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Let \(z\) denote a variable having a normal distribution with \(\mu=0\) and \(\sigma=1\). Determine each of the following probabilities: a. \(P(z<0.10)\) b. \(\quad P(z<-0.10)\) c. \(P(0.40-1.25)\) g. \(P(z<-1.50\) or \(z>2.50)\)

Short Answer

Expert verified
The probabilities are: a) 0.5398; b) 0.4602; c) 0.1469; d) 0.1469; e) 0.4577; f) 0.8944; g) 0.0730.

Step by step solution

01

Finding \(P(z

This is the probability that \(z\) is less than 0.10. Since \(z\) follows a standard normal distribution, this is equal to the CDF of the standard normal distribution at 0.10. Using the standard normal table or a calculator with a CDF function, we find that this is approximately 0.5398.
02

Finding \(P(z

This is the probability that \(z\) is less than -0.10. Using the standard normal table or a calculator with a CDF function, we find that this is approximately 0.4602.
03

Finding \(P(0.40

This is the probability that \(z\) is between 0.40 and 0.85. We find the probabilities \(P(z<0.85)\) and \(P(z<0.40)\), and subtract the latter from the former. Using a standard normal table or a calculator with a CDF function, we find that \(P(0.40<z<0.85) \approx 0.8023 - 0.6554 = 0.1469\).
04

Finding \(P(-0.85

Similar to Step 3, find the probabilities \(P(z<-0.40)\) and \(P(z<-0.85)\), and subtract the latter from the former. Using a standard normal table or a calculator with a CDF function, we find that \(P(-0.85<z<-0.40) \approx 0.3446 - 0.1977 = 0.1469\).
05

Finding \(P(-0.40

Similar to Steps 3 and 4, find the probabilities \(P(z<0.85)\) and \(P(z<-0.40)\), and subtract the latter from the former. Using a standard normal table or a calculator with a CDF function, we find that \(P(-0.40<z<0.85) \approx 0.8023 - 0.3446 = 0.4577\).
06

Finding \(P(z>-1.25)\)

This is the probability that \(z\) is greater than -1.25. Because the normal distribution is symmetrical, this probability is equivalent to \(P(z<1.25)\), i.e., the probability that \(z\) is less than 1.25. Using a standard normal table or a calculator with a CDF function, we find that this is approximately 0.8944.
07

Finding \(P(z2.50)\)

This is the probability that \(z\) is less than -1.50, or greater than 2.50. We calculate the individual probabilities and add them, since these are mutually exclusive events. Using a standard normal table or a calculator with a CDF function, we find that \(P(z<-1.50) \approx 0.0668\) and \(P(z>2.50) \approx 1 - P(z<2.50) = 1 - 0.9938 = 0.0062\). Therefore, \(P(z<-1.50\) or \(z>2.50) = 0.0668 + 0.0062 = 0.0730\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Normal Distribution
The standard normal distribution is a critical concept in statistics. It's a special case of the normal distribution where the mean (\( \mu \)) is equal to 0, and the standard deviation (\( \sigma \)) is equal to 1. This distribution is completely symmetric around the mean. It is often referred to simply as 'the Z distribution' or 'Z scores'.

Here are a few key points about the standard normal distribution:
  • Symmetrical Shape: It is bell-shaped and known as the Gaussian distribution.
  • Mean and Standard Deviation: The mean is 0 and the standard deviation is 1.
  • Area Under the Curve: Represents probabilities and is equal to 1.
  • Symmetry: The area under the curve to the left of the mean equals the area to the right, each accounting for 0.5 or 50% of the total area.
Understanding this distribution helps calculate probabilities and interpret statistical models effectively.
Probability
Probability is the measure of the likelihood that an event will occur. It is quantified as a number between 0 and 1, with 0 indicating an impossibility and 1 indicating certainty. A probability of 0.5 indicates that an event is as likely to occur as not.

When discussing normal distributions, such as the standard normal distribution, probability often relates to finding the likelihood of a variable falling within a certain range.

For example, if you read \( P(z < 0.10) \), it refers to the probability that a standard normal random variable \( z \) is less than 0.10. We determine probabilities using the cumulative distribution function, an essential aspect of probability assessments in normal distributions.
Cumulative Distribution Function
The cumulative distribution function (CDF) is a vital tool in statistics, especially when dealing with normal distributions. The CDF gives us the probability that a random variable \( z \) is less than or equal to a certain value.

The CDF for a standard normal distribution is often represented by \( \Phi(z) \). It accumulates probabilities from the left end (negative infinity) to the point of interest on the x-axis. This process effectively provides the area under the curve of a distribution up to that point.

Key aspects of the CDF:
  • Continuous Growth: As \( z \) increases, \( \Phi(z) \) increases from 0 to 1.
  • S-shaped Curve: Represents cumulative probability and is non-decreasing.
  • Use in Probability Calculations: Helps find probabilities and percentiles in the context of normal distribution.
The CDF is an essential concept for determining specific probabilities, such as \( P(z < 0.10) \) or \( P(0.40 < z < 0.85) \), in standard normal distribution problems.
Probability Calculations
Calculating probabilities for a standard normal distribution involves utilizing the cumulative distribution function (CDF) or standard normal distribution tables.

Here we break down the probability calculations involved:
  • Single Point Probability: For a single threshold, like \( P(z < 0.10) \), you locate the CDF at \( z = 0.10 \) to find the probability directly from a table or calculator.
  • Range Probability: For a range, such as \( P(0.40 < z < 0.85) \), determine the probability for each endpoint and subtract the lower endpoint from the upper endpoint.
  • Complex Events: For events like \( P(z < -1.50) \) or \( z > 2.50 \), calculate each component separately using the CDF and then combine the probabilities.
Each type of probability calculation relies on the standard normal distribution's properties and the CDF, allowing detailed probability determination within the curve's framework. This understanding is crucial for statistical analysis and data interpretation.

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Most popular questions from this chapter

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