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Are college students who take a freshman orientation course more or less likely to stay in college than those who do not take such a course? The article "A Longitudinal Study of the Retention and Academic Performance of Participants in Freshmen Orientation Courses" (Journal of College Student Development [1994]: 444 - 449) reported that 50 of 94 randomly selected students who did not participate in an orientation course returned for a second year. Of 94 randomly selected students who did take the orientation course, 56 returned for a second year. Construct a \(95 \%\) confidence interval for \(\pi_{1}-\pi_{2}\), the difference in the proportion returning for students who do not take an orientation course and those who do. Give an interpretation of this interval.

Short Answer

Expert verified
The 95% confidence interval for the difference in proportions, \(\pi_{1}-\pi_{2}\), is computed as per the steps mentioned. The interpretation depends on whether or not the interval contains 0, indicating whether the difference between the two groups is statistically significant or not.

Step by step solution

01

Calculate Sample Proportions and Sample Sizes

Firstly, it's important to calculate the sample proportions and the sample sizes for both groups. For those who didn't take the course, the proportion \(p_1\) is given by \(\frac{50}{94}\) and the sample size \(n_1 = 94\). For those who did take the course, the proportion \(p_2\) is given by \(\frac{56}{94}\) and the sample size \(n_2 = 94\).
02

Calculate Difference in Sample Proportions

Subtract the two sample proportions \(p_1 - p_2\) to find the difference.
03

Calculate Standard Error

Next, calculate the standard error (SE) of the differences using the formula \(SE = \sqrt{\frac{p_1(1-p_1)}{n_1} + \frac{p_2(1-p_2)}{n_2}}\)
04

Compute the 95% Confidence Interval

The formula to calculate the 95% confidence interval is given by \((p_1-p_2) \pm 1.96*SE\), where 1.96 represents the z-score associated with a 95% confidence level.
05

Interpret the Confidence Interval

The resulting interval provides an estimate for the difference in the population proportions. If the interval does not contain 0, that indicates there is a significant difference between the proportions. If it does contain 0, that indicates the difference is not statistically significant.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportions
Understanding sample proportions is essential when assessing statistical data from a group within a larger population. In the context of retention rates for college students in relation to freshmen orientation, a sample proportion represents the percentage of students who return for a second year from those surveyed. Specifically, from students who did not take an orientation course, the sample proportion, denoted as \( p_1 \), is calculated by dividing the number of students who returned, which is 50, by the total number of surveyed students, 94, leading to \( p_1 = \frac{50}{94} \). Likewise, the sample proportion of students who did take the orientation course, \( p_2 \), is calculated as \( p_2 = \frac{56}{94} \).
Standard Error Calculation
The standard error (SE) is a measurement of the variability or dispersion of a sample statistic from the population parameter. To find the SE of the difference between two sample proportions, we employ the formula \( SE = \sqrt{\frac{p_1(1-p_1)}{n_1} + \frac{p_2(1-p_2)}{n_2}} \). Here, \( p_1 \) and \( p_2 \) are the sample proportions, while \( n_1 \) and \( n_2 \) represent the number of subjects in each sample. By inputting the values obtained from our samples, we obtain a numerical value that expresses the expected standard deviation of the differences in sample proportions if the same study were to be repeated multiple times.
Difference in Population Proportions
As we estimate the difference between two population proportions, we look at the difference in sample proportions from our observed data to provide insights. In the proposed scenario, we are looking to understand whether freshman orientation effects retention. This investigation involves computing the difference \( \pi_1 - \pi_2 \), where \( \pi_1 \) and \( \pi_2 \) represent the true population proportions of students returning for a second year without and with taking an orientation course, respectively. The confidence interval we construct will provide a range in which we expect the actual difference in population proportions to fall. Notably, if our confidence interval does not include zero, it suggests a statistically significant difference between the two populations in their retention rates.
Freshman Orientation Impact on Retention
Evaluating the impact of freshman orientation on student retention is of high interest to educational institutions seeking to improve their support services. The calculated confidence interval around the difference in proportions provides insights into the possible effectiveness of orientation programs. A confidence level of 95% offers a degree of certainty that the interval constructed from our sample contains the true difference in population proportions. If this interval is entirely above or below zero, we may conclude that the orientation program has a statistically significant impact on the likelihood of a freshman returning for their second year. Consequently, a wider or more favorable confidence interval can indicate that such initiatives warrant ongoing implementation or further investigation.

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