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91Ó°ÊÓ

The time that it takes a randomly selected job applicant to perform a certain task has a distribution that can be approximated by a normal distribution with a mean value of 120 seconds and a standard deviation of 20 seconds. The fastest \(10 \%\) are to be given advanced training. What task times qualify individuals for such training?

Short Answer

Expert verified
The cut-off time that qualifies individuals for advanced training is 97.6 seconds.

Step by step solution

01

Identify Given Variables

In this exercise, the variables provided include the mean (\(\mu\)) and standard deviation (\(\sigma\)) of the task performance time. These are given as \(\mu = 120\) seconds and \(\sigma = 20\) seconds respectively. It's also mentioned that the distribution is normal and that the fastest 10% of individuals (which corresponds to the 10th percentile) are to be given advanced training.
02

Find the Z-score for the 10th Percentile

Using standard normal distribution tables, or a z-score calculator, find the z-score associated with the 10th percentile (P=0.10). The z-score is a measure of how many standard deviations an element is from the mean. In this case, it's approximately -1.28.
03

Calculate the Cut-off Time for Advanced Training

Use the z-score formula, which is \(Z = \frac{(X - \mu)}{\sigma}\), to solve for X (the cutoff time for advanced training). Here, \(Z = -1.28\), \(\mu = 120\) and \(\sigma = 20\). Rearranged, the formula becomes \( X = Z*\sigma + \mu \). Substituting the values gives \(X = -1.28*20 + 120\) , calculating this results in \( X= 97.6\), it means that to qualify for the advanced training, an individual has to perform the task in less than 97.6 seconds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Standard Deviation
When we talk about standard deviation, we're looking at a measure of how spread out numbers are in a set. Think of it as an average distance from the mean value, which is the typical average we're all familiar with. In the context of our exercise, the standard deviation helps us understand the variability in job applicants' task times.

Given a standard deviation of 20 seconds, what does this tell us? It means that the performances of most applicants will fall within 20 seconds of the average time, which is 120 seconds. However, not every applicant's time will be this close, as standard deviation only refers to the 'typical' deviation, not the maximum. By knowing the standard deviation, we can start to predict the range of times we might expect from all applicants.
Decoding the Z-score
The concept of a z-score might seem daunting, but it's essentially a way to pinpoint where a particular data point sits relative to the group. It tells us how many standard deviations away from the mean a value is.

In our exercise, we found a z-score of approximately -1.28 for the fastest 10% of applicants. This negative z-score indicates that the qualifying time for advanced training is below the average. Why does this matter? Because knowing the z-score allows us to make comparisons across different normal distributions, it's like having a universal measuring stick for all things 'normal'!
Percentiles Explained
Percentiles are another key concept in statistics. A percentile is a value below which a certain percent of observations fall. So, when we say the fastest 10%, we're referring to the 10th percentile; this is the time faster than which 10% of job applicants completed the task.

Understanding percentiles can be crucial, especially when determining benchmarks like what qualifies as 'advanced' performance. It's a way to rank scores in a population. If you're in the 90th percentile, for example, you've outperformed 90% of that population. This is a commonly used method in standardized testing and other assessment tools.
The Role of the Mean Value
Finally, let's circle back to the mean value. The mean is quite simply the average, and in a normal distribution, it's the center point where about half of the observations are expected to be above and half below.

In the task time exercise, the mean is the average time taken by all applicants, 120 seconds. It anchors the entire distribution, and combined with the standard deviation, it defines the shape and spread of the curve. Every other calculation, be it z-scores or percentiles, revolves around these two parameters. Remember, the mean isn't always the 'middle' in terms of the number of values since it can be skewed by extremely high or low numbers. Nevertheless, it's an essential starting point for analysis.

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Most popular questions from this chapter

Suppose that the distribution of typing speed in words per minute (wpm) for typists using a new type of split keyboard can be approximated by a normal curve with mean 60 wpm and standard deviation 15 wpm (The effects of Split Keyboard Geometry on Upper Body Postures," Ergonomics [2009]" 104-111). a. What is the probability that a randomly selected typist's net rate is at most 60 wpm? less than 60 wpm? b. What is the probability that a randomly selected typist's net rate is between 45 and 90 wpm? c. Would you be surprised to find a typist in this population whose net rate exceeded 105 wpm? (Note: The largest net rate in a sample described in the paper cited is 104 wpm.) d. Suppose that two typists are independently selected. What is the probability that both their typing rates exceed 75 wpm? e. Suppose that special training is to be made available to the slowest \(20 \%\) of the typists. What typing speeds would qualify individuals for this training?

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