \(P(x>0)\) ?

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Consider the following sample of 25 observations on the diameter \(x\) (in centimeters) of a disk used in a certain system. \(\begin{array}{llllll}16.01 & 16.08 & 16.13 & 15.94 & 16.05 & 16.27 \\ 15.89 & 15.84 & 15.95 & 16.10 & 15.92 & 16.04 \\ 15.82 & 16.15 & 16.06 & 15.66 & 15.78 & 15.99 \\ 16.29 & 16.15 & 16.19 & 16.22 & 16.07 & 16.13\end{array}\) 6

Homicide rate (homicides per 100,000 population) for each of the 50 states appeared in the 2010 Statistical Abstract (www.census.gov). A frequency distribution constructed from the 50 observations is shown in the following table: $$ \begin{array}{cc} \text { Homicide Rate } & \text { Frequency } \\ \hline 0 \text { to }<3 & 14 \\ 3 \text { to }<6 & 18 \\ 6 \text { to }<9 & 16 \\ 9 \text { to }<12 & 1 \\ 12 \text { to }<15 & 1 \\ \hline \end{array} $$ a. Calculate the relative frequency and density for each of the seven intervals in the frequency distribution. Use the computed densities to construct a density histogram for the variable \(x=\) homicide rate for the population consisting of the 50 states. b. Is the population distribution symmetric or skewed? c. Use the population distribution to determine the following probabilities. i. \(P(x \geq 12)\) ii. \(P(x<9)\) iii. \(P(6 \leq x<12)\)

The paper “Risk Behavior, Decision Making, and Music Genre in Adolescent Males" (Marshall University, May 2009 ) examined the effect of type of music playing and performance on a risky, decision-making task. a. Participants in the study responded to a questionnaire that was used to assign a risk behavior score. Risk behavior scores (read from a graph that appeared in the paper) for 15 participants follow. Use these data to construct a normal probability plot (the normal scores for a sample size of 15 appear in the previous exercise). $$ \begin{array}{llllllll} 102 & 105 & 113 & 120 & 125 & 127 & 134 & 135 \\ 139 & 141 & 144 & 145 & 149 & 150 & 160 & \end{array} $$ b. Participants also completed a positive and negative affect scale (PANAS) designed to measure emotional response to music. PANAS values (read from a graph that appeared in the paper) for 15 participants follow. Use these data to construct a normal probability plot (the normal scores for a sample size of 15 appear in the previous exercise). $$ \begin{array}{llllllll} 36 & 40 & 45 & 47 & 48 & 49 & 50 & 52 \\ 53 & 54 & 56 & 59 & 61 & 62 & 70 & \end{array} $$ c. The author of the paper states that he believes that it is reasonable to consider both risk behavior scores and PANAS scores to be approximately normally distributed. Do the normal probability plots from Parts (a) and (b) support this conclusion? Explain.

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