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The article 'The Relationship of Task and Ego Orientation to Sportsmanship Attitudes and the Perceived Legitimacy of Injurious Acts" (Research Quarterly for Exercise and Sport \([1991]: 79-87)\) examined the extent of approval of unsporting play and cheating. High school basketball players completed a questionnaire that was used to arrive at an approval score, with higher scores indicating greater approval. A random sample of 56 male players resulted in a mean approval rating for unsportsmanlike play of \(2.76\), whereas the mean for a random sample of 67 female players was \(2.02 .\) Suppose that the two sample standard deviations were \(.44\) for males and \(.41\) for females. Is it reasonable to conclude that the mean approval rating is higher for male players than for female players by more than \(.5\) ? Use \(\alpha=.05\).

Short Answer

Expert verified
The solution involves a series of calculations for the t-score and the degrees of freedom. After comparing the t-score with the critical value, you can conclude whether the mean approval rating is higher for male players than for female players by more than 0.5 or not.

Step by step solution

01

Formulate the Hypotheses

The null hypothesis (H0) is that the mean difference between the male and female approval ratings is equal to 0.5, and the alternate hypothesis (Ha) is that the mean difference is greater than 0.5. Mathematically, these can be stated as: H0: µ1 - µ2 = 0.5 Ha: µ1 - µ2 > 0.5 Where, µ1 and µ2 are the population means of male and female approval ratings respectively.
02

Calculation of t-score

The formula for the t-score in a two-sample t-test is given by: \(t = \frac{\overline{X_1} - \overline{X_2} - D_0}{\sqrt{s_1^2/n_1 + s_2^2/n_2}}\) Where, \(\overline{X_1}\) and \(\overline{X_2}\) are sample means, \(D_0\) (0.5 in this case) is the hypothesized difference, \(s_1\) and \(s_2\) are sample standard deviations and \(n_1\) and \(n_2\) are sample sizes. Using the given values, the t-score can be calculated.
03

Calculation of Degrees of Freedom and Critical Value

The formula for degrees of freedom in a two-sample t-test is: \(df = n_1 + n_2 - 2\) The critical value can be found from the t-distribution table by looking at row \(df\) and column \(\alpha\). We perform a one-tailed test here because we are looking at whether the male approval rating is greater than the female rating by more than 0.5.
04

Decision Making

Compare the calculated t-score with the critical value. If the t-score is greater than the critical value, we reject the null hypothesis and conclude that it is reasonable to say that the mean approval rating is higher for male players than for female players by more than 0.5. If it’s not greater, we fail to reject the null hypothesis and conclude that we don't have enough evidence to claim that the mean approval rating is higher for male players than for female players by more than 0.5 at the 5% significance level.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis Testing
At the core of comparing two sets of data, such as examining attitudes towards sportsmanship among gender lines, lies the method of hypothesis testing. This statistical approach begins with two competing hypotheses: the null hypothesis (\( H_0 \)) and the alternative hypothesis (\( H_a \)). The null hypothesis represents a position of skepticism, suggesting no effect or no difference; in our case, it assumes that the approval rating difference for unsportsmanlike behavior between male and female basketball players is exactly 0.5. Conversely, the alternative hypothesis postulates that there is indeed an effect or a difference; here, it suggests that male players have a mean approval rating for unsportsmanlike play that is greater than that of female players by more than 0.5.

To conduct the hypothesis test, we collect data and compare the observed results against what would be expected if the null hypothesis were true. This comparison is typically made using a test statistic that quantifies the difference between the observed data and the null hypothesis. If this statistic falls into a range that is unlikely under the null hypothesis (as determined by the significance level, \( \alpha \)), we have reason to reject the null hypothesis in favor of the alternative.
T-score Calculation
Diving into the quantitative aspect, the t-score is pivotal in hypothesis testing. It's a standardized value that shows the number of standard deviations a sample mean deviates from the hypothesized population mean difference. To calculate the t-score in a two-sample t-test, we use the formula: \[ t = \frac{\overline{X_1} - \overline{X_2} - D_0}{\sqrt{s_1^2/n_1 + s_2^2/n_2}} \] where \( \overline{X_1} \) and \( \overline{X_2} \) are the sample means for the two groups (males and females, in this context), \( D_0 \) is the hypothesized difference between the population means (0.5 for this exercise), \( s_1 \) and \( s_2 \) are the sample standard deviations, and \( n_1 \) and \( n_2 \) are the sample sizes.

When dealing with the t-score, remember it gauges the difference in terms relative to the data's variability. A higher t-score indicates a greater difference between the groups, which is an essential piece of evidence when testing our hypotheses.
Degrees of Freedom
Degrees of freedom (\( df \) in calculations) serve a crucial role in the realms of statistics, especially when determining the precision of an estimate or the distribution to use for a statistical test. In the context of a two-sample t-test, the degrees of freedom determine which specific t-distribution should be used when interpreting the t-score. They are calculated by the formula: \[ df = n_1 + n_2 - 2 \] which accounts for the total number of observations from both samples (\( n_1 \) and \( n_2 \) respectively) and subtracts 2 to adjust for the estimated means. This adjustment is necessary because each sample mean constrains one degree of freedom. The larger the degrees of freedom, the more the t-distribution resembles the normal distribution.

Understanding degrees of freedom is fundamental. They affect the critical value thresholds, which in turn influence whether we reject or fail to reject the null hypothesis. It's essential to calculate them accurately to arrive at valid conclusions.
Statistical Significance
Statistical significance is the term we use to decide whether the observed effect or difference in our data is unlikely to have occurred just by chance. This concept is a cornerstone of decision-making in hypothesis testing. The significance level (\( \alpha \)), typically set at 0.05, defines the threshold for this decision. If the probability of the observed data, assuming the null hypothesis is true, is less than \( \alpha \), we declare the results statistically significant.

A statistically significant difference is not always a large or meaningful one; it simply means that it is mathematically unlikely to have occurred due to the random variation inherent in the data. In our sportsmanship study, if we find that the calculated t-score exceeds the critical value from the t-distribution associated with our degrees of freedom, we would reject the null hypothesis, thereby concluding with statistical significance that male basketball players have a higher approval rating for unsportsmanlike behavior than their female counterparts by more than 0.5.

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Most popular questions from this chapter

An Associated Press article (San Luis Obispo Telegram-Tribune, September 23,1995 ) examined the changing attitudes of Catholic priests. National surveys of priests aged 26 to 35 were conducted in 1985 and again in 1993\. The priests surveyed were asked whether they agreed with the following statement: Celibacy should be a matter of personal choice for priests. In \(1985,69 \%\) of those surveyed agreed; in \(1993,38 \%\) agreed. Suppose that the samples were randomly selected and that the sample sizes were both 200 . Is there evidence that the proportion of priests who agreed that celibacy should be a matter of personal choice declined from 1985 to 1993 ? Use \(\alpha=.05\).

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