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Houses in California are expensive, especially on the Central Coast where the air is clear, the ocean is blue, and the scenery is stunning. The median home price in San Luis Obispo County reached a new high in July 2004, soaring to \(\$ 452,272\) from \(\$ 387,120\) in March 2004\. (San Luis Obispo Tribune, April 28, 2004). The article included two quotes from people attempting to explain why the median price had increased. Richard Watkins, chairman of the Central Coast Regional Multiple Listing Services was quoted as saying, "There have been some fairly expensive houses selling, which pulls the median up." Robert Kleinhenz, deputy chief economist for the California Association of Realtors explained the volatility of house prices by stating: "Fewer sales means a relatively small number of very high or very low home prices can more easily skew medians." Are either of these statements correct? For each statement that is incorrect, explain why it is incorrect and propose a new wording that would correct any errors in the statement.

Short Answer

Expert verified
Both statements are conditionally correct. Richard's statement needs a caveat that home prices need to be evenly distributed. Robert's statement correctly identifies that fewer sales can cause extreme high or low home prices to significantly affect the median.

Step by step solution

01

Evaluating the first statement

Richard Watkins says that selling fairly expensive houses pulls the median up. This statement can be correct under certain conditions. If the data is organized in ascending or descending order, adding a higher value can shift the median up, especially if the number of data values is even.
02

Evaluating the second statement

Robert Kleinhenz's statement is that fewer sales could increase the influence of very high or very low home prices on the median. This is quite accurate because with fewer data points, any extreme values (either high or low) can significantly affect the position of the median.
03

Conclusional statement

Both statements seem valid under certain circumstances. However, they might lead to misunderstanding if not clarified properly. For the first statement, it might be more accurate to say, 'If expensive houses are sold and if the home prices are evenly distributed, it can potentially pull the median up.' For the second statement, it might be clearer to say, 'With fewer sales, a small number of extreme high or low home prices can cause significant changes to the median.'

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Median
In statistics, the median is a measure of central tendency that represents the middle value of a data set when it is ordered from the smallest to the largest value. The benefit of using the median is that it is less affected by extreme values, or outliers, than the mean. This makes the median a reliable measure for skewed distributions.

To find the median, follow these steps:
  • Arrange the data in numerical order from lowest to highest.
  • If the number of data points is odd, the median is the middle point.
  • If the number of data points is even, the median is the average of the two middle numbers.
For example, in a data set of house prices ranging from \(\\(200,000\) to \(\\)3,000,000\), sorting the data will help accurately compute the median. Hence, if highly expensive homes are added to this sorted list, they might not affect the median directly unless they shift the middle position in the ordered list.
Data Analysis
Data analysis is the process of inspecting, cleaning, and modeling data to discover useful information and inform conclusions. Understanding patterns and trends in data sets allows us to make informed predictions about future outcomes.

In the context of house prices, data analysis involves looking at various aspects, such as price trends, median prices, and sales volume. Analysts may question whether the change in median prices relates to an actual increase in home value or if it's influenced by other factors such as the inclusion of higher-priced properties in the data set. Insights from this analysis can help consumers, real estate agents, and policymakers understand broader market trends.
Outliers
Outliers are data points that differ significantly from other observations. They can drastically affect statistical calculations, including the mean, making the median a less sensitive measure of central tendency when outliers are present.

In real estate, outliers may be properties that are unusually cheap or exceptionally expensive compared to the rest of the market. These properties can skew average prices but have less impact on the median. When analyzing data, it's crucial to identify outliers to understand their effects on the overall data set.

For example, if a few luxury homes are sold at the high end of the market, they can inflate the average price, but the median might remain stable unless these prices begin to shift the middle value of the data. Recognizing the presence of outliers helps ensure that data analysis is not misleading. Proper handling of outliers ensures more reliable and valid conclusions can be drawn from the data.

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Most popular questions from this chapter

Give two sets of five numbers that have the same mean but different standard deviations, and give two sets of five numbers that have the same standard deviation but different means.

Consider the following statement: More than \(65 \%\) of the residents of Los Angeles earn less than the average wage for that city. Could this statement be correct? If so, how? If not, why not?

The standard deviation alone does not measure relative variation. For example, a standard deviation of \(\$ 1\) would be considered large if it is describing the variability from store to store in the price of an ice cube tray. On the other hand, a standard deviation of \(\$ 1\) would be considered small if it is describing store-to-store variability in the price of a particular brand of freezer. A quantity designed to give a relative measure of variability is the coefficient of variation. Denoted by CV, the coefficient of variation expresses the standard deviation as a percentage of the mean. It is defined by the \(C V=100\left(\frac{s}{\bar{x}}\right)\) formula Consider two samples. Sample 1 gives the actual weight (in ounces) of the contents of cans of pet food labeled as having a net weight of 8 ounces. Sample 2 gives the actual weight (in pounds) of the contents of bags of dry pet food labeled as having a net weight of 50 pounds. The weights for the two samples are \(\begin{array}{lrrrrr}\text { Sample 1 } & 8.3 & 7.1 & 7.6 & 8.1 & 7.6 \\ & 8.3 & 8.2 & 7.7 & 7.7 & 7.5 \\ \text { Sample 2 } & 52.3 & 50.6 & 52.1 & 48.4 & 48.8 \\ & 47.0 & 50.4 & 50.3 & 48.7 & 48.2\end{array}\) a. For each of the given samples, calculate the mean and the standard deviation. b. Compute the coefficient of variation for each sample. Do the results surprise you? Why or why not?

The report "Who Moves? Who Stays Put? Where's Home?" (Pew Social and Demographic Trends, December 17, 2008 ) gave the accompanying data for the 50 U.S. states on the percentage of the population that was born in the state and is still living there. The data values have been arranged in order from largest to smallest. \(\begin{array}{lllllllllll}75.8 & 71.4 & 69.6 & 69.0 & 68.6 & 67.5 & 66.7 & 66.3 & 66.1 & 66.0 & 66.0 \\ 65.1 & 64.4 & 64.3 & 63.8 & 63.7 & 62.8 & 62.6 & 61.9 & 61.9 & 61.5 & 61.1\end{array}\) \(\begin{array}{lllllllllll}59.2 & 59.0 & 58.7 & 57.3 & 57.1 & 55.6 & 55.6 & 55.5 & 55.3 & 54.9 & 54.7 \\ 54.5 & 54.0 & 54.0 & 53.9 & 53.5 & 52.8 & 52.5 & 50.2 & 50.2 & 48.9 & 48.7\end{array}\) \(\begin{array}{llllll}48.6 & 47.1 & 43.4 & 40.4 & 35.7 & 28.2\end{array}\) a. Find the values of the median, the lower quartile, and the upper quartile. b. The two smallest values in the data set are 28.2 (Alaska) and 35.7 (Wyoming). Are these two states outliers? c. Construct a boxplot for this data set and comment on the interesting features of the plot.

The Insurance Institute for Highway Safety (www.iihs.org, June 11,2009 ) published data on repair costs for cars involved in different types of accidents. In one study, seven different 2009 models of mini- and micro-cars were driven at 6 mph straight into a fixed barrier. The following table gives the cost of repairing damage to the bumper for each of the seven models. $$ \begin{array}{lc} \text { Model } & \text { Repair Cost } \\ \hline \text { Smart Fortwo } & \$ 1,480 \\ \text { Chevrolet Aveo } & \$ 1,071 \\ \text { Mini Cooper } & \$ 2,291 \\ \text { Toyota Yaris } & \$ 1,688 \\ \text { Honda Fit } & \$ 1,124 \\ \text { Hyundai Accent } & \$ 3,476 \\ \text { Kia Rio } & \$ 3,701 \\ \hline \end{array} $$ Compute the values of the mean and median. Why are these values so different? Which of the two-mean or median-appears to be better as a description of a typical value for this data set?

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